mod-wsgi

问题 I've got a Python script that is executing functions asynchronously by using PEST wsgi library. However, when I try to import another module it simply results in a 500 error. The way I try to reference it is: from foo import * from foo import Foo where foo is a file .py in which I have the object that I want to reference to. Tried to monitor the calls through Chrome's Inspect Element Control but couldn't find a thing. Also tried to debug using Apache's error log, but nothing there. Any hints

问题 I'm on Windows, and am trying to invoke mod_wsgi on an Apache server. I located mod_wsgi.so in /usr/lib/apache2/modules/ and I have a directory called MyApp - /home/danu_bg/public_html/MyApp . Within this directory I have application.wsgi def application(environ, start_response): status = '200 OK' output = 'Hello World!' response_headers = [('Content-type', 'text/plain'), ('Content-Length', str(len(output)))] start_response(status, response_headers) return [output] And the .htaccess

问题 I'm running Django 2.0.4 with mod_wsgi 4.5.20. I'm getting an error when I try to deploy a site to our dev environment at /parature . What's weird is that the site deployed at the root of the VirtualHost is responding as normal: [Tue Apr 10 13:34:08.998704 2018] [wsgi:error] [pid 65245] [client xx.yy.zz:65390] Timeout when reading response headers from daemon process 'parature-develop-https': /var/django/html/parature-develop/config/wsgi.py I can run the site via runserver with the virtualenv

问题 i'm having this problem: i'm runing pythonbrew to get python2.7, and so i re-compiled mod_wsgi to use the 2.7 python. to that end, i followed this tutorial: code.google.com/p/modwsgi/wiki/QuickInstallationGuide which involved downloading the file - there is a tar.gz file i get - and then "configuring it" with ./configure --with-python=/home/bharal/.pythonbrew/pythons/Python-2.7.2/bin/python --enable-shared now i'm assuming this is the right place to attach for my python - the value for with

问题 I'm setting up Django with apache, mod_wsgi, virtual env I have a virtual env that I want to use here: [Missleading name - long story!] /home/andy/Dev/python/async-mongo/ I downloaded mod_wsgi and compiled it with virtual_env as root ./configure --with-python=/home/andy/Dev/python/async-mongo/bin/python I ran as root: make install I setup WSGIPythonHome & Path in http.conf WSGIPythonHome /home/andy/dev/python/async-mongo/ WSGIPythonPath /home/andy/dev/python/async-mongo/lib/python2.6/site

问题 The error from apache after a 504 page [info] mod_wsgi (pid=): Python home /var/venv/mybox. [info] mod_wsgi (pid=): Initializing Python. ImportError: No module named site This is with a barely configured app. <IfModule mod_wsgi.c> WSGIDaemonProcess myapp python-home=/var/venv/mybox WSGIProcessGroup myapp WSGIScriptAlias / /var/www/html/web/myapp/wsgi.py WSGISocketPrefix /var/run/wsgi <Directory /var/www/html/web> <Files wsgi.py> Order deny,allow Allow from all </Files> </Directory> </IfModule

问题 I've deployed a python flask app on an apache server. Here is my abc.conf file: WSGIDaemonProcess voting_app threads=5 WSGIScriptAlias /election /var/www/voting_app/voting.wsgi LogLevel info ErrorLog "/var/www/voting_app/error.log" CustomLog "/var/www/voting_app/access.log" combined <Directory /var/www/voting_app> WSGIProcessGroup voting_app WSGIApplicationGroup %{GLOBAL} Order deny,allow Allow from all </Directory> To check debugging I made a syntax error in my application. On restarting the

问题 I'm putting my django site in production for the first time so please forgive for my ignorance. I'm trying to put my django site on apache. I've read documentation about mod_wsgi and tried that simple Hello world so it is configured OK. The problem I'm having seems to be with using virtualenvs with it. I wanna set things up properly including virtualenvs and everything so I'm ready for future sites. To the problem now. The error I'm getting in apache log is: No module named django.core

问题 I'm using the Python 2.5 that came with Mac OS X Snow Leopard (10.6). I've set the defaults value: defaults write com.apple.versioner.python Version 2.5 and normally I get python 2.5 as it suggests. However when I try to build mod_wsgi, that doesn't seem to adhere. I've used the --with-python=/usr/bin/python2.5 option to configure to force it to use python 2.5 but the shared library which is built ends up with references to the python 2.6 libraries. I've also tried: setting $VERSIONER_PYTHON

问题 I'm using mod_wsgi and was wondering if it's possible to over-write the print() command (since it's useless). Doing this doesn't work: print = myPrintFunction Since it's a syntax error. :( 回答1: Print is not a function in Python 2.x, so this is not directly possible. You can, however, override sys.stdout. If you are on Python 3.0 in which print is now a function what you have would then work, assuming you have the right signature. Also see a related question in this site. 回答2: Would import sys