mysqli | 易学教程

PHP MySQLi fetch “array push” overrides data

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问题 I have 2 arrays: $arr = []; $tempArray = [ 'val1' => "xxx", 'val2' => 0, 'val3' => 0 ]; Then in my mysql query i fill the temp array with values from the current row and finally push him into the $arr: $stmt->bind_result($tempArray["val1"], $tempArray["val2"], $tempArray["val3"]); while ( $stmt->fetch () ) { array_push($arr, $tempArray); } The Problem is, on every loop the "array_push" overrides the data in the $arr . For example I loop 3 times in the $stmt->fetch() . 1. Loop $tempArray = [

Warning: mysqli_fetch_assoc() expects parameter 1 to be mysqli_result, string given in

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问题 Trying to get the last row in the table but throwing error ... 'Warning: mysqli_fetch_assoc() expects parameter 1 to be mysqli_result, string given in ' $recents = "SELECT * FROM list ORDER BY id DESC LIMIT 1"; if ($result = mysqli_fetch_assoc($recents)) { $mName = $result['name']; $mDesc = $result['description']; $mCost = $result['cost']; } 回答1: You need to pass a result from a query, not the query string. $sql = "SELECT * FROM list ORDER BY id DESC LIMIT 1"; $recent = mysqli_query(

get_result()->fetch_assoc() always returning 1 row

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问题 I have this php code : public function getcabang(){ $cabang = $this->conn->prepare("SELECT nama_cabang,alamat FROM cabang"); if ($cabang->execute()){ $cbg = $cabang->get_result()->fetch_assoc(); $cabang->close(); return $cbg; } else { return NULL; } } but it always returning 1 row : {"error":false,"cabang":{"nama_cabang":"Senayan","alamat":"Pintu 1 Senayan"}} even though it have more than 1 row in table 回答1: You need to iterate to get every row, here is an example from php.net : $query =

two mysqli querys, one in a while loop

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问题 Can't seam to find the answer to this. I have a mysqli loop statement. And in that loop I want to run another query. I cant write these two sql together. Is that possible? I thought since I use stmt and set that to prepare statement. So i add another variable stmt2. Running them seperate works, but run it like I wrote it gives me "mysqli Fatal error: Call to a member function bind_param() on a non-object" Pseudocode : loop_sql_Statement { loop_another_sql_statement(variable_from_firsT_select)

PHP MYSQLi Displaying all tables in a database

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问题 How do I display out all the information in a database (All tables and records) using PHP? I read displaying tables as HTML table but how do I do it for all the tables? I tried the example here: http://davidwalsh.name/html-mysql-php But it shows the table names, how do I also display all the values? Thanks In Advance 回答1: If you want to pull all tables with the values in mysql , you can use the following code: <?php mysql_connect ("localhost", "DB_USER", "DB_PASSWORD"); //your mysql

PHP MYSQLi Displaying all tables in a database

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How can I retrieve and echo multiple images/videos from 1 post/record without using tables? [closed]

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问题 Closed . This question needs to be more focused. It is not currently accepting answers. Want to improve this question? Update the question so it focuses on one problem only by editing this post. Closed 3 days ago . I will be as specific as possible. I am retrieving information, text, and multiple images from database using mysqli and php. These are my tables: TABLE posts( post_id INT(15) NOT NULL AUTO_INCREMENT, user_id INT(11) NOT NULL, post_text VARCHAR(400) NOT NULL, post_file VARCHAR(200)

201909个人笔记

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2019-9-1 android fiddler抓包视频模块替换资源后生成视频方案：方案一：用AE模板生成视频，.特别复杂，效果最好方案二：用PPT生成视频，.中等难度，效果一般方案三：用第三方SDK（veSDK）.调用容易，收费 2019-9-3 ppt ppsaveasfiletype 枚举值 https://docs.microsoft.com/zh-tw/office/vba/api/powerpoint.ppsaveasfiletype 参考开发文档 https://docs.microsoft.com/zh-cn/office/vba/api/overview/powerpoint 2019-9-6 https://www.microsoft.com/en-us/download/details.aspx?id=40326 OFFICE 2013 VBA documentation download OFFICE 2013 替换图片方法先保存原图片shape相关参数，删除shape,shapes addpicture ,设置为保存的参数得到图片名字：双击ppt中的图片->在上面的排列栏-->选择窗体-->将显示对象的图片名 2019-9-8 安装php-fpm php-mysql扩展问题记录 1.出现 Uncaught Error: Class

Mysql-What does this query mean?

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问题 I'm trying to understand some queries one of them is (select (@a) from (select(@a:=0x00) ,(select (@a) from (information_schema.schemata) where (@a) in (@a:=concat(@a,schema_name,'<br>')) ) ) a ) Can some explain it please? 回答1: Not much to explain, it is a horrendous abuse of session variables. It looks like it is trying to get a concatenated list of database names, in the same manner GROUP_CONCAT would with a delimiter of <br> ; but it looks very unreliable. 来源： https://stackoverflow.com

Mysql-What does this query mean?

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