maze

In an attempt to write a brute force maze solving C program, I've written this java program first to test an idea. I'm very new to C and intend to convert it after getting this right in java. As a result, I'm trying stick away from arraylists, fancy libraries, and such to make it easier to convert to C. The program needs to generate a single width path of shortest steps to solve a maze. I think my problem may be in fragmenting a path-storing array passed through each recursion. Thanks for looking at this. -Joe maze: 1 3 3 3 3 3 3 3 3 3 3 0 0 0 3 3 0 3 3 3 0 3 3 3 2 Same maze solved by this

I'm having trouble figuring out how exactly to get this to work... I'm attempting to get the shortest path to the goal using a DFS. I know that BFS is better but I was asked to use DFS for this. As you can see, I attempt to make a comparison between all stacks that lead to the end to find the goal, but it does not work, only the first stack that leads to the goal is ever printed... I know somewhere I need to unvisit nodes, but I cannot figure out exactly how. Right now I do get a path to the goal, but not the shortest one. Any help with this would be greatly appreciated. Writing a non

I want to generate a maze that looks like this: That is, it consists of paths in one direction that are then connected. I have looked for an algorithm to generate mazes like this without success. Specifically, I don't want a maze like this: because it doesn't "run" in only one direction. Also, it would be nice if the solution of this maze required the player to "backtrack" -- i.e. not just move upwards all the time. create a random path between point A and B randomly add walls as long as it doesn't lie on the path until you're satisfied Well that was fun! Complete with ASCII art output I

I am trying to make a maze solver, and it is working except that instead of the path being marked by "o" I want it to be marked with ">", "<", "v", "^" depending on the direction of the path. This is the part of the code where it solves the maze: def solve(self,x,y): maze = self.maze #Base case if y > len(maze) or x > len(maze[y]): return False if maze[y][x] == "E": return True if maze[y][x] != " ": return False #marking maze[y][x] = "o" #recursive case if self.solve(x+1,y) == True : #right return True if self.solve(x,y+1) == True : #down return True if self.solve(x-1,y) == True : #left return

This question already has an answer here: Programming theory: Solve a maze 14 answers The maze is defined as a square matrix. For example: int maze[N][N] = { { 1, 1, 1, 1, 1, 1, 1 }, { 0, 1, 0, 1, 0, 0, 1 }, { 0, 1, 0, 1, 1, 1, 1 }, { 0, 1, 0, 0, 0, 1, 1 }, { 0, 1, 1, 1, 0, 1, 1 }, { 0, 0, 1, 0, 1, 1, 1 }, { 1, 1, 1, 1, 0, 1, 1 } }; You can walk only where there's a 1. You can take a step down, up, left, right. You start at the top-left corner and finish at down-right corner. The output should be the minimum steps to finish any maze. We can assume there is at least one way to finish the maze.

Which algorithm can be used to generate a maze with more than one successful path and if algorithm is modified version of some well known algorithm then explain or add a link . I am using 2D array A to store configuration of maze . Assume if the size of maze is n * n then more than one path should be there from A[0][0] to A[n-1][n-1] . This algorithms should be able to generate mazes with distinct loop-free paths from start to goal: Starting with an empty maze (or a solid block of rock), with just the start and the goal... Subdivide the maze into three sets: Start (intially holding just the

This question already has an answer here: Why does foo.append(bar) affect all elements in a list of lists? [duplicate] 3 answers I seem to have a problem with my maze generating program made in Python. I'm trying to randomly create a path that branches out at select points, with the points getting stored as it goes along. When the maze gets to a dead end, it will sort back through the visited points by testing the top value than popping that and going to the next one, until it gets to a spot where it isn't a dead end. However, when I try to append items to the list I'm using to save the spaces