nodes

What is a node in Javascript?

由 痴心易碎 提交于 2019-12-31 08:32:33
问题 I was wondering what exactly a node is in JavaScript? As in the functions: element.nodeType row.parentNode.removeChild(row); 回答1: A "node", in this context, is simply an HTML element. The "DOM" is a tree structure that represents the HTML of the website, and every HTML element is a "node". See Document Object Model (DOM). More specifically, "Node" is an interface that is implemented by multiple other objects, including "document" and "element". All objects implementing the "Node" interface

Delete node with simplexml

由 此生再无相见时 提交于 2019-12-31 04:38:07
问题 I have this xhtml : <?xml version="1.0" encoding="UTF-8"?> <html> <head> <meta charset="utf-8"></meta> </head> <body> <nav> <ol> <li> <a href="cover.xhtml">Cover</a> </li> <li> <a href="page002.xhtml">P002</a> </li> <li> <a href="page005.xhtml">P005</a> </li> <li> <a href="page038.xhtml">P038</a> </li> </ol> </nav> </body> </html> I do this in php : copy("nav.xhtml", "nav.xml"); $doc1 = simplexml_load_file("nav.xml"); foreach($doc1->body->nav->ol->li->a as $seg){ $dom=dom_import_simplexml(

C adding node to head of linked list

由 喜欢而已 提交于 2019-12-31 03:34:06
问题 I have created a linked list struct in c struct node{ int value; struct node* next; }; a method to add a node at the start of the list : void addFirst(struct node *list, int value){ struct node *new_node = (struct node*) malloc (sizeof (struct node)); new_node->value = value; new_node->next = list; list = new_node; } I create a list (malloc and everything), then call this method, it adds the new node inside the method but when i get back to my main my old list remains unchanged. Using DDD

How to use user-defined class object as a networkx node?

由 人走茶凉 提交于 2019-12-30 08:32:36
问题 Class point is defined as (there are also some methods, atributes, and stuff in it, but this is minimal part): class point(): def ___init___(self, x, y): self.x = x self.y = y So, I saw this question, but when I tried applying it, it returns an error: G = nx.Graph() p = point(0,0) G.add_node(0, p) NetworkXError: The attr_dict argument must be a dictionary. If i use G = nx.Graph() p = point(0,0) G.add_node(0, data = p) I don't get an error, but when i try to access the x-coordinate, it turns

Group/merge childs of same nodes in xml/xslt

由 谁说我不能喝 提交于 2019-12-29 00:46:29
问题 I am new to XSLT and changing it manually will take a lot of time. <GroupData ID="xxx" Key="4" Temp="yyy"> <ItemData ID="zzz" Value="3"/> </GroupData> <GroupData ID="xxx" Key="4" Temp="yyy"> <ItemData ID="www" Value="1982"/> </GroupData> I want to have the childs of these multiple GroupData nodes within the same group, i.e., <GroupData ID="xxx" Key="4" Temp="yyy"> <ItemData ID="zzz" Value="3"/> <ItemData ID="www" Value="1982"/> </GroupData> So I need to merge/combine/match them on both

Running a stored procedure with NodeJS and MSSQL package error

由 ￣綄美尐妖づ 提交于 2019-12-28 05:55:30
问题 Im trying to get the MSSQL nodejs package to return the results of a stored procedure from Microsoft SQL server using the code below. However the error I get is... [TypeError: Cannot read property 'type' of undefined] I'm not sure I have done the inputs correctly as I couldn't find an example with more than one input anywhere online. Any ideas? exports.executeSqlStoredProd = function (callback) { var conn = new sqlDb.Connection(settings.dbConfig) conn.connect().then(function () { var req =

C linked list why is my list head variable remaining null (new to C) [closed]

由 廉价感情. 提交于 2019-12-25 18:38:23
问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 6 years ago . i received great help on my other questions in relation to this link list problem. My current problem is now that the head of the list remains null so i cannot actually link any nodes to it or print anything out to the console. The problem is the insert_node function, so when print is called the while loop doesn

C linked list why is my list head variable remaining null (new to C) [closed]

由 生来就可爱ヽ(ⅴ＜●) 提交于 2019-12-25 18:38:15
问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 6 years ago . i received great help on my other questions in relation to this link list problem. My current problem is now that the head of the list remains null so i cannot actually link any nodes to it or print anything out to the console. The problem is the insert_node function, so when print is called the while loop doesn

duplicate the singly linked list

由 五迷三道 提交于 2019-12-25 15:01:46
问题 [3, 5, 4, 2, 1] where I need the delete the nodes close to the tail which is it should be like [1, 2, 3, 5, 4] any suggestions? public void delete() { for(Node<T> current = getHead(); current != null; current = current.getNext()){ System.out.println(temp.getValue()); removeValue(temp.getValue()); } } } } 回答1: You don't need to remove anything at all (I mean not by calling removeValue ). Just store the values you encounter in a set and if the value is already in the set, re-link your list in

Linq to XML in .net 2.0

由 回眸只為那壹抹淺笑 提交于 2019-12-25 13:18:09
问题 IS there a way to use Linq to XML in .net 2.0? I'm not sure about it, if not, how could i recode this var doc = XDocument.Load("config.xml"); var xVideo = doc .Element("XML") .Element("VIDEO"); xVideo.SetElementValue("MAPTEXTURELEVEL", 8); doc.Save("config.xml"); Without using Linq to XML? 回答1: XmlDocument doc = new XmlDocument(); doc.Load("config.xml"); XmlNode node = doc.SelectSingleNode("/XML/VIDEO/MAPTEXTURELEVEL[1]"); node.InnerText = "8"; doc.Save("config.xml"); No, you can't use
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