mysql-error-1054

assigning mysql value to variable inline

由 无人久伴 提交于 2019-12-11 08:44:57
问题 Why doesn't this work i'm trying to get the previous and current value to calculate percent change. I get both values correctly but now how can I reuse them to do the math operatio When I try the below command I get ERROR 1054 (42S22): Unknown column 'currentVal' in 'field list' SELECT IFNULL(DValue,0) as currentVal, (SELECT IFNULL(DValue,0) FROM ... WHERE...) as previousVal, (currentVal-previousVal)/previousVal FROM ... WHERE ...; 回答1: Wrap another query around what you currently have and

error 1054. Unknown coloumn in Insert clause

由 邮差的信 提交于 2019-12-11 03:43:13
问题 i have this problem: if i write the following query: INSERT INTO prodotto (Barcode, InseritoDa, DataInserimento, UrlImage) VALUES ('vfr','ff','12-10-2012', 'vfr.jpg') I get this error message: Error Code: 1054. Unknown column 'InseritoDa' in 'where clause' But in the table prodotto i have this coloumn and its named InseritoDa. Where am I wrong? the error may be due to the fact that the field InseritoDa is a foreign key that points to another table called utente? the trigger associated to the

how to Check string present in database column? [closed]

由 删除回忆录丶 提交于 2019-12-10 22:25:52
问题 This question is unlikely to help any future visitors; it is only relevant to a small geographic area, a specific moment in time, or an extraordinarily narrow situation that is not generally applicable to the worldwide audience of the internet. For help making this question more broadly applicable, visit the help center. Closed 6 years ago . I have document table with fields id , sender_id , receiver_id and receiver_id contains string value like U12,U13,U14 now I currently logged in user and

Doctrine Column not found: 1054 Unknown column 's.features' in 'field list''

由 邮差的信 提交于 2019-12-08 17:24:56
问题 I added a new column "features" to the site table and regenerated the models using Doctrine. This code is causing an error: $siteTable = Doctrine_Core::getTable("Site"); $site = $siteTable->findOneByName("site"); // this line is throwing an exception Exception: Unknown column "s.features" in field list..... I checked the database and it contains the field, I also checked the Site model and the table definition contains the column information. The primary key of all tables is id . Also in the

Query: count multiple aggregates per item

由 眉间皱痕 提交于 2019-12-08 01:41:02
问题 Often you need to show a list of database items and certain aggregate numbers about each item. For instance, when you type the title text on Stack Overflow, the Related Questions list appears. The list shows the titles of related entries and the single aggregated number of quantity of responses for each title. I have a similar problem but needing multiple aggregates. I'd like to display a list of items in any of 3 formats depending on user options: My item's name (15 total, 13 owned by me) My

Can I use a column I have selected later in a query?

由 淺唱寂寞╮ 提交于 2019-12-07 14:49:43
问题 Imagine this query... SELECT `id`, `hits` + `other_hits` AS `total_hits` FROM `something` WHERE `hits` + `other_hits` > 30 As you can see, I've repeated the addition of hits and other_hits . Can I refer to total_hits column I created in other parts of the query? I tried it, and I got 1054: Unknown column in where clause . 回答1: Use: SELECT `id`, `hits` + `other_hits` AS `total_hits` FROM `something` HAVING `total_hits` > 30 The earliest MySQL allows references to column aliases is the GROUP BY

Query: count multiple aggregates per item

由 生来就可爱ヽ(ⅴ＜●) 提交于 2019-12-06 13:29:17
Often you need to show a list of database items and certain aggregate numbers about each item. For instance, when you type the title text on Stack Overflow, the Related Questions list appears. The list shows the titles of related entries and the single aggregated number of quantity of responses for each title. I have a similar problem but needing multiple aggregates. I'd like to display a list of items in any of 3 formats depending on user options: My item's name (15 total, 13 owned by me) My item's name (15 total) My item's name (13 owned by me) My database is: items : itemId, itemName,

sql select statement giving column error

由 青春壹個敷衍的年華 提交于 2019-12-04 05:56:49
问题 When i use SELECT order_id from `order` where `order_id`=U687678601 i get error ERROR 1054: Unknown Column 'U687678601' in where clause but when i type SELECT order_id from`order` where `order_id`='U687678601' it works fine.. I am using mysql. I know its a novice question but can anyone explain why this is happening and can i add quotes programmatically and is it a good idea to add quote through code Thanks 回答1: When we are supplying a string/varchar type to the SQL query we must specify it

MySQL “Unknown Column in On Clause” [duplicate]

由 大兔子大兔子 提交于 2019-12-04 00:02:57
问题 This question already has answers here : MySQL unknown column in ON clause (3 answers) Closed 3 years ago . I have the following MySQL query: SELECT posts.id, posts.name, LEFT(posts.content, 400), posts.author, posts.date, users.display_name, GROUP_CONCAT(tags.tag ORDER BY tag_linking.pid ASC SEPARATOR ",") update_tags FROM posts, tag_linking, tags INNER JOIN `users` ON posts.author=users.id; WHERE tag_linking.pid = posts.id AND tags.id = tag_linking.tid ORDER BY posts.date DESC Which, was

MySQL error #1054 - Unknown column in 'Field List'

由 橙三吉。 提交于 2019-12-03 16:16:41
问题 Whenever I try to input data into my tblorder I get the error message #1054 - Unknown column 'FK_Customer_ID' in 'field list'. I have tried breaking my code down and in doing this I found that the error is repeated for FK_Customer_ID and OrderQuantity whereas FK_DVD_ID it will take single data entries. I have tried dropping the table and recreating it, I have dropped the database and recreated it but nothing works. As far as I can tell my code is correct along with my spelling so I'm really
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