neo4j

How can I use py2neo to store a dictionary as one property value to single property key of a node in neo4j?

↘锁芯ラ 提交于 2020-06-03 01:50:48
问题 I have a node and I want to add one property property_x whose value I want to be {"year1":value, "year2":value} . Making more than one node for each year is not needed as I need these values in my processing together. 回答1: Neo4j only supports certain kinds of properties (docs): ...there are restrictions as to what types of values can be used as property values. Allowed value types are as follows: Numbers: Both integer values, with capacity as Java’s Long type, and floating points, with

How can I use py2neo to store a dictionary as one property value to single property key of a node in neo4j?

▼魔方 西西 提交于 2020-06-03 01:48:30
问题 I have a node and I want to add one property property_x whose value I want to be {"year1":value, "year2":value} . Making more than one node for each year is not needed as I need these values in my processing together. 回答1: Neo4j only supports certain kinds of properties (docs): ...there are restrictions as to what types of values can be used as property values. Allowed value types are as follows: Numbers: Both integer values, with capacity as Java’s Long type, and floating points, with

Neo4j cypher query language - order of operations for boolean expressions

大兔子大兔子 提交于 2020-05-30 08:00:26
问题 I am trying to write a query to pull data from my Neo4J database. Lets say there are five conditions that determine whether or not I want to pull _____ from my database: A, B, C, D, and E. The boolean expression which determines this is: A && B && (C || D || E) From scouring the web, I cannot find any information about an order of operations that Neo4J AND and OR queries abide by (AND usually precedes OR), but from my observations they seem like they execute sequentially. Since there is no

How can I limit to only one relationship between two nodes in Neo4j?

♀尐吖头ヾ 提交于 2020-05-24 00:35:46
问题 I have the following graph: Currently I am using this QUERY to add a relationship between two nodes: MATCH (a:Service),(b:Service) WHERE a.service_id = 'cs2322' and b.service_id = 'ab3232' CREATE (a)-[r:DEPENDENT_ON]->(b) RETURN type(r) However I dont want to have more than one relationship between any two nodes, because I want to visualise my services and the dependency between them, so I cannot have a service being two times dependent on the other. Is there any way I can limit this to force

Neo4j match nodes related to all nodes in collection

那年仲夏 提交于 2020-05-14 01:29:47
问题 I have a graph of tags, which are related with each other. My goal is to create a Cypher query, which will return all tags that are related to an array of input tags via 1 or 2 hops. I made a query, which doesn't work quite as intended. MATCH (t:Tag) WHERE t.name IN ["A", "B", "C"] WITH t MATCH (a:Tag)-[:RELATED*1..2]-(t) RETURN DISTINCT a; This query first finds the nodes A , B , C and then searches for tags, that are related to A , B or C via 1 node or less. What I want to do though is to

Neo4j match nodes related to all nodes in collection

我们两清 提交于 2020-05-14 01:28:47
问题 I have a graph of tags, which are related with each other. My goal is to create a Cypher query, which will return all tags that are related to an array of input tags via 1 or 2 hops. I made a query, which doesn't work quite as intended. MATCH (t:Tag) WHERE t.name IN ["A", "B", "C"] WITH t MATCH (a:Tag)-[:RELATED*1..2]-(t) RETURN DISTINCT a; This query first finds the nodes A , B , C and then searches for tags, that are related to A , B or C via 1 node or less. What I want to do though is to

Neo4j match nodes related to all nodes in collection

放肆的年华 提交于 2020-05-14 01:28:33
问题 I have a graph of tags, which are related with each other. My goal is to create a Cypher query, which will return all tags that are related to an array of input tags via 1 or 2 hops. I made a query, which doesn't work quite as intended. MATCH (t:Tag) WHERE t.name IN ["A", "B", "C"] WITH t MATCH (a:Tag)-[:RELATED*1..2]-(t) RETURN DISTINCT a; This query first finds the nodes A , B , C and then searches for tags, that are related to A , B or C via 1 node or less. What I want to do though is to

Neo4j match nodes related to all nodes in collection

一曲冷凌霜 提交于 2020-05-14 01:28:05
问题 I have a graph of tags, which are related with each other. My goal is to create a Cypher query, which will return all tags that are related to an array of input tags via 1 or 2 hops. I made a query, which doesn't work quite as intended. MATCH (t:Tag) WHERE t.name IN ["A", "B", "C"] WITH t MATCH (a:Tag)-[:RELATED*1..2]-(t) RETURN DISTINCT a; This query first finds the nodes A , B , C and then searches for tags, that are related to A , B or C via 1 node or less. What I want to do though is to

Neo4j - Counting Nodes with Labels

℡╲_俬逩灬. 提交于 2020-05-11 05:20:08
问题 I'd like a query that counts how many nodes have each label in the dataset. For instance: LabelA 100 LabelB 200 I can do this for each individual label with something like MATCH (n:LabelA) return count(n); But, I'd like to do it for every label in one command. 回答1: Try something like this MATCH (n) RETURN DISTINCT count(labels(n)), labels(n); This will return the sum of the labels in the first column and the label name in the second. 回答2: A quick alternative here, for single labels only, APOC

Neo4j - Counting Nodes with Labels

空扰寡人 提交于 2020-05-11 05:18:07
问题 I'd like a query that counts how many nodes have each label in the dataset. For instance: LabelA 100 LabelB 200 I can do this for each individual label with something like MATCH (n:LabelA) return count(n); But, I'd like to do it for every label in one command. 回答1: Try something like this MATCH (n) RETURN DISTINCT count(labels(n)), labels(n); This will return the sum of the labels in the first column and the label name in the second. 回答2: A quick alternative here, for single labels only, APOC