member

I'm querying for the ID of a field by accessing a class function which someone has already put in place. The result is a object returned with protected member variables. I'm struggling to see how I can access the member variable values outside the class. Just add a "get" method to the class. class Foo { protected $bar = 'Hello World!'; public function getBar() { return $this->bar; } } $baz = new Foo(); echo $baz->getBar(); Pawka Accessing protected or private variables from public is incorrect (thats why they are protected or private). So better is to extend class and access required property

I'm trying to print the second member variable of all items in an stl map using a lambda expression map<int, int> theMap; for_each(theMap.begin(), theMap.end(), cout << bind(&pair<int, int>::second, _1) << constant(" ")); but this is not compiling. I essentially want to de-reference the placeholder. Any idea what I'm missing here? Thanks in advance! std::map will add const to its key; this is to prevent messing up the ordering. Your pair should be: std::pair<const int, int> Like dirkgently suggests, use the value_type to always get the correct type. The verbosity is alleviated with a typedef:

经典的问题（上） 当程序中存在多个对象的时候，如何确定这些对象的析构顺序？ 关于析构的疑问 单个对象 创建时 构造函数的调用顺序 1. 调用 父类的构造过程 （后续再说） 2. 调用 成员变量的构造函数 （调用顺序与声明顺序相同）---------有可能某个类，它里面的成员是其他类的对象。此时就调用成员变量的构造函数。 3. 调用 类自身 的构造函数 析构函数与对应构造函数的调用顺序相反 多个对象析构时 同样遵循 析构顺序与构造顺序相反 实例分析 构造与析构顺序 #include <stdio.h> class Member { const char* ms; public: Member(const char* s) { printf("Member(const char* s): %s\n", s); ms = s; } ~Member() { printf("~Member(): %s\n", ms); } }; class Test { Member mA; Member mB; public: Test() : mB("mB"), mA("mA") { printf("Test()\n"); } ~Test() { printf("~Test()\n"); } }; Member gA("gA"); int main() { Test t; return 0; }

I am developing a web application using Java/JSP. One class, say Student, has a static member static private int _nextID; I want to know, if this _nextID is the same among all user sessions? Or each session has its own _nextID? andersoj In the simple case , you can assume that multiple instances of Student will share the same static nextID field. However, one should think beyond the simple case (or document that you haven't). In this case, it's fine unless the instance id fields derived from the nextID counter propagate out into a larger application where the IDs are meant to be unique. In

In C++14, since constexpr are not implicitly const anymore, can a constexpr member function modify a data member of a class: struct myclass { int member; constexpr myclass(int input): member(input) {} constexpr void f() {member = 42;} // Is it allowed? }; Yes they are, I believe this change started with proposal N3598: constexpr member functions and implicit const and eventually became part of N3652: Relaxing constraints on constexpr functions which changed section 7.1.5 paragraph 3 what is allowed in the function body from a white-list: its function-body shall be = delete, = default, or a

I want to access a private data member in a class. There is no member function in the class to access the private data member. It is private. I want to take the class and some how crack it open. One method was to copy the declaration of the class, make the private member public and call the new class class something_else. Then I do a reinterpret cast and copy the original object. This works. But I want something more elegant ... or perhaps generic ... or just another way. What options are there? Can I use void*? Can I memcpy the class into another empty class? What are ways to do this?? % I am