member

Why protected superclass member cannot be accessed in a subclass function when passed as an argument?

北城以北 提交于 2019-12-01 14:06:02
问题 I get a compile error, which I'm slightly confused about. This is on VS2003. error C2248: 'A::y' : cannot access protected member declared in class 'A' class A { public: A() : x(0), y(0) {} protected: int x; int y; }; class B : public A { public: B() : A(), z(0) {} B(const A& item) : A(), z(1) { x = item.y;} private: int z; }; The problem is with x = item.y; The access is specified as protected. Why doesn't the constructor of class B have access to A::y? 回答1: It's because of this: class base

Export ExpressionEngine members to WordPress

喜你入骨 提交于 2019-12-01 13:19:42
问题 I need to export all members from an ExpressionEngine site over to WordPress. How would I go about this? It seems like a daunting task to move them all over, including all their password etc. Any ideas on how to get started? It's fine if the users have to reset their password on logging into the new WordPress site if that's the case. I just can't get my head around it all... 回答1: Here's a query that will give you results which use the column names and formats that you need for your wp_users

How to check with SFINAE if a member exists, without knowing the member's type?

对着背影说爱祢 提交于 2019-12-01 06:23:22
In pre-C++11 code, if I'm looking for a member variable whose type I don't know, how can I use SFINAE to check if the member exists? Here's an example using Member detector idiom that you asked for: template<typename T> struct has_x { typedef char(&yes)[1]; typedef char(&no)[2]; // this creates an ambiguous &Derived::x if T has got member x struct Fallback { char x; }; struct Derived : T, Fallback { }; template<typename U, U> struct Check; template<typename U> static no test(Check<char Fallback::*, &U::x>*); template<typename U> static yes test(...); static const bool value = sizeof(test

How to set a login cookie in django?

醉酒当歌 提交于 2019-12-01 02:34:00
How do I set_cookie with the username of the member that is logged in to my site? Thanks you can implement this by using the session middleware , make sure to enable it in your project. I recommend you to use django.contrib.auth to manage sessions though. It manages sessions in the database which is a lot safer than just saving the username in a cookie Here is an example of how to do it using middleware class UserCookieMiddleWare(object): """ Middleware to set user cookie If user is authenticated and there is no cookie, set the cookie, If the user is not authenticated and the cookie remains,

Hold any kind of C++ template class in member variable

孤人 提交于 2019-11-30 20:27:50
I have got two classes. The first class (A) is builded with an template. template <class T> class A { public: T value; }; The second class (B) should have an object of class A as member variable. Like this: class B { public: A<int> value; }; But now i want to use any kind of template-class in class A. Not only int . Apparent I can't declare a (member-)variable which contains any kind of a class. So, I need something like this: class B { public: A<*> value; }; Is there any (clean) solution for this problem? -- Greeting from Germany, Bastian You cannot have a single class B with "any" member

invalid use of non-static member function [duplicate]

本小妞迷上赌 提交于 2019-11-30 17:15:55
This question already has an answer here: problem sorting using member function as comparator 7 answers I have something like this: class Bar { public: pair<string,string> one; std::vector<string> cars; Bar(string one, string two, string car); }; class Car { public: string rz; Bar* owner; Car(string car, Bar* p); }; class Foo { public: Foo ( void ); ~Foo ( void ); int Count ( const string & one, const string & two) const; int comparator (const Bar & first, const Bar & second) const; std::vector<Bar> bars; }; int Foo::comparator(const Bar & first, const Bar & second) const{ return first.name <

pointer to const member function typedef

别来无恙 提交于 2019-11-30 16:27:44
问题 I know it's possible to separate to create a pointer to member function like this struct K { void func() {} }; typedef void FuncType(); typedef FuncType K::* MemFuncType; MemFuncType pF = &K::func; Is there similar way to construct a pointer to a const function? I've tried adding const in various places with no success. I've played around with gcc some and if you do template deduction on something like template <typename Sig, typename Klass> void deduce(Sig Klass::*); It will show Sig with as

Iterating through the Object Browser in VBA

久未见 提交于 2019-11-30 15:53:18
问题 I would like to iterate through members of any class in a referenced library much like is done using the Object Browser. How can this be done using VBA? 回答1: Actually, how to do this is undocumented, but is possible. If your looking to implement a for..Each syntax for a collection, then you can do the following: Option Compare Database Option Explicit Public colT As New Collection Public Function NewEnum() As IUnknown Set NewEnum = colT.[_NewEnum] End Function Public Property Get NextItem()

Iterating through the Object Browser in VBA

不羁的心 提交于 2019-11-30 15:40:11
I would like to iterate through members of any class in a referenced library much like is done using the Object Browser. How can this be done using VBA? Actually, how to do this is undocumented, but is possible. If your looking to implement a for..Each syntax for a collection, then you can do the following: Option Compare Database Option Explicit Public colT As New Collection Public Function NewEnum() As IUnknown Set NewEnum = colT.[_NewEnum] End Function Public Property Get NextItem() As IUnknown Attribute NextItem.VB_UserMemId = -4 Attribute NextItem.VB_MemberFlags = "40" Set NextItem = colT

pointer to const member function typedef

|▌冷眼眸甩不掉的悲伤 提交于 2019-11-30 10:58:44
I know it's possible to separate to create a pointer to member function like this struct K { void func() {} }; typedef void FuncType(); typedef FuncType K::* MemFuncType; MemFuncType pF = &K::func; Is there similar way to construct a pointer to a const function? I've tried adding const in various places with no success. I've played around with gcc some and if you do template deduction on something like template <typename Sig, typename Klass> void deduce(Sig Klass::*); It will show Sig with as a function signature with const just tacked on the end. If to do this in code it will complain that