mergesort

I have managed to get a merge sort working in p5.js to sort different length lines but can not figure out how to actually show them being sorted. I.e show them unsorted and then update their position as they are being sorted. I'm not sure if there is an easy way to do this with the way my code is currently written or if I need to break the sorting function up and re draw it after each stage? var values = []; var numLines = 500; function setup() { createCanvas(900, 600); colorMode(HSB, height); for (i = 0; i < numLines; i++) { values[i] = (round(random(height))); } values = mergeSort(values);

For merge-sort divide and conquer operations, how much time is required in bottom up merging phase? My instructor says that it is be linear, hence it will be O(n) . But I didn't get it. How will it be linear? How will merging operation be linear O(n) ? Merge operation of two arrays, is scanning arrays and picking the lowest/highest of two. so you have a: [1, 3, 6, 7] b: [4, 5, 7, 8] you compare like this (sort of pseudo code) indexA = 0; indexB = 0; auxilaryArray = []; indexAux = 0; while true if indexA > len(a)-1 or indexb > len(b) -1 break # you are cherry picking one from the two array

I have made a merge sort program in Python and it is running perfectly but I have modified it to count the number of inversions involved and now it is giving me an error : Here's my code: def merge_list(left,right,c): result=[] i,j=0,0 while i < len(left) and j < len(right): if left[i] < right[j]: result.append(left[i]) print "Left result",result i=i+1 elif left[i] > right[j]: result.append(right[j]) print "Right result",result j=j+1 if right[j] < left[i] and i<j: c=c+1 result=result+left[i:] result=result+right[j:] print "Inversions: ",c return result,c def sort_and_count(lis,count): if len

I'm learning algorithms from Cormen and Co. and I have problem with implementation of merge sort from their pseudocode. I compiled it by: $ gcc -Wall -g merge_sort.c I have a problem because for numbers: 2 4 5 7 1 2 3 6 The result is: 1 2 2 3 3 4 5 5 I tried to read carefully the pseudo code but this does not help me. I want to know what I'm doing wrong. Below is my code: #include <stdio.h> #define SIZE 8 void merge(int *array_of_integers, int p, int q, int r) { int n1 = q - p + 1; int n2 = r - q; int i, j, k; int left_array[n1 + 1]; int right_array[n2 + 1]; for (i = 0; i < n1; i++) left_array

i have code for mergesort using linked list,it works fine,my question what is complexity of this algorithm?is it O(nlog(n))?also is it stable?i am interested because as i know mergesort is stable,what about using linked list?if we have elements with some equal with each-other,does this code preserve orders of elements?thanks a lot #include<stdio.h> #include <stdlib.h> struct node { int number; struct node *next; }; struct node *addnode(int number,struct node *next); struct node*mergesort(struct node *head); struct node *merge(struct node *one,struct node *two); int main(void){ struct node

This is my code, when I enter a very large number I get stack overflow error does anyone know why? When i enter a very large number i get that error and im not really sure what is causing it, it is only with large numbers small ones work fine..... // // merge two sorted lists into one: // let rec merge L1 L2 = if L1 = [] && L2 = [] then [] else if L1 = [] then L2 else if L2 = [] then L1 else if L1.Head <= L2.Head then L1.Head :: merge L1.Tail L2 else L2.Head :: merge L1 L2.Tail // // mergesort: // let rec mergesort L = match L with | [] -> [] | E::[] -> L | _ -> let mid = List.length L / 2 let

I have a custom type Position(x,y,z) ,now I create a ArrayList<Position> , i want to sort this array ordered by the value of z, from small to bigger,how can i do that using Collections.sort or is there any other efficient sorting method? When I try to use public class PositionComparator implements Comparator<Position> { @Override public int compare(Position o1, Position o2) { // TODO Auto-generated method stub return o1.height().compareTo(o2.height()); } } get an error Cannot invoke compareTo(double) on the primitive type double try Collections.sort(SortList, new Comparator<Position>(){ public

I'm having some troubles understanding this behaviour. I'm measuring the execution time with the timeit-module and get the following results for 10000 cycles: Merge : 1.22722930395 Bubble: 0.810706578175 Select: 0.469924766812 This is my code for MergeSort: def mergeSort(array): if len(array) <= 1: return array else: left = array[:len(array)/2] right = array[len(array)/2:] return merge(mergeSort(left),mergeSort(right)) def merge(array1,array2): merged_array=[] while len(array1) > 0 or len(array2) > 0: if array2 and not array1: merged_array.append(array2.pop(0)) elif (array1 and not array2) or