mysqli

问题 Before someone say this is a duplicate. Yes i have found this: Move data from one MySQL table to another But in Laravel its a bit different this is quiet that what i want. Like him i want a button wich delete a row in a tabel like this one: (Updated picture) Just to have an example. After he hit the button it should move the shown row into the database just like it is shown here and delete it afterwards. I really dont know how to start something like this in laravel and i really cant find

问题 How can i create a search page with multiple criteria where at least a criteria should be checked. Table Structure ID [pk] Name Sex Location I want to create a search form where user will be able to search by name or by name,sex or by name,sex,location or any such combination among [name,sex,location] How to design the query ? Edit i am not asking for checking atleast a single option has value [js validation], i am asking for the query ! I'll use mysqli prepared statement ! 回答1: You can check

问题 I've been messing around with the MySQLi object in PHP , and was getting used to preparing statements before executing them. Thus far I've mostly been doing the following : if($stmt = $mysqli->prepare($sql) == false){ return $mysqli->error; } Which, when it failed, has always told me that my SQL was wrong basically. Assume the following : A check has been done to ensure MySQL connectivity The SQL is correct, even if it returns 0 rows. All relevant tables exist. Under what circumstances could

问题 I've been messing around with the MySQLi object in PHP , and was getting used to preparing statements before executing them. Thus far I've mostly been doing the following : if($stmt = $mysqli->prepare($sql) == false){ return $mysqli->error; } Which, when it failed, has always told me that my SQL was wrong basically. Assume the following : A check has been done to ensure MySQL connectivity The SQL is correct, even if it returns 0 rows. All relevant tables exist. Under what circumstances could

问题 I have a page that displays a list of projects. With each project is displayed the following data retrieved from a mysqli database: Title Subtitle Description Part number (1 of x) The total number of photos associated with that project A randomly selected photo from the project A list of tags Projects are displayed 6 per page using a pagination system As this is based on an old project of mine, it was originally done with sloppy code (I was just learning and did not know any better) using

问题 according to this example for prepared statements I first bind parameters and then set values for the parameters. Let's assume I have a 2-dim array $alias $array1 = [ 'id' => 1, 'tstamp' => 123456789, 'alias' => '$alias', ]; $array2 = [ 'id' => 1, 'tstamp' => 123456789, 'alias' => '$alias2', ]; $alias = [$array1, $array2]; Why is this code working $insert = 'INSERT INTO abcdef VALUES (?,?,?)'; $insertStmt = $conn->prepare($insert); foreach ($alias as $array) { $insertStmt->bind_param('iis',

问题 I have a form with some optional fields. In the database those fields are set to accept NULL. The code below will throw an error if some field is empty. Could you please assist on what is the best way to avoid this? The only solution I was thinking of is to set the vars to ' ' if is empty(). $query = "INSERT INTO gifts (dateRequest, firstName, lastName, note, lastUpdated) VALUES (?, ?, ?, ?, NOW())"; if ($stmt = $dbc->prepare($query)) { $dateRequest = $_POST['dateRequest']; $firstName = $

问题 I want to display all the questions from the drop down menu when the user selects All from the question drop down menu and output it underneath. Problem is that it is not doing this and to make it worse, it is giving me undefined offset errors stating: Notice: Undefined offset: ... in .... on line 605 Line 605 is: echo '<p><strong>Question:</strong> ' .htmlspecialchars($arrQuestionNo[$key]). ': ' .htmlspecialchars($arrQuestionContent[$key]). '</p>' . PHP_EOL; My question is how to fix the

问题 I want to display all the questions from the drop down menu when the user selects All from the question drop down menu and output it underneath. Problem is that it is not doing this and to make it worse, it is giving me undefined offset errors stating: Notice: Undefined offset: ... in .... on line 605 Line 605 is: echo '<p><strong>Question:</strong> ' .htmlspecialchars($arrQuestionNo[$key]). ': ' .htmlspecialchars($arrQuestionContent[$key]). '</p>' . PHP_EOL; My question is how to fix the

问题 I want to display all the questions from the drop down menu when the user selects All from the question drop down menu and output it underneath. Problem is that it is not doing this and to make it worse, it is giving me undefined offset errors stating: Notice: Undefined offset: ... in .... on line 605 Line 605 is: echo '<p><strong>Question:</strong> ' .htmlspecialchars($arrQuestionNo[$key]). ': ' .htmlspecialchars($arrQuestionContent[$key]). '</p>' . PHP_EOL; My question is how to fix the