memory-address

Get address of base object from derived object

谁说我不能喝 提交于 2020-01-01 19:19:33
问题 I'm getting a very confusing error in my program. I think I may have two different objects of the same class where I thought I had the same object. It is confusing because I am dealing with a very large framework where it is not simple to obtain a pointer to the object I need. My question is, if I have a class Derived which in inherits from Base, and I have a pointer to a Derived object, how can I get the address of the Base object from the derived object? I am working with the source code of

Keeping address in C++ hacking game code? [closed]

对着背影说爱祢 提交于 2019-12-31 01:06:32
问题 Closed . This question needs to be more focused. It is not currently accepting answers. Want to improve this question? Update the question so it focuses on one problem only by editing this post. Closed 2 years ago . I have this code that edits addresses in a game to get unlimited ammo and what not, and I found out that the addresses are different for every computer, sometimes every time you restart the game, so how would I manage making this work still even though they change. 回答1: If you get

Why C++ would not print the memory address of a char but will print int or bool? [duplicate]

那年仲夏 提交于 2019-12-30 05:58:32
问题 This question already has answers here : Closed 7 years ago . Possible Duplicate: Why is address of char data not displayed? Here is the code and the output: int main(int argc, char** argv) { bool a; bool b; cout<<"Address of a:"<<&a<<endl; cout<<"Address of b:"<<&b<<endl; int c; int d; cout<<"Address of c:"<<&c<<endl; cout<<"Address of d:"<<&d<<endl; char e; cout<<"Address of e:"<<&e<<endl; return 0; } The output: Address of a:0x28ac67 Address of b:0x28ac66 Address of c:0x28ac60 Address of d

C++ - Get value of a particular memory address

六月ゝ 毕业季﹏ 提交于 2019-12-28 05:55:08
问题 I was wondering whether it is possible to do something like this: unsigned int address = 0x0001FBDC; // Random address :P int value = *address; // Dereference of address Meaning, is it possible to get the value of a particular address in memory ? Thanks 回答1: You can and should write it like this: #include <cstdint> uintptr_t p = 0x0001FBDC; int value = *reinterpret_cast<int *>(p); Note that unless there is some guarantee that p points to an integer, this is undefined behaviour. A standard

Why does Go forbid taking the address of (&) map member, yet allows (&) slice element?

三世轮回 提交于 2019-12-28 05:21:53
问题 Go doesn't allow taking the address of a map member: // if I do this: p := &mm["abc"] // Syntax Error - cannot take the address of mm["abc"] The rationale is that if Go allows taking this address, when the map backstore grows or shinks, the address can become invalid, confusing the user. But Go slice gets relocated when it outgrows its capacity, yet, Go allows us to take the address of a slice element: a := make([]Test, 5) a[0] = Test{1, "dsfds"} a[1] = Test{2, "sdfd"} a[2] = Test{3, "dsf"}

content on particular memory address is different than was expected in gdb

人盡茶涼 提交于 2019-12-25 03:12:39
问题 I have variable i of type int which value is 129. I have played with various representations of this variable in gdb. # Decimal format of i (gdb) p/d i $18 = 129 # Binary format of i (gdb) p/t i $19 = 10000001 # Address of variable i (gdb) p &i $20 = (int *) 0xbffff320 # Binary format displayed at one byte (gdb) x /tb &i 0xbffff320: 10000001 # Decimal format displayed at four bytes (one word) (gdb) x /dw &i 0xbffff320: 129 # Decimal format displayed at one byte (gdb) x /db &i 0xbffff320: -127

print 64bit c++ full memory address

旧街凉风 提交于 2019-12-24 23:37:45
问题 While I was writing code on a 64 bit machine for a c++ program,I noticed that printing the address of a variable (for example) returns just 12 hexadecimal characters, instead of 16. Here's an example code: int a = 3 ; cout sizeof(&a) << " bytes" << endl ; cout << &a << endl ; The output is: 8 bytes 0x7fff007bcce0 Obviously, the address of a variable is 8 byte (64 bit system). But when I print it, I get only 12 hexadecimal digits instead of 16. Why this? I think that is due to the fact that

VB.Net Get Offset Address

故事扮演 提交于 2019-12-24 10:23:34
问题 In VB.Net I open a file with BinaryReader.. I need to find on the file for some Hex values and if they are found, it return the offset address of the first Byte.. It is possible? and how can achieve this? Thank you EDIT: My current code: Private Function findOffset() Using reader As New BinaryReader(File.Open(filename, FileMode.Open)) ' Loop through length of file. Dim pos As Integer = 0 ' <== THIS IS THE OFFSET Dim length As Integer = reader.BaseStream.Length Do While pos < length ' Read the

Interact with a STM32 chip's memory in C [closed]

拈花ヽ惹草 提交于 2019-12-24 08:55:50
问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 2 years ago . I would like to interact with a STM32 chip's memory , STM32L476, first to read and store its electronic signature (MCU_ID) and then to write data in its memory . I am using a STM32QFP64 socket linked to a JTAG ST-LINK. I am quite good in C but really beginning embedded programming so I chose Atollic Studio IDE

What is the difference between *p and (*p)[3] in the function?

混江龙づ霸主 提交于 2019-12-24 08:38:56
问题 I'm new in programming and learning pointers in array in C. Have a look at the below programmes. 1st program #include<stdio.h> int fun(); int main() { int num[3][3]={21,325,524,52,0,6514,61,33,85}; fun(num); printf("%d",*(*(num+1)+1)); *(*(num+1)+1)=0; printf("%d",*(*(num+1)+1)); return 0; } int fun(int **p) { *(*(p+1)+1)=2135; return 0; } 2nd program #include<stdio.h> int fun(); int main() { int num[3][3]={21,325,524,52,0,6514,61,33,85}; fun(num); printf("%d",*(*(num+1)+1)); *(*(num+1)+1)=0;