mysql-error-1054

问题 Hey all, I'm getting an error OperationalError: (1054, "Unknown column 'XX' in 'where clause'") Where XX is the value of CLASS in the following code conn = MySQLdb.connect(host = "localhost",user = "user", passwd = "pass",db = "dbase") cursor = conn.cursor() cursor.execute("""SELECT * FROM %s WHERE course =%s AND sec = %s""" % (str(DEPT),str(CLASS),str(SEC),)) The thing is, I only get this error with certain values, namely, when CLASS contains a letter. I have the table set up as varchar if

问题 Let's create a TestParent table which caches the total value of the num column in a TestChild table, and insert some rows. CREATE TABLE TestParent ( id INT NOT NULL PRIMARY KEY, total INT NOT NULL DEFAULT 0); CREATE TABLE TestChild ( parent_id INT NOT NULL, num INT NOT NULL); INSERT INTO TestParent (id) VALUES (123); INSERT INTO TestChild (parent_id, num) VALUES (123, 1); CREATE PROCEDURE Sync (IN parent INT) UPDATE TestParent SET total = ( SELECT SUM(num) FROM TestChild WHERE parent_id

问题 I've read my threads about this problem but I still don't know how to solve it. Error SQL query: -- -- Dump data for table `bi_instituicoes` -- INSERT INTO `bi_instituicoes` (`id`, `Instituicao`, `Morada`, `Código Postal`, `Localidade`, `País`) VALUES (1, 'Escola Secundária D. Afonso Sanches', 'Alameda Flâmula Pais', NULL, 'Vila do Conde ', 'Portugal'), (2, 'Escola Secundária da Boa Nova', 'Av. dos Combatentes da Grande Guerra', NULL, 'Leça da Palmeira ', 'Portugal'), (3, 'Escola Secundária

问题 I had the below query working in mysql 4.1, but does not in 5.0: SELECT * FROM email e, event_email ee LEFT JOIN member m on m.email=e.email WHERE ee.email_id = e.email_id The error: 1054 (Unknown column 'e.email' in 'on clause') 回答1: You can only refer the tables previously joined with the JOIN clause in the ON clause. SELECT * FROM email e JOIN event_email ee ON ee.email_id = e.email_id LEFT JOIN member m ON m.email = e.email This can be illustrated better if I put the parentheses around

问题 Have looked for any solution but unsuccessfully... The mystery is about body of my few functions. I presented two of them below. They are pretty the same but Fun1 works fine and Fun2 doesn't. The error is as in topic - "Unknown column in 'field list'". I've noticed that it rather depends on declared variable type - if it's string (like tadnotation) there is no problem met, if it's time, decimal, enum, it causes errors. Can someone explain it to me? And of course I'm also searching for the

问题 I have just exported a table using phpMyAdmin and I have tried to import this table into my local database by importing the sql file I have just exported. After phpMyAdmin imports 330 rows of the 15,000. It says: 1054 - Unknown column 'font_name' in 'field list' How can anything go wrong, I thought it was straight forward export/import? I have had a look at row 330 and 331 and there isn't anything wrong within the two columns. How can I narrow this down? What is the problem likely to be?

问题 I am doing some work on a MySQL database and completely stumped on receiving the error 1054 - Unknown column 'Puzzles.PuzzleID' in 'on clause' Both the table and the column names exist and are correct. I just created it in Navicat's visual designer. SELECT `PuzzleCategories`.`PuzzleCategory`, `Clients`.`BusinessName`, `Puzzles`.`PuzzleNumber` FROM `Puzzles` Inner Join `PuzzleCategories` ON `Puzzles`.`PuzzleCategoryID` = `PuzzleCategories`.`PuzzleCategoryID` , `Clients` Inner Join

问题 I'm trying to join some tables together in MySQL, but I seem to get an error saying: #1066 - Not unique table/alias: 'calendar_jobs' I really want it to select everything from the cal_events, the 2 user bits and just the destination col from the jobs table, but become "null" if there arn't any job. A right join seemed to fit the bill but doesn't work! Can anyone help!? UPDATE: Thanks for the help on the previous query, I'm now up to this: SELECT calendar_events.* , calendar_users

问题 I keep getting the error 1054 - Unknown column 'apa_calda' in 'where clause' in MySQL. Here is the query: SELECT user_id FROM `detalii_contor` WHERE tip_contor=apa_calda I want to use this query in a PHP file but it doesn't give any results. So I tried to write it in the SQL command prompt. Here is what I tried in the PHP file: $Q = "SELECT id_contor, den_contor FROM detalii_contor WHERE tip_contor='".$contor."'"; $Q = "SELECT id_contor, den_contor FROM detalii_contor WHERE tip_contor='

问题 +------------------+ +------------------+ | object | | example | +------------------+ +------------------+ | id | | id | | table_name | | ... | | ref_id | | | +------------------+ +------------------+ object [ id = 5, table_name = example, ref_id = 2] example [ id = 2 ] I have a table which can represent a group of objects originating from a number of different tables. These objects all have an id , referenced by object.ref_id . I am trying to select the original object (from the table