minimum

问题 I would ask how to decrease minimum version of 'compile using android version'. I have: compile using android version ( 2.3[Gingerbred] , 6.0[Marshmallow] ) minimum android to target ( 1.6 - 6.0 ) target android version ( 1.6 - 6.0 ) I would like to set lower than 2.3 version in 'compile using android version'. How to set it? Dowload something from manager sdk? Please help me. I ask because I have amazing problems with my Samsung Galaxy Ace. Any application cannot work on my mobile even code

问题 I am working on a homework assignment where I calculate the values in an interval of integers of a function (f(x) = x * x – 12 * x + 40) in a 'for' loop. I need to find a minimum value. That's all fine, but I also need to keep the index number for which the value was smallest. At the moment I reiterate the function again in another loop, but this looks really messy. Also I could derive x and calculate the answer using the known minimum, but that's also weird, because derivation is not so

问题 I'm reviewing a python exercise which does the following : reads list of numbers til "done" gets entered. When "done" is inputted, print largest and smallest of the numbers . And it should be without directly using the built-in functions, max() and min(). Here is my source. Traceback says, "'float' object is not iterable" I think my errors are coming from not using the list properly to calculate smallest and largest. Any tips and help will be greatly appreciated! while True: inp = raw_input(

问题 I have four arrays of size 2^N where N = 25. The elements of arrays have been generated by my algorithm. These are sorted but contain numbers. Now I have to take each element of array1 and select elements of array2, array3, array4 such that sum of them should be minimum (when I say sum I can take a1[k] +-a2[j]+-a3[m]+-a4[t]. I think it is similar to K Dimension merge problem. Can some one point to the literature/implementation /heuristic for doing the same. Regards, Allahbaksh 回答1: Step 1 For

问题 I'm trying to find the minimum value in a list of integers using recursion. The main idea is that if the list is only one element long, this element is my minimum. Else, I divide the list onto two smaller lists of the same size, look for minimum value in both of them and then compare which one is smaller. The code looks like this: def minimum(a,l,p): if l == p: return a[l] else: m1 = minimum(a,l, (l+p)/2) m2 = minimum(a, (l+p)/2 + 1, p) if m1 < m2: return m1 else: return m2 It doesn't seem to

问题 I've got a matrix with a lot of zeros and with positive numerical values. I want to get the row and column number for which the element is the minimal NONZERO value of the matrix. I don't find that min() has extra options to exclude zero, so how can I handle this? 回答1: Seems like there could be a shorter answer but u can replace the zeros with NA and use na.rm=T test = matrix(c(0:9,0:9),nrow =4,ncol=5) test[which(test==0)] = NA minValue = min(test,na.rm=T) rows = which(apply(test,1,min,na.rm

问题 I've got a matrix with a lot of zeros and with positive numerical values. I want to get the row and column number for which the element is the minimal NONZERO value of the matrix. I don't find that min() has extra options to exclude zero, so how can I handle this? 回答1: Seems like there could be a shorter answer but u can replace the zeros with NA and use na.rm=T test = matrix(c(0:9,0:9),nrow =4,ncol=5) test[which(test==0)] = NA minValue = min(test,na.rm=T) rows = which(apply(test,1,min,na.rm

问题 i want to know how can i find the maximum and minimum value in c++ by user input value and and user also put the limit for for loop , for example : Write a c++ program that initially takes an integer value from the user as the loop’s limit. It means that the loop will execute the same times as the input from the user. The loop will then take integer values as input from the user until it reaches loop limit. You are required to use only one variable which will be used to take input repeatedly

问题 I'm having an issue with highcharts where I have a number of different charts being generated by JSON calls. For the majority of these charts I need the minimum y-axis value to be set at 0, however there are a couple of occasions where negative values need to be shown. How can I tell highcharts to have a minimum y-axis value of 0 only if there are no negative values in the data, is this even possible? Thanks 回答1: The option that you're looking for is called softMin and was introduced in

问题 I have a data.frame that contains 4 columns (given below). I want to find the index of the minimum column (NOT THE VALUE) for each row. Any idea hiw to achieve that? > d V1 V2 V3 V4 1 0.388116155 0.98999967 0.41548536 0.76093748 2 0.495971331 0.47173142 0.51582728 0.06789924 3 0.436495321 0.48699268 0.21187838 0.54139290 4 0.313514389 0.50265539 0.08054103 0.46019601 5 0.277275961 0.39055360 0.29594162 0.70622532 6 0.264804739 0.86996266 0.85708635 0.61136741 7 0.627344463 0.54277873 0