C++ overloaded new[] query : What size does it take as parameter?
问题 I have overloadded operator new[] like this void * human::operator new[] (unsigned long int count){ cout << " calling new for array with size = " << count << endl ; void * temp = malloc(count) ; return temp ; } and now calling human * h = new human[14] ; say sizeof(human) = 16 , but count it prints is 232 which is 14*16 + sizeof( int * ) = 224+8 . Why is this extra space being allocated ? And where does it fall in memory ? Because when I print *h OR h[0] I get same results , so its not in