mongodb-query

问题 I need to get the closest place near a certain point using this data structure: [ { "data_id": "127", "actual_data": [ { "id": "220", "value": "shaul" }, { "id": "221", "value": "3234324" }, { "id": "222", "value": { "lngalt": [ 13.7572225, -124.0429047 ], "street_number": null, "political": null, "country": null, } }, { "id": "223", "value": "dqqqf1222fs3d7ddd77@Dcc11cS2112s.com" }, { "id": "224", "value": "123123" }, { "id": "225", "value": "lala1" }, .... }, { "data_id": "133", "actual

问题 We're using MongoDB via Spring Data and rely on the findAndModify operation to update existing entities or create new ones. In the findAndModify we can configure to return old state of the entity or the new one using returnNew(...) . Is there some way to return both old and new entities from findAndModify ? We need to compare entity states before and after update, this is why we need both instances. At the moment we're resorting to requireNew(false) and then manually update a copy of the old

问题 let dbOperations = Edge.collection.initializeOrderedBulkOp() edges.forEach(edge => { dbOperations.find({_id: edge.id}).upsert().updateOne({ $set: { value: edge.value }, $setOnInsert: { _id: edge.id } }) }) dbOperations.execute() .then(result => { console.log(result.nModified) // This shows the number of edges that is actually modified console.log(result.getModifiedIds()) // This is what I want to achieve }) Any way to achieve this? 回答1: Well from one point of view the anwer is "no" and there

问题 Mongo DB Array Structure: { "time" :[ [2018-12-18T20:16:28.800Z , 2018-12-18T20:16:28.800Z, 2016-11-14T10:16:32.700Z], [2016-11-14T10:16:32.700Z, 2017-09-17T11:16:54.500Z, 2018-12-18T20:16:28.800Z], [2017-09-17T11:16:54.500Z, 2018-12-18T20:16:28.800Z, 2016-11-14T10:16:32.700Z] ], "bar": [ [2,5,9,8], [6,3,7,None], [7,8,None] ] } Expected output with One array without None values: "time" :[ 2018-12-18T20:16:28.800Z, 2018-12-18T20:16:28.800Z, 2016-11-14T10:16:32.700Z, 2016-11-14T10:16:32.700Z,

问题 Mongo DB Array Structure: { "time" :[ [2018-12-18T20:16:28.800Z , 2018-12-18T20:16:28.800Z, 2016-11-14T10:16:32.700Z], [2016-11-14T10:16:32.700Z, 2017-09-17T11:16:54.500Z, 2018-12-18T20:16:28.800Z], [2017-09-17T11:16:54.500Z, 2018-12-18T20:16:28.800Z, 2016-11-14T10:16:32.700Z] ], "bar": [ [2,5,9,8], [6,3,7,None], [7,8,None] ] } Expected output with One array without None values: "time" :[ 2018-12-18T20:16:28.800Z, 2018-12-18T20:16:28.800Z, 2016-11-14T10:16:32.700Z, 2016-11-14T10:16:32.700Z,

问题 I have a document which looks like this { _id:1, list_id:23, name:'list01' cards:[ { id:3, name:'card01' categories:[{ id:10, category:'section01', tags:[{id:11,name:'tag01',is_selected: true}] }] } ] } I need to insert/push some data to tags array in a selected category for a given list_id but I'm getting an error saying MongoError: Too many positional (i.e. '$') elements found in path 'cards.$.categories.$.tags' This is the query that I have tried out. What's wrong with this query any idea

问题 I have 2 collections : Users collection : { _id: ObjectId } Toto Collection : { _id: ObjectId fieldA: {_id: ObjectId} fieldB: [{_id: ObjectId}, {_id: ObjectId}] } And I'm trying to join the element of A collection which fieldA's id OR one of fieldB's id is matching with user's id with following aggregation : db.users.aggregate([ { $lookup: { from: "Toto", let: { "user_id": "$_id" }, as: "fcollection", pipeline: [ { $match: {$or:[ {"fieldB": {$elemMatch: {"_id": "$$user_id"}}}, {$expr: {$eq :[

问题 I have 2 collections : Users collection : { _id: ObjectId } Toto Collection : { _id: ObjectId fieldA: {_id: ObjectId} fieldB: [{_id: ObjectId}, {_id: ObjectId}] } And I'm trying to join the element of A collection which fieldA's id OR one of fieldB's id is matching with user's id with following aggregation : db.users.aggregate([ { $lookup: { from: "Toto", let: { "user_id": "$_id" }, as: "fcollection", pipeline: [ { $match: {$or:[ {"fieldB": {$elemMatch: {"_id": "$$user_id"}}}, {$expr: {$eq :[

问题 I have to insert multiple documents if they don't already exist, but the important thing is that in the query results I need to have IDs of both the inserted and already existing items. I'm trying with the following bulkWrite operation: // external_id is a unique id other than the mongo _id let items = [ {external_id: 123, name: "John"}, {external_id: 456, name: "Mike"}, {external_id: 789, name: "Joseph"} ]; db.collection("my_collection") .bulkWrite( items.map((item) => { return { updateOne:

问题 below is my query: while executing below query getting mongoerror : Expression $in takes exactly 2 arguments. 1 were passed in. i am using $in Comparison operator { "$expr": { "$not": { "$eq":{ "$and": [ { "PrName": { "$in": [ "pname" ] } }, { "AccountId": { "$in": [ "34562", "88765", "87654", "12345" ] } } ] } } } } 回答1: When you use $expr , the operator expressions syntax changes a little: { $in: [ <expression>, <array expression> ] } { "$expr": { "$not": { "$and": [ { "$in": [ "$PrName", [