memory-address

I'm getting a very confusing error in my program. I think I may have two different objects of the same class where I thought I had the same object. It is confusing because I am dealing with a very large framework where it is not simple to obtain a pointer to the object I need. My question is, if I have a class Derived which in inherits from Base, and I have a pointer to a Derived object, how can I get the address of the Base object from the derived object? I am working with the source code of the Base Class and am printing out the address of "this" in Base. In another part of my code a

I'm working on a question where I am to examine values and address before and after a fork() call in C. My approach was to display the variables values and address assuming to see a difference in the address after the fork() . Much to my surprise address's for said variables remained the same. My questions is why are they the same? What happens if I change a variable in the child? Will it change in both parent and child? If not, how am I able to change the value in that address while the address is the same for both parent and child. code(for reference): #include <stdio.h> #include <stdlib.h>

In C++, is the address of a reference to a dereferenced pointer guaranteed to be the same as the address of the pointer? Or, written in code, is the following assertion guaranteed to always hold true? SomeType *ptr = someAddress; SomeType &ref = *ptr; assert(&ref == ptr); Yes, that is correct and will always be true. Reference is nothing but an Alias of the type which it is referring to. It does not have a separate existence, it is always tied up to the one it is referring. Yes, provided of course that someAddress is not a null pointer, or otherwise not allowed to be dereferenced. In that case

Possible Duplicate: Why is address of char data not displayed? Here is the code and the output: int main(int argc, char** argv) { bool a; bool b; cout<<"Address of a:"<<&a<<endl; cout<<"Address of b:"<<&b<<endl; int c; int d; cout<<"Address of c:"<<&c<<endl; cout<<"Address of d:"<<&d<<endl; char e; cout<<"Address of e:"<<&e<<endl; return 0; } The output: Address of a:0x28ac67 Address of b:0x28ac66 Address of c:0x28ac60 Address of d:0x28ac5c Address of e: My question is: Where is the memory address of the char? And why is it not printed? Thank you. I suspect that the overloaded-to- char *

I tried to print the address of each character of std::string . But I amn't understanding what is happening internally with std::string that is resulting this output while for the array it is giving the address as I expected. Could someone please explain what is going on? #include <iostream> #include <string> using namespace std; int main(){ string str = "Hello"; int a[] = {1,2,3,4,5}; for( int i=0; i<str.length(); ++i ) cout << &str[i] << endl; cout << "**************" << endl; for( int i=0; i<5; ++i ) cout << &a[i] << endl; return 0; } Output: Hello ello llo lo o **************