nested-lists

say I have this list: li = [["0", "20", "ar"], ["20", "40", "asdasd"], ["50", "199", "bar"], ["24", "69", "sarkozy"]] Now, forget about the numbers, they are something that let me recognize the position of string. So basically, given that I have the string "ar" in hand, how can I extract all the lists that contain "ar"? new_li = [["50", "199", "bar"], ["24", "69", "sarkozy"]] How can I obtain this list? >>> [x for x in li if 'ar' in x[2]] [['0', '20', 'ar'], ['50', '199', 'bar'], ['24', '69', 'sarkozy']] 来源： https://stackoverflow.com/questions/6889785/python-how-to-search-an-item-in-a-nested

Here's the code: <ScrollView> { tree.myPoiComments.CommentInfo && tree.myPoiComments.CommentInfo.length>0 && <FlatList data={tree.myPoiComments.CommentInfo} keyExtractor = {(item, index) => item.CommentId} ListHeaderComponent = {() => <View> <Text style={styles.listHeader}>My Comments</Text> </View>} renderItem= {({item}) => <CommentItem comment={item} owner={1} />} /> } { tree.poiComments.CommentInfo && tree.poiComments.CommentInfo.length>0 && <FlatList data={tree.poiComments.CommentInfo} keyExtractor = {(item, index) => item.CommentId} onEndReachedThreshold={1} onEndReached={(info) => {

I'm using a NestedList with a underlying TreeStore. Now I want to add items to the NestedList as leafs. How can I do this? Currently my code (Controller, onAddButtonTapped) looks like this: var store = Ext.getStore('menuStore'); var customerAreaNode = store.getRoot().getChildAt(1); customerAreaNode.appendChild({name: "text", leaf:true}); customerAreaNode.expand(); store.sync(); This code results in two new empty listentries on leaf level (behind the correct node) and one new listentry on node level. Every new entry has no names shown in the NestedList but every item contains "text" in their

I have a list like that [[1]] [1] a1 b1 c1 [[2]] [1] a2 b2 c2 [[3]] [1] a3 b3 c3 I want specific element removed from each part of it: [[1]] [1] a1 c1 [[2]] [1] a2 c2 [[3]] [1] a3 c3 I tried tail but removes "outer" elements. Maybe some indexing would do? Assuming the pattern is just that you want the second element removed, lapply(List, function(x) x[-2]) Using purrr::map it would be even shorter by doing # setup some example data nestedList = list(list(4,5,6),list(1,2,3)) # remove first element from each sublist map(nestedList, tail, -1) 来源： https://stackoverflow.com/questions/34858384/r-how

I know that one can create lists within lists. But how many, exactly can I fit in one. I tried this in the IPython console: In [1]: Alist = [1] In [2]: Alist.append(Alist) In [3]: Alist Out[3]: [1, [...]] In [4]: Alist[1] Out[4]: [1, [...]] In [5]: Alist[1][1] Out[5]: [1, [...]] In [6]: Alist[1][1][1] Out[6]: [1, [...]] Now I could go on forever trying to access Alist[1][1][1][1]...[1] , But how is this possible? Also, how come my machine hasn't run out of memory with this? I use Python2.7 on Ubuntu 16.04 if it helps. There is only one object of finite size here: You first create a list object