methods

Create my own method for DataFrames (python)

走远了吗. 提交于 2020-04-07 23:02:54
问题 So I wanted to create a module for my own projects and wanted to use methods. For example I wanted to do: from mymodule import * df = pd.DataFrame(np.random.randn(4,4)) df.mymethod() Thing is it seems I can't use .myfunc() since I think I can only use methods for the classes I've created. A work around is making mymethod a function and making it use pandas.Dataframes as a variable: myfunc(df) I don't really want to do this, is there anyway to implement the first one? 回答1: If you really need

C# Generic Method, cannot implicit convert

纵饮孤独 提交于 2020-04-06 04:52:12
问题 I've got the following code: public static T GetCar<T>() where T : ICar { T objCar = default(T); if (typeof(T) == typeof(SmallCar)) { objCar = new SmallCar(""); } else if (typeof(T) == typeof(MediumCar)) { objCar = new MediumCar(""); } else if (typeof(T) == typeof(BigCar)) { objCar = new BigCar(""); } return objCar; } And this is the error I am getting: Cannot implicitly convert type 'Test.Cars' to 'T' What Am I missing here? All car types implement the ICar interface. Thanks 回答1: You cannot

How are methods, `classmethod`, and `staticmethod` implemented in Python?

倖福魔咒の 提交于 2020-04-05 13:42:55
问题 At what point do methods in Python acquire a get property? —As soon as they're defined in the class? Why does Python let me define a method without any arguments (not even a first self argument)? I know how to use classmethod and staticmethod , and I know that they're built-in functions, but what happens to a function that is so-decorated? Essentially, I'm wondering about the "magic" that happens between class definition and class construction. 回答1: Check this out. http://docs.python.org

How are methods, `classmethod`, and `staticmethod` implemented in Python?

人走茶凉 提交于 2020-04-05 13:41:04
问题 At what point do methods in Python acquire a get property? —As soon as they're defined in the class? Why does Python let me define a method without any arguments (not even a first self argument)? I know how to use classmethod and staticmethod , and I know that they're built-in functions, but what happens to a function that is so-decorated? Essentially, I'm wondering about the "magic" that happens between class definition and class construction. 回答1: Check this out. http://docs.python.org

Javascript OOP, Accessing methods from other nested methods

拈花ヽ惹草 提交于 2020-03-25 17:24:52
问题 Ok, folks, getting there with learning my JS. I have come across a singular one. Here's the code: hangar = function(game){ } hangar.prototype = { loadImages: function(graphicAssets){ ... }, writeTerminal: function(timer, str, destination){ }, writeStats: function(){ var writeTerminal = this.writeTerminal; console.log('wt', this.writeTerminal); console.log('wt2', writeTerminal); //ZOMG This does not work! }, handleHangarInput: function(layerShips, layerBg){ ... does some variable declarations

Have trouble understanding a piece of golang code

好久不见. 提交于 2020-03-24 03:56:30
问题 package main type Writeable interface { OnWrite() interface{} } type Result struct { Message string } func (r *Result) OnWrite() interface{} { return r.Message } // what does this line mean? what is the purpose? var _ Writeable = (*Result)(nil) func main() { } The comments in the code snippet expressed my confusion. As I understood, the line with comment notifies the compiler to check whether a struct has implemented the interface, but I am not sure very much. Could someone help explaining

Change cart items subscription properties values before checkout

≡放荡痞女 提交于 2020-03-23 06:24:06
问题 This may be a noob question so apologies in advance. I have variable subscription products whose price varies by subscription length. I also have simple subscriptions that have a subscription_length = 0. When the cart contains both types, Woocommerce subscriptions creates two subscriptions. I am trying to modify the subscription_length metadata of all the items in the cart to match the longest length in the cart so only one subscription will be created. I just can't seem to find right way to

'respond_to?' versus 'defined?'

安稳与你 提交于 2020-03-22 03:52:56
问题 If I want to check whether a method with a given name is defined, which is better to use, respond_to? , or defined? ? From the point of view of efficiency, there can be an argument for using defined? because defined? is a built in keyword, whereas respond_to? is a method, and hence the former might be faster. But on the other hand, under the situation that the expression to be checked is known to be a simple method, defined? needs to parse the whole expression, and that may be a drawback as

How to pass an array and a single element to a multiple argument method?

我的梦境 提交于 2020-03-16 03:52:14
问题 Example: public void foo(params string[] s) { ... } We can call this method with: a) foo("test", "test2", "test3") // multiple single strings b) foo(new string[]{"test", "test2", "test3"}) // string array But it is not possible to call the method with: c) foo("test", new string[]{"test", "test2", "test3"}) So when I have a single string and an array of strings, do I have to put them into one array first to call the method? Or is there a nice workaround to tell the method to consider the

How to pass an array and a single element to a multiple argument method?

一曲冷凌霜 提交于 2020-03-16 03:49:06
问题 Example: public void foo(params string[] s) { ... } We can call this method with: a) foo("test", "test2", "test3") // multiple single strings b) foo(new string[]{"test", "test2", "test3"}) // string array But it is not possible to call the method with: c) foo("test", new string[]{"test", "test2", "test3"}) So when I have a single string and an array of strings, do I have to put them into one array first to call the method? Or is there a nice workaround to tell the method to consider the