nodes

How to use user-defined class object as a networkx node?

我们两清 提交于 2019-12-01 16:41:12
Class point is defined as (there are also some methods, atributes, and stuff in it, but this is minimal part): class point(): def ___init___(self, x, y): self.x = x self.y = y So, I saw this question , but when I tried applying it, it returns an error: G = nx.Graph() p = point(0,0) G.add_node(0, p) NetworkXError: The attr_dict argument must be a dictionary. If i use G = nx.Graph() p = point(0,0) G.add_node(0, data = p) I don't get an error, but when i try to access the x-coordinate, it turns out it didn't save it as a point. G[0].x returns: AttributeError: 'dict' object has no attribute 'x'

HTMLAgilityPack get innerText of a td tag with an id attribute

社会主义新天地 提交于 2019-12-01 16:27:04
问题 I am trying to select the inner text of a td with an id attribute with the HTMLAgilityPack. Html Code: <td id="header1"> 5 </td> <td id="header2"> 8:39pm </td> <td id="header3"> 8:58pm </td> ... Code: HtmlAgilityPack.HtmlDocument doc = new HtmlAgilityPack.HtmlDocument(); doc.LoadHtml(data); var nodes = doc.DocumentNode.SelectNodes("//td[@id='header1']"); if (nodes != null) { foreach (HtmlAgilityPack.HtmlNode node in nodes) { MessageBox.Show(node.InnerText); } } I keep getting null nodes

SLinkedList and Node in Java

这一生的挚爱 提交于 2019-12-01 13:23:12
To start with, yes, this is for an assignment in class, but my lack of understanding on how it operates is higher than I want it to be. We were given 3 classes, they are the following: SLinkedList.java package chapter3.linkedList; public class SLinkedList<V> { // instance variables. Add the tail reference. protected Node<V> head, tail; protected long size; // methods, empty list constructor first public SLinkedList () { head = null; tail = null; size = 0; } // end constructor of a SLinkedList // method to add nodes to the list. Storage space for the node // is already allocated in the calling

trouble inserting a struct into a set C++

岁酱吖の 提交于 2019-12-01 13:09:09
问题 I am working on an A* pathfinding algorithm, but am having trouble with an error I receive when i insert a struct called node into a set. The error reads: "Error 1 error C2678: binary '<' : no operator found which takes a left-hand operand of type 'const node' (or there is no acceptable conversion)" but the error is found in another file 'XSTDDEF' which i haven't looked at. I am unsure of what it means. struct node{ int f; int g; int h; int x; int y; }; node coords[24] = { -1 }; std::set<node

Sort XML nodes with PHP

你说的曾经没有我的故事 提交于 2019-12-01 12:14:53
问题 I have a serialized string comming in with POST: $imgdata = $_POST['imgdata']; // li[]=2&li[]=3&li[]=1&li[]=4 In this example 001 is reordered after 003 How can I update my XML file with this new order? I think I need simpleXML or xpath. Here are my thoughts: // 1. load xml string $xml = simplexml_load_file('test.xml'); /* <?xml version="1.0" encoding="UTF-8"?> <gallery> <album> <img src="001.jpg" caption="First caption" /> <img src="002.jpg" caption="Second caption" /> <img src="003.jpg"

Django and Node processes for the same domain

与世无争的帅哥 提交于 2019-12-01 11:41:52
Hi I have two process Django and MYSQL node/express and mongo db. 1. How can I configure this two process to point to different url like. Django point to api.abc.com/v1 and node point to api.abc.com/v2 ? 2. all my user login is inside Django and MYSQL with OAuth. I can authenticate user in Django. But how can authenticate user in nodejs app with the token send by Django REST OAuth ? Thanks. Scenario A You create a url in django ^v2/.*$ and then make a request from django view to node.js process. this way django can handle user auth and permissions and node can be standalone and not know

Position/showing of labels with networkx + graphviz

爷,独闯天下 提交于 2019-12-01 10:46:04
I've achieved the following plot with a combination networkx and graphviz: I'm very happy with the result. In the plot you can identify what I call aggregation nodes: those are the latest green ones (where all the green nodes converge) one hop before the orange ones. What I'd like to achieve is the following: 1) Put labels on the sides of the nodes. As you can see, the labels are over them and it's difficult to read; 2) Only show labels on the aggregation nodes and the orange ones. This is how I get to plot the diagram. # We create the graph G = nx.DiGraph() # We add nodes and edges G.add

SLinkedList and Node in Java

巧了我就是萌 提交于 2019-12-01 10:25:38
问题 To start with, yes, this is for an assignment in class, but my lack of understanding on how it operates is higher than I want it to be. We were given 3 classes, they are the following: SLinkedList.java package chapter3.linkedList; public class SLinkedList<V> { // instance variables. Add the tail reference. protected Node<V> head, tail; protected long size; // methods, empty list constructor first public SLinkedList () { head = null; tail = null; size = 0; } // end constructor of a SLinkedList

Vis.js network node customization: cards as nodes

只愿长相守 提交于 2019-12-01 08:18:10
I would like to build a network where the nodes represent information that is structured similarly to cards. With a card I mean a structure composed of two areas: multi-line text area where I can put information that comes from different resources, like a name, a phone number, an address and control area where I can have 2-3 buttons (preferably with icons) that maximize the node, or make the node a root/main one etc. As far as I could see from the vis.js documentation see example here , it is possible to enter paragraph/text as a node label but there is no way to structure a node via Html. Can

Delete node from BST in C

笑着哭i 提交于 2019-12-01 07:40:45
问题 i was trying to understand this function founded online for deleting a node from a BST. There are some things i can't understand This is the code : struct Node* Delete(struct Node *root, int data) { if (root == NULL) { return NULL; } if (data > root->data) { // data is in the left sub tree. root->left = Delete(root->left, data); } else if (data > root->data) { // data is in the right sub tree. root->right = Delete(root->right, data); } else { // case 1: no children if (root->left == NULL &&