newline

问题 How do you split a long piece of text into separate lines? Why does this return line1 twice? /^(.*?)$/mg.exec('line1\r\nline2\r\n'); ["line1", "line1"] I turned on the multi-line modifier to make ^ and $ match beginning and end of lines. I also turned on the global modifier to capture all lines. I wish to use a regex split and not String.split because I'll be dealing with both Linux \n and Windows \r\n line endings. 回答1: arrayOfLines = lineString.match(/[^\r\n]+/g); As Tim said, it is both

问题 I am making a code to parse some input data and write it to a file in a special formatting. I am removing a newline from each string token as so: token[strlen(token)-2] ='\0' It is -2 because the last element is \0 . This much works. However, the final element of the input data does NOT have a newline, so using just that ends up removing the second-to-last character from the last input set. original input: 0.38 after running it through the removal: 0.3 The obvious solution is to check if the

问题 considering the following function private static void GetText(String nodeValue) throws IOException { if(!file3.exists()) { file3.createNewFile(); } FileOutputStream fop=new FileOutputStream(file3,true); if(nodeValue!=null) fop.write(nodeValue.getBytes()); fop.flush(); fop.close(); } what to add to make it to write each time in the next line? for example i want each words of a given string in a seperate lline for example: i am mostafa writes as: i am mostafa 回答1: To write text (rather than

问题 I'm trying to append a strings which end in newlines to a textarea using jQuery. However, different newline tokens show different behavior in Firefox3.5 and IE8, and I can't seem to find a way to use something that works for both browsers. \n works in FF but not in IE <br/> and \r\n work in IE but not in FF No luck using <pre></pre> tags either I've seen info on the IE innerHTML issue but I'm not exactly sure how to best approach this problem in jQuery. Thanks for any help! 回答1: Not sure how

问题 My original config file (web1.config) has no extra line and when viewed in notepad (showing all characters) looks as: <?xml version="1.0"?> <configuration> <system.web> <compilation debug="true" targetFramework="4.6" /> <httpRuntime targetFramework="4.6" /> </system.web> <appSettings> <add key="myConnectionString" value="server=localhost;database=myDb;uid=myUser;password=myPass;" /> </appSettings> </configuration> Now, I need to apply the script to change my database name to something else

问题 I have a string that I got from a text file. Text file: Line 1 Line 2 Line 3 ... I want to convert it to an array, one array element per line. [ "Line 1", "Line 2", "Line 3", ... ] Depending on how the file was saved, the string could take one of the following forms: string = "Line 1\nLine 2\nLine 3\n..." where \n is the new line (line feed) character string = "Line 1\r\nLine 2\r\nLine 3\r\n..." where \r is the carriage return character. As I understand it, \n is commonly used in Apple/Linux

问题 I have a string that I got from a text file. Text file: Line 1 Line 2 Line 3 ... I want to convert it to an array, one array element per line. [ "Line 1", "Line 2", "Line 3", ... ] Depending on how the file was saved, the string could take one of the following forms: string = "Line 1\nLine 2\nLine 3\n..." where \n is the new line (line feed) character string = "Line 1\r\nLine 2\r\nLine 3\r\n..." where \r is the carriage return character. As I understand it, \n is commonly used in Apple/Linux

问题 I have a text which might have different newline styles. I want to replace all newlines '\r\n', '\n','\r' with the same newline (in this case \r\n ). What's the fastest way to do this? My current solution looks like this which is way sucky: $sNicetext = str_replace("\r\n",'%%%%somthing%%%%', $sNicetext); $sNicetext = str_replace(array("\r","\n"),array("\r\n","\r\n"), $sNicetext); $sNicetext = str_replace('%%%%somthing%%%%',"\r\n", $sNicetext); Problem is that you can't do this with one

问题 I tried to use the regexp (?<=^(?![ \t]*@).+)(?<![\{\};:)]|//.{0,1024}|^[ \t]+)\R to: Match newlines without matching preceding characters Don't match newlines in only-space lines (empty lines) Don't match newlines in lines started by optional spaces (not newlines) and at-symbol '@'. Don't match newlines in lines containing [unescaped] '//'. Don't match newlines preceded by '{', '}', ';' or ':'. (better if doesn't match newlines preceded by optional spaces and that characters.) That regexp

问题 i have a space before a new line in a string and cant remove it (in java). I have tried the following but nothing works: strToFix = strToFix.trim(); strToFix = strToFix.replace(" \n", ""); strToFix = strToFix.replaceAll("\\s\\n", ""); 回答1: myString.replaceAll("[ \t]+(\r\n?|\n)", "$1"); replaceAll takes a regular expression as an argument. The [ \t] matches one or more spaces or tabs. The (\r\n?|\n) matches a newline and puts the result in $1 . 回答2: try this: strToFix = strToFix.replaceAll(" \