mysqli

问题 I have searched the net and so far what I have seen is that you can use mysql_ and mysqli_ together meaning: <?php $con=mysqli_connect("localhost", "root" ,"" ,"mysql"); if( mysqli_connect_errno( $con ) ) { echo "failed to connect"; }else{ echo "connected"; } mysql_close($con); echo "Done"; ?> or <?php $con=mysql_connect("localhost", "root" ,"" ,"mysql"); if( mysqli_connect_errno( $con ) ) { echo "failed to connect"; }else{ echo "connected"; } mysqli_close($con); echo "Done"; ?> Are valid but

问题 Problem: I need to transfer all the files from the table invoicesub to another table called displaybilling in invoicesubmitfinal page and then delete all the contents inside invoicesub. Then, i need to parse in the total_amt variable and paid variable as well as the customer name variable(cname) to a 4th page. How do i go about doing these 2 things? Create Invoice: This is a form that takes allows the admin to add in more rows of description, quantity, amount, discount. All values keyed in as

问题 I've recently started working with mysqli. Previously with php and MySQL I would write a common class holding the MySQL database connection as I don't want to repeat that code over and over. Now with mysqli I can't seem to do this. Is there a simple way to do this I think I'm missing something really obvious. 回答1: Have you considered using PDO? Example: session_start(); $db_user = 'example'; $db_pass = 'xxxxx'; $user_id = 1; try { $db=new PDO( "mysql:host={$db_host}dbname={$db_name}", $db

问题 This question already has answers here : How can I enable the MySQLi extension in PHP 7? (6 answers) Closed 2 years ago . i get an error when trying to connect to my database with mysqli on php 7.0 and php 7.1 PHP Fatal error: Uncaught Error: Call to undefined function mysqli_connect() in /home/mywebsite/public_html/connection.php:7 $conn = mysqli_connect($DBhost,$DBuser,$DBpass,$DBname); 回答1: First check, if mysqli is enabled: phpinfo() The mysqli PHP extension is not installed on your

问题 I'm using the Tutorial to create a search engine. However I want the user to be allowed to keep typing in the search but make the search ignore anything after a certain amount of text has been entered. I see right here include_once ('database_connection.php');//Including our DB Connection file if(isset($_GET['keyword'])){//IF the url contains the parameter "keyword" $keyword = trim($_GET['keyword']) ;//Remove any extra space $keyword = mysqli_real_escape_string($dbc, $keyword);//Some

问题 I am trying to create a private messaging system in which user sends message to another user and that content is inserted into database..Iam using a random number called hash to identify a conversation between two people..table for that is "message_group" and table for saving messages is "messages"..here comes the problem..when I type something in text area it is supposed to enter into database table messages but it doesnot..This code is supposed to display the messages and also reply to a

问题 This question is unlikely to help any future visitors; it is only relevant to a small geographic area, a specific moment in time, or an extraordinarily narrow situation that is not generally applicable to the worldwide audience of the internet. For help making this question more broadly applicable, visit the help center. Closed 7 years ago . I have a mysql query that looks like this $query="SELECT * FROM #__content" . I have no idea what the #__ before content is supposed to mean ? If I have

问题 Does anyone know of a good resource on how to create the hyperlink numbers at the bottom of a results page as search engines do to load the next number of results? The page would load the first 10 results. And then if you click on the number, it loads corresponding results in that 10 number range. Example: 0-10 -> show no numbers 11-20 -> show 1, 2 21-30 -> 1, 2, 3 up to 50 anything more than 50 does 1,2,3,4,5.....67 [last number]. My thoughts so far (I'm doing this in PHP/mysqli but the

问题 I have the parameters to send to a prepared statement in an array, I am using call_user_func_array and using it as such call_user_func_array(array($stmt, "bind_param"), array_merge(array($types), $params_fixed)) , where $types contains the types and $params_fixed contains the parameters. I ran it and got the error Warning: Parameter 2 to mysqli_stmt::bind_param() expected to be a reference, value given in ... , I searched for this error and an answer was to send the parameters by reference so

问题 first of all im a noob when it comes to coding but il try to explain im trying to send email with all the products from Cart table to a customer, but all I can send is the last row of the cart table, when im echoing the var's it prints to me all the products I need. $message =""; $message2 =""; $trxformail = "select * from orders where trx_id = '$trx_id'"; $run_trx = mysqli_query($con, $trxformail); while($post_trx = mysqli_fetch_array($run_trx)){ $pro_id = $post_trx['p_id']; $pro_price =