mkdir

After reading the mkdir(2) man page for the Unix system call with that name, it appears that the call doesn't create intermediate directories in a path, only the last directory in the path. Is there any way (or other function) to create all the directories in the path without resorting to manually parsing my directory string and individually creating each directory ? Carl Norum There is not a system call to do it for you, unfortunately. I'm guessing that's because there isn't a way to have really well-defined semantics for what should happen in error cases. Should it leave the directories that

I'm trying to create a directory on my server using PHP with the command: mkdir("test", 0777); But it doesn't give full permissions, only these: rwxr-xr-x The mode is modified by your current umask , which is 022 in this case. The way the umask works is a subtractive one. You take the initial permission given to mkdir and subtract the umask to get the actual permission: 0777 - 0022 ====== 0755 = rwxr-xr-x. If you don't want this to happen, you need to set your umask temporarily to zero so it has no effect. You can do this with the following snippet: $oldmask = umask(0); mkdir("test", 0777);

I am writing a shell script to run under the KornShell (ksh) on AIX. I would like to use the mkdir command to create a directory. But the directory may already exist, in which case I do not want to do anything. So I want to either test to see that the directory does not exist, or suppress the "File exists" error that mkdir throws when it tries to create an existing directory. Any thoughts on how best to do this? Try mkdir -p : mkdir -p foo Note that this will also create any intermediate directories that don't exist; for instance, mkdir -p foo/bar/baz will create directories foo , foo/bar ,