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问题 This seems like a common question, but I can't find this anywhere on Google nor SO. Please point me to the article if you find one. How do I insert a new line in bash prompts (when you just press ENTER), similar to that in Windows prompt? Linux: $ $ $ Windows: C:\> C:\> C:\> I need that extra space in between. 回答1: Change the PS1 Bash prompt variable: PS1="\n$PS1" 来源： https://stackoverflow.com/questions/17198311/insert-new-line-to-bash-prompts

问题 I have an issue with a file that's created from data (in format of bytes) returned from the database. the problem is that there is a few newlines in the file. i would like to know if there is a way to write a where clause to check if some record has a newline character? 回答1: Using the CHR function to look for the ASCII value: select * from your_table where instr(your_text_col, chr(10)) > 0; If you want to search for carriage returns, that would be chr(13). 回答2: You can write something like:

问题 I am trying to make an ordered dataset out of an OCR scan. I have preprocessed the result by making a list which contains all 'units' - separated by newlines. This looks like this: [' 525-11 Prof.Dr.F.J.A.Kreuzer, Nijmegen onderzoek met betrekking tot de fysiologie van ademhaling en bloedsomloop op grote hoogte 17.500\n', ' 527-7 Dr.G.Buyze, Utrecht onderzoek naar het kopermetabolisme bij geesteszicken s 9.400\n', ' 527-8 Prof. Dr. Elisabeth P.Steyn Parv\xc3\xa9, Utrecht onderzoek naar de

问题 I can't figure out how to match a string but not if it has a trailing newline character ( \n ), which seems automatically stripped: import re print(re.match(r'^foobar$', 'foobar')) # <_sre.SRE_Match object; span=(0, 6), match='foobar'> print(re.match(r'^foobar$', 'foobar\n')) # <_sre.SRE_Match object; span=(0, 6), match='foobar'> print(re.match(r'^foobar$', 'foobar\n\n')) # None For me, the second case should also return None . When we set the end of a pattern with $ , like ^foobar$ , it

问题 This is so stupidly simple but I'm just having issues with it. A text file has a header, e.g., # Avizo BINARY-LITTLE-ENDIAN 2.1 define Lattice 496 384 470 Parameters { AlignTransform { slice0000 0 -0 -30 -1, slice0001 0 -0 -30 -1, slice0002 0 -0 -30 -1, And I'm trying to read each of these lines using fscanf. int i; for ( i = 0; i < 10; i++ ) { fscanf(fp, "%s\n", buf); printf("%d) %s\n",i,buf); } resulting in this 0) # 1) Avizo 2) BINARY-LITTLE-ENDIAN 3) 2.1 4) define 5) Lattice 6) 496 7) 384

问题 These are valid characters: a-z A-Z 0-9 - / How do I remove all other characters from my string? 回答1: Dim cleanString As String = Regex.Replace(yourString, "[^A-Za-z0-9\-/]", "") 回答2: Use either regex or Char class functions like IsControl(), IsDigit() etc. Get a list of these functions here: http://msdn.microsoft.com/en-us/library/system.char_members.aspx Here's a sample regex example: (Import this before using RegEx) Imports System.Text.RegularExpressions In your function, write this Regex

问题 I have a Git repository (originally CVS, then SVN, now Git) containing a Rails project that has been deployed on Linux for a while now. Everything seems to run fine. Now that I've converted to git, I see that many of my files in the repository contain CRLF line endings . I'd love for it to all be consistent ( LF ), but not at the expense of loosing the edit history of every file that has CRLF line endings. Can you think of any reason I can't leave the files as they are? I seem to remember

问题 I have a Git repository (originally CVS, then SVN, now Git) containing a Rails project that has been deployed on Linux for a while now. Everything seems to run fine. Now that I've converted to git, I see that many of my files in the repository contain CRLF line endings . I'd love for it to all be consistent ( LF ), but not at the expense of loosing the edit history of every file that has CRLF line endings. Can you think of any reason I can't leave the files as they are? I seem to remember

问题 Given a string string , what is the fastest/most-efficient way to count lines therein? Will accept best answers for any flavour of Rebol. I've been working under the assumption that the parse [some [thru]] combination was the fastest way to traverse a string, but then I don't know that for certain, hence turning to SO: count-lines: func [string [string!] /local count][ parse/all string [ (count: 1) some [thru newline (count: count + 1)] ] count ] Or: count-lines: func [string [string!] /local

问题 The line-break marker on Windows should be CR+LF whereas on Unix, it's just LF . So when I use something like Console.Write("line1\nline2"); , why would it work "properly" and give me two lines? I expect this \n not to work, and only a combo of \r\n would work. 回答1: '\n' is the Line Feed character. Traditionally, it caused the printer to roll the paper up one line. '\r' is the Carriage Return character, which traditionally caused the printer head to move to the far left edge of the paper. On