mysqli

OpenCart: Fatal Error: Class 'Mysqli' Line 7

只谈情不闲聊 提交于 2020-01-11 13:07:07
问题 I have problem for installation OpenCart in cPanel with Softacolous, when I'm finished for install and during open the site I have message: Fatal error: Class 'mysqli' not found in /home/radiance/public_html/shoukhin/system/library/db/mysqli.php on line 7 ==Info:== OpenCart: Version: 2.0.3.1, 1.5.6.4 Release Date: 29-05-2015 Anything more to solve or get ans? Anyone there to solve it? 回答1: Please install mysqli into your centos server . To install mysqli using EachApache: Login to WHM as

OpenCart: Fatal Error: Class 'Mysqli' Line 7

☆樱花仙子☆ 提交于 2020-01-11 13:06:20
问题 I have problem for installation OpenCart in cPanel with Softacolous, when I'm finished for install and during open the site I have message: Fatal error: Class 'mysqli' not found in /home/radiance/public_html/shoukhin/system/library/db/mysqli.php on line 7 ==Info:== OpenCart: Version: 2.0.3.1, 1.5.6.4 Release Date: 29-05-2015 Anything more to solve or get ans? Anyone there to solve it? 回答1: Please install mysqli into your centos server . To install mysqli using EachApache: Login to WHM as

Insert multiple rows into a MySQL database from a table

柔情痞子 提交于 2020-01-11 11:36:19
问题 I retrieve data from databased based on 4 dropdown criteria.Display them on a table and add one column for scores of each student. I want to populate another table with all the record displayed alongside the scores in each row.I have tried all I know, look at scenerios from Stackoverflow but seems not to work. I need help pls. <form id="form1" name="form1" method="POST"> <fieldset id="Result"> <legend>Result Capture</legend> <table width="1110" border="0"> <tr> <td width="236">Session:<span

Insert multiple rows into a MySQL database from a table

天涯浪子 提交于 2020-01-11 11:35:35
问题 I retrieve data from databased based on 4 dropdown criteria.Display them on a table and add one column for scores of each student. I want to populate another table with all the record displayed alongside the scores in each row.I have tried all I know, look at scenerios from Stackoverflow but seems not to work. I need help pls. <form id="form1" name="form1" method="POST"> <fieldset id="Result"> <legend>Result Capture</legend> <table width="1110" border="0"> <tr> <td width="236">Session:<span

Mysqli prepared statement fetch_assoc

牧云@^-^@ 提交于 2020-01-11 11:25:07
问题 I've tried over and over to figure out why this code isn't working, I have several rows in this table but when I try to execute this it is not returning the rows, everything else is working including the first prepared statement, I have tried using this code in other places and it works just fine, I can also bind the result to a variable and echo the info from the variable so it is there, I have no idea why it won't echo the rows, any advice appreciated! <?php include_once 'includes/functions

Does mysqli have support for caching_sha2_password in PHP 7.4?

早过忘川 提交于 2020-01-11 08:38:31
问题 When I tried upgrading from PHP 7.3 to PHP 7.4, I received this error: Unexpected server response while doing caching_sha2 auth 109 As I see it, this indicates that PHP 7.4 MySQLi is trying to use the caching_sha2_password plugin. This article points out that PHP MySQLi does not support the plugin (it also hints future support for it), but since PHP 7.4 is new and seems to be trying to use it, I guess it should work. Also the error message is different, than if it wasn't supported ( access

PHP prepared statements - check if a value already exists

左心房为你撑大大i 提交于 2020-01-11 07:29:32
问题 I am trying to do a check on a value (email), to determine if it already exist in the db. This should be done using prepared statements. What is the best way for doing this? My solution is this (which is wrong): $mysqli = connectToDB(); $getEmail = $mysqli->prepare('SELECT * FROM users WHERE email=?') or die('Couldn\'t check the email'); $getEmail->bind_param('s', $email); $getEmail->execute(); $countRows = $getEmail->num_rows; print $countRows; It always prints out 0 even though the email

It is not inserting data into database

前提是你 提交于 2020-01-11 05:13:27
问题 I want to insert data into Image_Question Table. but it does not perform an insert in the Image_Question Table. I am getting two errors: Notice: Undefined offset: 0 in ... on line 305 Notice: Undefined offset: 3 in ... on line 305 Here is the application you can use: Application To use app to see what is happening do the following: Click Add Question button twice to append two file inputs Now upload a file one at a time but do it like this. Upload a file in file input in row 1, then upload a

Warning: mysqli_connect(): Unknown MySQL server host

扶醉桌前 提交于 2020-01-11 01:41:10
问题 I have some trouble connecting to a mysql server. I can connect using the linux terminal, so I know that my host, port, user, and password works. I cannot, however, connect using PHP. PHP Version: 5.2.17 Server version: 5.5.27-log MySQL Community Server (GPL) Here is a test code example: <?php $link = mysqli_connect('host.com:5306', 'user', 'pass', 'db'); /* check connection */ if (mysqli_connect_errno()) { printf("Connect failed: %s\n", mysqli_connect_error()); exit(); } if (!mysqli_query(

mysqli_query() always return true

不羁的心 提交于 2020-01-10 20:02:26
问题 This is my form: <!DOCTYPE html> <html> <head> </head> <body> <form action="register_ajax.php" method="get"> <input type="text" name="email"> <input type="submit" value="test"> </form> </body> </html> This is my php code: <?php $dbc = mysqli_connect("localhost","root","*******","continental_tourism") OR die(mysqli_connect_error()); $email = $_GET['email']; $query = "SELECT email FROM customer_info WHERE email = '$email' "; $r = mysqli_query($dbc, $query) OR die(mysqli_error($dbc)); if($r)