methods

问题 If i want to destruct an Object i would do : const obj = { a: 'a', fn: () => 'some function' } // const fn = obj.fn; // OR const { a, fn } = obj; console.log( fn() ); this doesn't work for the Date Object : Uncaught TypeError: this is not a Date object. const date = new Date(); const day = date.getDate(); console.log(day); // works const { getDate } = date; console.log( getDate() ); // doesn't work Why is this possible with the first Object and not with the Date ? how would one acheive that

问题 I have a script that changes the status of orders based on our ERP system. In addition to that, we need to add customer notes. I found the way to do it: $order->add_order_note($note); $order->save(); Unfortunately this won't work outside the order edit screen, I tried to run it from my custom plugin. (source) If I do it via $order->update_status($status, $note); it only updates the status. Is there a way to add a note outside the edit screen? (Including e-mailing the customer) 回答1: If the

问题 I'm new to programming, so I apologize if there is a very simple answer to this, but I cannot seem to find anything that actually. I am using a scanner object for user input in a guess your number game. The scanner is declared in my main method, and will be used in a single other method (but that method will be called all over the place). I've tried declaring it as static, but eclipse has a fit over that and won't run. public static void main(String[] args) { int selection = 0; Scanner dataIn

问题 I'm new to programming, so I apologize if there is a very simple answer to this, but I cannot seem to find anything that actually. I am using a scanner object for user input in a guess your number game. The scanner is declared in my main method, and will be used in a single other method (but that method will be called all over the place). I've tried declaring it as static, but eclipse has a fit over that and won't run. public static void main(String[] args) { int selection = 0; Scanner dataIn

问题 I would like to call an object method dynamically. The variable "MethodWanted" contains the method I want to execute, the variable "ObjectToApply" contains the object. My code so far is: MethodWanted=".children()" print eval(str(ObjectToApply)+MethodWanted) But I get the following error: exception executing script File "<string>", line 1 <pos 164243664 childIndex: 6 lvl: 5>.children() ^ SyntaxError: invalid syntax I also tried without str() wrapping the object, but then I get a "cant use +

问题 I would like to call an object method dynamically. The variable "MethodWanted" contains the method I want to execute, the variable "ObjectToApply" contains the object. My code so far is: MethodWanted=".children()" print eval(str(ObjectToApply)+MethodWanted) But I get the following error: exception executing script File "<string>", line 1 <pos 164243664 childIndex: 6 lvl: 5>.children() ^ SyntaxError: invalid syntax I also tried without str() wrapping the object, but then I get a "cant use +

问题 I would like to call an object method dynamically. The variable "MethodWanted" contains the method I want to execute, the variable "ObjectToApply" contains the object. My code so far is: MethodWanted=".children()" print eval(str(ObjectToApply)+MethodWanted) But I get the following error: exception executing script File "<string>", line 1 <pos 164243664 childIndex: 6 lvl: 5>.children() ^ SyntaxError: invalid syntax I also tried without str() wrapping the object, but then I get a "cant use +

问题 class MyClass { void myMethod(byte b) { System.out.print("myMethod1"); } public static void main(String [] args) { MyClass me = new MyClass(); me.myMethod(12); } } I understand that the argument of myMethod() being an int literal, and the parameter b being of type byte, this code would generate a compile time error. (which could be avoided by using an explicit byte cast for the argument: myMethod((byte)12) ) class MyClass{ byte myMethod() { return 12; } public static void main(String [ ] args

问题 I've started Javascript 30. What bothers is like on given example code: const audio = document.querySelector(`audio[data-key="${e.keyCode}"]`); Why are the arguments put into the backticks? I understand how to use double and single quotes and when I can use both. However I don't understand how and when to use backticks. 回答1: The backticks allow you to use the string interpolation syntax ${}. 回答2: You can add expression in string with back-tick. This feature was add on ES6. 回答3: Backticks are

问题 Closed . This question is opinion-based. It is not currently accepting answers. Want to improve this question? Update the question so it can be answered with facts and citations by editing this post. Closed 9 days ago . Improve this question i experienced this questions in a during the job interview, but i cant answered it and i cant find the answer after. They asked me 'Why methods return just one kind of parameter in normal conditions in C#? (ref-out is extra way to return multiple