mysqli

问题 I want to make a loop with one INSERT query for each fetched row from a previous query with prepared statements. In a more visual way: MAKE QUERY While Fetching - Make new query I can't close my statement since I need it to keep working... The problem is that when we use prepared statements, we have to fetch all data before doing a new prepare(). So, how could I do this? Maybe without statements, but it's not a nice solution. 回答1: You are going to kill your DB (and if you have a DBA your DBA

问题 This question already has answers here : Reference - What does this error mean in PHP? (35 answers) mysqli_fetch_assoc() expects parameter / Call to a member function bind_param() errors. How to get the actual mysql error and fix it? (1 answer) Closed last year . I want to ask why am I getting this error: Trying to get property 'num_rows' of non-object with the following code: $sql = "SELECT * FROM $table_name ORDER BY Author"; $result = $mysqli->query($sql); if ($result->num_rows > 0) {... I

问题 I have stuck in getting all children's query where parent id greater than the customer id table test id name parent 1 test1 0 2 test2 1 3 test3 1 4 test4 2 5 test5 2 6 test6 10 7 test7 10 8 test8 6 9 test9 6 10 test10 5 11 test10 7 Currently I am using this recursive query but it shows children till the 10 parent but not able to give children of 6 and 7 and further SELECT id , parent FROM (SELECT id , parent from (SELECT * FROM test order by parent , id) testdata_sorted, (SELECT @pv := '1')

问题 For some reason I cannot get this to work for the life of me, I am new to prepared statements! $q = $dbc -> prepare ("SELECT * FROM accounts WHERE email = ? && logcount = ''"); $q -> bind_param ('s', ($_SERVER['QUERY_STRING'])); $row = $q -> fetch_array(MYSQLI_ASSOC); $q -> execute(); $q -> store_result(); if ($q -> num_rows == 1) { $q = $dbc -> prepare("UPDATE accounts SET logcount = '0' WHERE email = ?"); $q -> bind_param('s', ($_SERVER['QUERY_STRING'])); $q -> execute(); echo '

问题 I am trying to make a login system with php but i cant figure out why my form is just redirecting me to the script file when i click on my login button. it works fine on my sign up form. everything seems to work exept its redirecting me to the script file. My php file that contains my form: https://codepen.io/hubbe-andersson/pen/yGOPoM EDIT: I have put my phpscript into my header.php instead and now im getting ERR_TOO_MANY_REDIRECTS in chrome what is caussing this? <?php if(isset($_POST[

问题 I have this partial code: if ($getRecords = $con->prepare("SELECT * FROM AUCTIONS WHERE ARTICLE_NO = ?")) { $getHtml = $con->prepare("SELECT ARTICLE_DESC FROM AUCTIONS WHERE ARTICLE_NO = ?"); $getHtml->bind_param("i", $pk); $getHtml->execute(); $getHtml->bind_result($ARTICLE_DESC); $getRecords->bind_param("i", $pk); $getRecords->execute(); $getRecords->bind_result($ARTICLE_NO, $ARTICLE_NAME, $SUBTITLE, $CURRENT_BID, $START_PRICE, $BID_COUNT, $QUANT_TOTAL, $QUANT_SOLD, $ACCESSSTARTS,

问题 i am new in code igniter, i tried to connect with local db then successfully connected,but while connecting with external db it resulting an error A PHP Error was encountered Severity: Warning Message: mysqli::real_connect(): (HY000/2003): Can't connect to MySQL server on 'xxxxx.gridserver.com' (110) Filename: mysqli/mysqli_driver.php Line Number: 202 Backtrace: File: /var/www/html/restapi/application/libraries/REST_Controller.php Line: 375 Function: __construct File: /var/www/html/restapi

问题 My code to generate the SQL statement works fine - however I run into a hiccup when generating the string for $stmt->bind_param. Code is as follows: $stmt = $mysqli->stmt_init(); if ($stmt->prepare ($sql)) { $bind_types = '"'; $bind_values = ''; if ($action == 'insert' || $action == 'update') { reset ($array); foreach ($array as $key => $value) { if (is_string ($value)) { $type = 's'; } else if (is_int ($value)) { $type = 'i'; } else if (is_float ($value)) { $type = 'd'; } else { die ('Cannot

问题 I want to perform a query whereby I want to check whether on the columns A has either certain values. A could have only X , X and Y or a combination of X Y and Z. To give a better understanding. I am checking a book's author within a table itself. The table has the BOOK_ID , BOOK_TITLE , AUTHOR_NAME, AUTHOR_ORDER. So a book might have 1,2 or 3 authors, listed in order written inside the AUTHOR_ORDER row. I am trying very hard to reach an output where if a book has 3 authors, it will display

问题 im trying to insert data from a form (via POST) into a MySQL database, it does not show any errors, but it does not show up when I check it in phpMyAdmin. <?php $amount = $_POST["amount"]; $unit = $_POST["unit"]; $date = date('Y-m-d H:i:s'); $host = "localhost"; $user = "root"; $pass = ""; $db = "finance"; $table = "silver"; $mysqli = new mysqli($host, $user, $pass, 'finance'); if(!$mysqli) { echo "<div class=\"error\">"; echo "No connection can be established"; echo "</div>"; die(); } if (