nested-loops

Turning a recursive function into a for loop?

北城以北 提交于 2019-11-28 12:47:31
Does every recursive function have an equivalent for loop? (Both achieve the same result). I have this recursive function: private static boolean recur(String word, int length) { if(length == 1 || length == 2) return false; if(length == 0) return true; if(words[length].contains(word.substring(0, length))) return recur(word.substring(length), word.length() - length); return recur(word, length-1); } Given that words is a Set[], and where words[i] = a set with words of length i. What am trying to do is: initiate the recursion with a word (say, "stackoverflow", no spaces), I am trying to find if

React JSX: rendering nested arrays of objects

落花浮王杯 提交于 2019-11-28 11:39:56
问题 I have a component with the following render: render() { const { policy } = this.props; let deployment = policy.Deployment; let value = policy.value; let policyLegend = deployment.policyLegend; let policyObj = this.valueToPolicy(policyLegend, value); console.log(policy); console.log(deployment); console.log(value); console.log(policyLegend); console.log(policyObj); return( <div> <Form onSubmit={ (event) => this.handleSubmit(event, this.props) }> { policyLegend.map(function(policy) { <div> <h3

Creating N nested for-loops

…衆ロ難τιáo~ 提交于 2019-11-28 10:02:33
Is there a way to create for-loops of a form for(int i = 0; i < 9; ++i) { for(int j = 0; j < 9; ++i) { //... for(int k = 0; k < 9; ++k) { //N-th loop without knowing N at the compile time. Ideally I'm trying to figure out a way to loop through separate elements of a vector of digits to create each possible number if a certain amount of digits is replaced with different digits. You may use recursion instead with a base condition - void doRecursion(int baseCondition){ if(baseCondition==0) return; //place your code here doRecursion(baseCondition-1); } Now you don't need to provide the

Itertools equivalent of nested loop “for x in xs: for y in ys…”

亡梦爱人 提交于 2019-11-28 08:19:06
问题 I have a nested loop to create all combinations in a set of conjugated verbs. The aim to to get all possible combinations of verb, person and tense, e.g. [['to be', 'first person singular', 'future'],['to be', 'second person singular', 'future'], ...] . for v in verbs: for p in persons: for t in tenses: return [v, p, t] Is there a way of reducing the nesting, perhaps using itertools ? 回答1: for v, p, t in itertools.product(verbs, persons, tenses): ... 回答2: You can use itertools.product for

Mutating an item inside of nested loops

浪尽此生 提交于 2019-11-28 07:48:09
问题 I'm trying to write a program to evenly (or as close to possible) distribute points about the surface of a sphere. I'm trying to achieve this by placing N points randomly about a unit sphere, and then running multiple steps where the points repel each other. The problem is in the loop over the points array. The code below loops over each point, and then the loop inside that, again loops over each point and calculates the repulsive force between each point pair. for point in points.iter_mut()

Big O for 3 nested loops

假如想象 提交于 2019-11-28 07:15:05
问题 Another Big O notation question...What is the Big O for the folling code: for (int i = n; i > 0; i = i / 2){ for (int j = 0; j < n; j++){ for (int k = 0; k < n; k++){ count++; } } } My Thoughts: So breaking it down, I think the outside loop is O(log2(n)) , then each of the inner loops is O(n) which would result in O(n^2 * log2(n)) Question #1 is that correct? Question #2: when combining nested loops is it always just as simple as mulitply the Big O of each loop? 回答1: When loop counters do not

Is using labels in JavaScript bad practice?

青春壹個敷衍的年華 提交于 2019-11-28 04:51:41
I just found out about using label s in JavaScript, such as: for (var i in team) { if(i === "something") { break doThis: //Goto the label } else { doThat(); } } doThis: //Label doIt(); I've not heard about this until now and I can't find much information online about it and I'm beginning to think there is a reason for that. It seems to me like this is similar to a GOTO statement in other languages and would be considered bad practice. Would I be right in assuming this? Those are loop breaker identifiers. They are useful if you have nested loops (loops inside loops) and using these identifiers,

Breaking out of an outer loop from an inner loop in javascript

笑着哭i 提交于 2019-11-28 04:36:30
问题 while(valid){ for(loop through associative array){ if(!valid){ break; } } } I have tried to find a way to break out of the while loop from the if statement. So far, the best method seems to be the goto method that is non-existant in Javascript. What is the best way to cause the if statement to break out of both of the loops it is nested in? Thanks in advance for the help! 回答1: Depending on what your conditionals are, it should be easy to set the iterator of your for-loop to something that

In python is there an easier way to write 6 nested for loops?

给你一囗甜甜゛ 提交于 2019-11-28 04:20:44
This problem has been getting at me for a while now. Is there an easier way to write nested for loops in python? For example if my code went something like this: for y in range(3): for x in range(3): do_something() for y1 in range(3): for x1 in range(3): do_something_else() would there be an easier way to do this? I know that this code works but when you indent instead of using 2 spaces, like me, it can get to be a problem. Oh in the example there were only 4 nested for loops to make things easier. If you're frequently iterating over a Cartesian product like in your example, you might want to

NodeJS, Promises and performance

最后都变了- 提交于 2019-11-28 01:40:22
My question is about performance in my NodeJS app... If my program run 12 iteration of 1.250.000 each = 15.000.000 iterations all together - it takes dedicated servers at Amazon the following time to process: r3.large: 2 vCPU, 6.5 ECU, 15 GB memory --> 123 minutes 4.8xlarge: 36 vCPU, 132 ECU, 60 GB memory --> 102 minutes I have some code similair to the code below... start(); start(){ for(var i=0; i<12; i++){ function2(); // Iterates over a collection - which contains data split up in intervals - by date intervals. This function is actually also recursive - due to the fact - that is run