newline

问题 Consider the following (Python 3.2 under Windows): >>> import io >>> import csv >>> output = io.StringIO() # default parameter newline=None >>> csvdata = [1, 'a', 'Whoa!\nNewlines!'] >>> writer = csv.writer(output, quoting=csv.QUOTE_NONNUMERIC) >>> writer.writerow(csvdata) 25 >>> output.getvalue() '1,"a","Whoa!\nNewlines!"\r\n' Why is there a single \n - shouldn't it have been converted to \r\n since universal newlines mode is enabled? With this enabled, on input , the lines endings \n , \r ,

问题 I want to send new-line-character as part of a value of a post request (text)variable. I am using wget to fire the request. How do I code that ? 回答1: According to the W3C spec, you encode a line break as %0D%0A in the x-www-form-urlencoded format -- which is what you hand to the --post-data option to wget. 来源： https://stackoverflow.com/questions/6262275/newline-character-in-post-request

问题 In a .fs file a newline is denoted by \r\n , but in the F# Interactive window it is \n . In a problem I'm currently trying to solve, the length of a multiple line literal string matters. So a problem arises when I am testing code in the F# Interactive window, because the length of the string is different from in normal execution. I hope there is an option to change the newline 'character' in F# Interactive to \r\n , but I can't find it. Does anyone know where I can achieve this, or some other

问题 This question already has answers here : How to prevent EditText from breaking a line after punctuation (3 answers) Closed 6 years ago . I would like to avoid breaking lines in specifical parts of the String. Let's say we have this String: Speed (m/s) The ideal would be either not jumping at all and having the full String in one line, or, if the jump is needed, in this way: Speed (m/s) What I want to avoid are thing like this: Speed (m/ s) Any ideas? 回答1: Try to use non-breaking space between

问题 Historically, I like to break expressions so that the "it's clearly incomplete" bias is shown on the continued line: var something = foo + bar + baz(mumble); This is an attitude that comes from working in languages which need semicolons to terminate expressions. The first line is already obviously incomplete due to no-semicolon, so it's better to make it clear to the reader that the second line is not complete. The alternative would be: var something = foo + bar + baz(mumble); That's not as

问题 I've seen similar questions here, but still can figure out why it's not working. How to add line break (in other words add new paragraph) in multiline UIlabel? I have a label with a lot of text, lbl.numberOfLines = 0; lbl.sizeToFit; but I'm still getting something like this: "Some text here\nAnd here I want new line" Thank you 回答1: UILabel won't respect \n, You can use option-return (in Interface builder) to force where you want a line break. You can use a UIWebView in place of the label and

问题 Basically I have an HTML fragment with <br> and <p></p> inside. I was able to remove all the HTML tags but doing so leaves the text in a bad format. I want something like nl2br() in PHP except reverse the input and output and also takes into account <p> tags. is there a library for it in Java? 回答1: You basically need to replace each <br> with \n and each <p> with \n\n . So, at the points where you succeed to remove them, you need to insert the \n and \n\n respectively. Here's a kickoff

问题 I have a git repo set with core.eol=crlf , core.autocrlf=true and core.safecrlf=true . When I apply a patch from another crlf repo and to my repo all the line endings for the effected file are changed to lf . Currently I'm applying the patch as so: git apply --ignore-whitespace mychanges.patch (It seems I have to use --ignore-whitespace to get the patch to successfully apply.) My current work around is to run unix2dos on the file. Is there a better way of getting apply to conform to my eol

问题 how can I output text to the console without new line at the end? for example: print 'temp1' print 'temp2' output: temp1 temp2 And I need: temp1temp2 回答1: Add a comma after the last argument: print 'temp1', print 'temp2' Alternatively, Call sys.stdout.write : import sys sys.stdout.write("Some output") 回答2: In Python > 2.6 and Python 3: from __future__ import print_function print('temp1', end='') print('temp2', end='') 回答3: Try this: print 'temp1', print 'temp2' 回答4: There are multiple ways,

问题 I need to print month using the month and day. But I cannot seem to move the numbers after '1' to the next line using Python. # This program shows example of "November" as month and "Sunday" as day. month = input("Enter the month('January', ...,'December'): ") day = input("Enter the start day ('Monday', ..., 'Sunday'): ") n = 1 if month == "January" or month == "March" or month == "May" or month == "July" or month == "August" or month == "October" or month == "December": x = 31 elif month ==