nodes

How do I convert repeated xml nodes into a comma delimited string using powershell

由 被刻印的时光 ゝ 提交于 2019-12-02 09:56:10
问题 I have some 13000 log files that are formatted in XML format and I need to convert all of them into a spreadsheet\csv file. As you will see I'm not programmer but I've tried. I have written a powershell script to get the first nodes out and create a comma delimited string but I am stuck with getting the last node which can contain anything from no entries to dozens. example of the xml file: <?xml version="1.0" encoding="utf-8"?> <MigrationUserStatus> <User>username@domain.com</User>

Using visNetwork to dynamically update nodes in R

由 六月ゝ 毕业季﹏ 提交于 2019-12-02 09:44:42
the below snapshot visual is created using the "visNetwork" package. My requirement here is that I have to hard code the edges and also after using visHierarchicalLayout(), I am not able to see them in order, Please help me with a dynamic approach such that no matter how many numbers, I get consecutive numbers in order without hard code. Thanks and please help. library(visNetwork) nodes <- data.frame(id = 1:7, label = 1:7) edges <- data.frame(from = c(1,2,3,4,5,6), to = c(2,3,4,5,6,7)) visNetwork(nodes, edges, width = "100%") %>% visEdges(arrows = "to") %>% visHierarchicalLayout() Using level

How to delete a node in a linked list?

由 一曲冷凌霜 提交于 2019-12-02 08:19:19
问题 This is what I have so far, but it's not working in the test file. Basically skips to the else if(cnode == preposition) void LinkedList::Delete(Node *PrePosition) { Node *cnode = head; Node *pnode = NULL; while (cnode != NULL) { if (cnode->value != NULL) { if (pnode == NULL) { //if there is not previous node head = cnode->next; } else if(cnode == PrePosition){ //if there is previous node cout << endl << "Deleting: " << cnode << endl; pnode->next = cnode->next; } } else { //dont delete pnode =

How to delete a node in a linked list?

由 眉间皱痕 提交于 2019-12-02 06:59:06
This is what I have so far, but it's not working in the test file. Basically skips to the else if(cnode == preposition) void LinkedList::Delete(Node *PrePosition) { Node *cnode = head; Node *pnode = NULL; while (cnode != NULL) { if (cnode->value != NULL) { if (pnode == NULL) { //if there is not previous node head = cnode->next; } else if(cnode == PrePosition){ //if there is previous node cout << endl << "Deleting: " << cnode << endl; pnode->next = cnode->next; } } else { //dont delete pnode = cnode; } cnode = cnode->next; } } 1: Take the pointer from the previous node and point it to the next

Giving unique IDs to all nodes?

由 拟墨画扇 提交于 2019-12-02 05:49:24
I am making a class in Python that relates a lot of nodes and edges together. I also have other operations that can take two separate objects and merge them into a single object of the same type, and so on. However, I need a way to give every node a unique ID for easy lookup. Is there a "proper way" to do this, or do I just have to keep an external ID variable that I increment and pass into my class methods every time I add more nodes to any object? I also considered generating a random string for each node upon creation, but there is still a risk of collision error (even if this probability

Delete node with simplexml

由 我只是一个虾纸丫 提交于 2019-12-02 05:36:56
I have this xhtml : <?xml version="1.0" encoding="UTF-8"?> <html> <head> <meta charset="utf-8"></meta> </head> <body> <nav> <ol> <li> <a href="cover.xhtml">Cover</a> </li> <li> <a href="page002.xhtml">P002</a> </li> <li> <a href="page005.xhtml">P005</a> </li> <li> <a href="page038.xhtml">P038</a> </li> </ol> </nav> </body> </html> I do this in php : copy("nav.xhtml", "nav.xml"); $doc1 = simplexml_load_file("nav.xml"); foreach($doc1->body->nav->ol->li->a as $seg){ $dom=dom_import_simplexml($seg); $dom->parentNode->removeChild($dom); } $doc1->asXml("nav.xhtml"); In result, just the fist is

Reorder XML nodes with php and simplexml

由 时光总嘲笑我的痴心妄想 提交于 2019-12-02 05:31:29
My page is currently updating an existing xml, the problem is that when it adds new nodes they go to the end of the xml or parent tag ie: <N1></N1> <N1></N1> <N2></N2> <N2></N2> <N2></N2> <N1></N1> //I want this node to be displayed with the other N1 nodes. I have read solutions for this that don't use simplexml, but the problem is that I have already written way to much code around simplexml to change now. Also, keep in mind that the page isn't rewriting the xml from scratch, rather it is simply changing what is different. So is what I'm asking possible? thanks. There's no way to re-order

D3.js: Dynamically generate source and target based on identical json values

由 ╄→尐↘猪︶ㄣ 提交于 2019-12-02 04:24:46
Good day, I am a novice in d3/javascript and this may be an easy/repeated question, but I just cannot get this section of my code to work.. I have this json array here: var myArray = [{"id": "red", "value":"1"}, {"id": "orange", "value":"2"}, {"id": "yellow", "value":"3"}, {"id": "green", "value":"1"}, {"id": "blue", "value":"1"}, {"id": "violet", "value":"3"}]; I understand that for me to create links between nodes in D3, I need an array with a [{"source": "___", "target": "___"} structure. Is anyone able to guide me in linking the above array items based on their values (i.e. the node graph

My program replaces all the string data types in all the nodes in the linked list

由 ≯℡__Kan透↙ 提交于 2019-12-02 04:24:21
I have a program that basically adds a history(node) to the employee_record(linked list). Here is my code: #include <stdio.h> #include <stdlib.h> struct history{ char *department1; char *title1; int day; int month; int year; struct history *next; }; struct employee_record{ char firstname[20]; char lastname[20]; long int employee_id; char sex; int age; struct history *head; }; void addjob(struct employee_record *rec, char *department, char *title, int day, int month, int year); void print(struct employee_record *rec); int main(int argc, char *argv[]) { struct employee_record *worker=(struct

Networkx - Problem with drawing nodes with nodelist

由 萝らか妹 提交于 2019-12-02 04:21:55
问题 i have an nested tuple like this: mostfrequent = (('16.37.97.17', '178.237.19.228', '55177', '443', '6', '1', '46'), ('16.37.97.17', '178.237.17.97', '44492', '443', '6', '1', '46'), ('16.37.97.29', '178.237.17.61', '56326', '443', '6', '1', '46'), ('16.37.97.222', '104.131.44.62', '60179', '80', '6', '2', '620'), ('16.37.93.196', '16.37.157.74', '2049', '691', '6', '1', '100')) I want to draw every element of every subtuple with networkx declared via nodelist: nx.draw_networkx_nodes(G, pos,
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