methods

JSF - actionListener tag calls method which doesn't take an ActionEvent parameter

时间秒杀一切 提交于 2019-12-28 07:05:07
问题 I keep reading posts which say that ActionListener methods must have the following signiture: public void calledByActionListener(ActionEvent e) { } Invoked like so: <p:commandButton value="Example" id="example" process="@this" ajax="false" actionListener="#{exampleBean.calledByActionListener()}"> However I have a no-arg method like this which works: public void calledByActionListener() { } Did something change? 回答1: Yes, that's the new EL 2.2 feature of invoking methods with custom arguments.

How do I chain methods in PHP? [duplicate]

微笑、不失礼 提交于 2019-12-28 04:09:24
问题 This question already has answers here : PHP method chaining? (8 answers) Closed 4 years ago . jQuery lets me chain methods. I also remember seeing the same in PHP so I wrote this: class cat { function meow() { echo "meow!"; } function purr() { echo "purr!"; } } $kitty = new cat; $kitty->meow()->purr(); I cannot get the chain to work. It generates a fatal error right after the meow. 回答1: To answer your cat example, your cat's methods need to return $this , which is the current object instance

C# - How to check if namespace, class or method exists in C#?

我是研究僧i 提交于 2019-12-28 03:40:33
问题 I have a C# program, how can I check at runtime if a namespace, class, or method exists? Also, how to instantiate a class by using it's name in the form of string? Pseudocode: string @namespace = "MyNameSpace"; string @class = "MyClass"; string method= "MyMEthod"; var y = IsNamespaceExists(namespace); var x = IsClassExists(@class)? new @class : null; //Check if exists, instantiate if so. var z = x.IsMethodExists(method); 回答1: You can use Type.GetType(string) to reflect a type. GetType will

Write a mode method in Java to find the most frequently occurring element in an array

假如想象 提交于 2019-12-28 02:05:10
问题 The question goes: Write a method called mode that returns the most frequently occurring element of an array of integers. Assume that the array has at least one element and that every element in the array has a value between 0 and 100 inclusive. Break ties by choosing the lower value. For example, if the array passed contains the values {27, 15, 15, 11, 27}, your method should return 15. (Hint: You may wish to look at the Tally program from earlier in this chapter to get an idea of how to

Write a mode method in Java to find the most frequently occurring element in an array

会有一股神秘感。 提交于 2019-12-28 02:04:37
问题 The question goes: Write a method called mode that returns the most frequently occurring element of an array of integers. Assume that the array has at least one element and that every element in the array has a value between 0 and 100 inclusive. Break ties by choosing the lower value. For example, if the array passed contains the values {27, 15, 15, 11, 27}, your method should return 15. (Hint: You may wish to look at the Tally program from earlier in this chapter to get an idea of how to

Why is Main method private?

余生颓废 提交于 2019-12-27 23:37:08
问题 New console project template creates a Main method like this: class Program { static void Main(string[] args) { } } Why is it that neither the Main method nor the Program class need to be public? 回答1: The entry point of a program is marked with the .entrypoint IL directive. It does not matter if the method or the class is public or not, all that matters is this directive. 回答2: The Main method shouldn't need to be called by anyone. It is actually marked as the entry point for execution in the

Android ViewPager setCurrentItem not working after onResume

99封情书 提交于 2019-12-27 17:41:06
问题 Ive got this strange issue, ViewPager's setCurrentItem(position, false) works perfectly fine, then im switching to another activity, and after im back to the first activity, the ViewPager always ends up on the first item. Even though ive added setCurrentItem to onResume method it still ignores it. Its not even throwing any exception when im trying to set item to out of bounds index. Though later on when i call this method, when the button "next" is clicked, it works like expected. Checked my

Android ViewPager setCurrentItem not working after onResume

|▌冷眼眸甩不掉的悲伤 提交于 2019-12-27 17:40:09
问题 Ive got this strange issue, ViewPager's setCurrentItem(position, false) works perfectly fine, then im switching to another activity, and after im back to the first activity, the ViewPager always ends up on the first item. Even though ive added setCurrentItem to onResume method it still ignores it. Its not even throwing any exception when im trying to set item to out of bounds index. Though later on when i call this method, when the button "next" is clicked, it works like expected. Checked my

Go embedded struct call child method instead parent method

自作多情 提交于 2019-12-27 12:06:29
问题 Here a sample of Go code with an Interface, a Parent Struct and 2 Children Structs package main import ( "fmt" "math" ) // Shape Interface : defines methods type ShapeInterface interface { Area() float64 GetName() string PrintArea() } // Shape Struct : standard shape with an area equal to 0.0 type Shape struct { name string } func (s *Shape) Area() float64 { return 0.0 } func (s *Shape) GetName() string { return s.name } func (s *Shape) PrintArea() { fmt.Printf("%s : Area %v\r\n", s.name, s

How to call a method in java?

笑着哭i 提交于 2019-12-27 11:45:56
问题 How to call a method, which is in another class of same package in java? What i know is, using an object we can call a method from a different class. Is there any other way to call a method of different class? 回答1: Create an instance of Class B: B b=new B(); b.method(); or define an static method in Class B: class B { static void staticMethod(); } and call it like this: B.staticMethod(); 回答2: Methods are object methods or class methods . Object methods: it applies over an object. You have to