mysqli

问题 Why does this function return an infinite loop? I am trying to create a function where you just have to give it the query and the while loop takes care of the rest. but for some reason ONLY when i have the function return $q->fetch_assoc() it goes into an infinite loop. if I return just $q, then call $q->fetch_assoc() in the while loop then it doesn't cause the infinite loop. public function fetch($query){ $con = $this->con; $q = $con->query($query); return $q->fetch_assoc(); } while($r =

问题 I am new in PHP and MYSQL database. I am trying to display row in table from my two table. I want all row from table called teacher_profile and want name column from center. I am able to run query in phpmyadmin and its working fine but issue is both table have name is common so I am not able to properly display centername in my table. because there teacher_profile and center both have name column. I can not rename it because its live and used with my android application. select * from teacher

问题 which one is the correct code in a prepared statement? $ID_user=$mysqli->insert_id; or $ID_user=$stmt->insert_id; ? $stmt = $mysqli->prepare("INSERT INTO users (first_name, last_name) VALUES (? ,?)"); $stmt->bind_param("ss",$first_name,$last_name); if($stmt->execute()) { $ID_user=$mysqli->insert_id; // or $ID_user=$stmt->insert_id; } 回答1: There is absolutely no difference, you can use whatever you wish. 来源： https://stackoverflow.com/questions/43184732/mysqli-insert-id-mysqli-insert-id-or-id

问题 which one is the correct code in a prepared statement? $ID_user=$mysqli->insert_id; or $ID_user=$stmt->insert_id; ? $stmt = $mysqli->prepare("INSERT INTO users (first_name, last_name) VALUES (? ,?)"); $stmt->bind_param("ss",$first_name,$last_name); if($stmt->execute()) { $ID_user=$mysqli->insert_id; // or $ID_user=$stmt->insert_id; } 回答1: There is absolutely no difference, you can use whatever you wish. 来源： https://stackoverflow.com/questions/43184732/mysqli-insert-id-mysqli-insert-id-or-id

问题 I have few question. Spec: MySql database; server side language PHP 5.3.10 1) When should one use prepared statements? I am building a webapp which has users. I am retrieving/inserting data into the database constantly. I am currently not using prepared statements and I was wondering if that was wrong way of doing things? /** * Register a new user into the database. Please make sure to * hash the password. * @param type $fName First name of the user - String value. * @param type $lName Last

问题 Let's say I have 3 DB tables: teachers, with the following fields: id name subjects, with the following fields: id name teachers-subjects, with the following fields: teacher_id subject_id So, a relationship comes some teachers have subjects in common. I've thought about the algorithm for querying: For each record s in subjects table: Select the count in teachers_subjects table. If count is greater than 1 In teacher_subjects, get teacher_id's where subject_id is s. Make the relationship pairs.

问题 For some reason it executes the statement and then the bind_results returns all values but not the last value of $postContent. <?php if (isset($_GET['postID'])) { $postID = $_GET['postID']; $stmt = $mysqli->prepare("SELECT * FROM Posts WHERE postID = ?"); $stmt->bind_param('i', $postID); $stmt->execute(); $stmt->bind_result($postID, $postTitle, $postCat, $postUser, $postDateTime, $postContent); $stmt->fetch(); echo $postContent; ?> <h1><?php echo $postTitle;?></h1> </div> <!-- End of box div

问题 I have a simple login system protection mechanism by recording the user's IP, failed attempt number and last attempt time to a MySQL database table named bannedusers . However when I attempt to use the following code below to insert a new entry into the database the execute() function returns false and fails to execute. Code as follows: private $con; function updateTable($IP, $attempt, $exists){ $time = time(); //The following statement is actually in the constructor, moved here for

问题 I need to create a GUI, using which users can select several attributes which will be used to query the database to find suitable persons. I'm looking for ideas how to dynamically generate the database query according to user's choices. Query will contain several fields, but to get the idea I will include only three of those below as an example: Occupation - there can be 0 to n occupation strings. If occupation strings are given, one of them have to match. Age - age can be given as: exact

问题 I am doing PHP coding for first time. I got the following errors: Errors : Warning: mysqli_real_escape_string() expects parameter 1 to be mysqli, boolean given in C:\xampp\htdocs\331002.php on line 9 Warning: mysqli_real_escape_string() expects parameter 1 to be mysqli, boolean given in C:\xampp\htdocs\331002.php on line 10 Warning: mysqli_real_escape_string() expects parameter 1 to be mysqli, boolean given in C:\xampp\htdocs\331002.php on line 11 Notice: Undefined index: empID in C:\xampp