maze

I want to implement a maze solving algorithm in Prolog. Therefore i searched for some maze solving algorithms and found the following: http://www.cs.bu.edu/teaching/alg/maze/ FIND-PATH(x, y): if (x,y outside maze) return false if (x,y is goal) return true if (x,y not open) return false mark x,y as part of solution path if (FIND-PATH(North of x,y) == true) return true if (FIND-PATH(East of x,y) == true) return true if (FIND-PATH(South of x,y) == true) return true if (FIND-PATH(West of x,y) == true) return true unmark x,y as part of solution path return false I already build a matrix in prolog,

I'm basing a maze generator program on the Prim's algorithm: This algorithm is a randomized version of Prim's algorithm. Start with a grid full of walls. Pick a cell, mark it as part of the maze. Add the walls of the cell to the wall list. While there are walls in the list: Pick a random wall from the list. If the cell on the opposite side isn't in the maze yet: Make the wall a passage and mark the cell on the opposite side as part of the maze. Add the neighboring walls of the cell to the wall list. If the cell on the opposite side already was in the maze, remove the wall from the list. (from

I know we can use DFS for maze exploration. But I think we can also use BFS for maze exploration. I'm little bit confused here because most of the books and articles that I've read had used DFS for this problem. What I think is that the Best Case time complexity of DFS will be better as compared to BFS. But Average and Worst Case time complexity will be same for both BFS & DFS and thats why we prefer DFS over BFS. Am I right or I'm having some misconception They have similar running time , but either may greatly outperform the other on any given problem simply due to the order in which the

(This is not a duplicate) We have a 2D maze surrounded by X on all 4 sides and there are inner blocks too. All these characters of the maze is stored in 2D array. The program must find the path from start 'S' to goal 'G'. For this, a boolean method called 'solve(int row, int col) is uses and is initialized with row and column index of 'S'. The algorithm must be recursive. It should return true if its able to find the path to 'G' and false other wise. Here's how I tried to approach this problem which shows "partial correct result". public boolean solve(int row, int col) { char right = this

I am working or understanding how to create a simple java 2d maze that should look like this: int [][] maze = { {1,1,1,1,1,1,1,1,1,1,1,1,1}, {1,0,1,0,1,0,1,0,0,0,0,0,1}, {1,0,1,0,0,0,1,0,1,1,1,0,1}, {1,0,0,0,1,1,1,0,0,0,0,0,1}, {1,0,1,0,0,0,0,0,1,1,1,0,1}, {1,0,1,0,1,1,1,0,1,0,0,0,1}, {1,0,1,0,1,0,0,0,1,1,1,0,1}, {1,0,1,0,1,1,1,0,1,0,1,0,1}, {1,0,0,0,0,0,0,0,0,0,1,0,1}, {1,1,1,1,1,1,1,1,1,1,1,1,1} }; Ones this has been created the idea is to set a starting point and goal point and by using recursive depth first find the path. but must say i am having difficulties to create the maze. Do you

What is the algorithm for generating the maze in the game Netwalk ? The source code is available at Google Code, so you can read it for yourself and find out! The maze is generated by the function generate_maze in game.c , lines 78ff. Update: try the demo! Netwalk generates a maze by running a randomized version of Prim's algorithm to find a minimum spanning tree . Prim's algorithm iteratively grows a tree once branch at a time, starting from a source node (or nodes: in this case, the "server", the dark blue double-height box). At any given point in the running of the algorithm, the data

I am trying to implement a randomly generated maze using Prim's algorithm. I want my maze to look like this: however the mazes that I am generating from my program look like this: I'm currently stuck on correctly implementing the steps highlighted in bold: Start with a grid full of walls. Pick a cell, mark it as part of the maze. Add the walls of the cell to the wall list. While there are walls in the list: **1. Pick a random wall from the list. If the cell on the opposite side isn't in the maze yet: Make the wall a passage and mark the cell on the opposite side as part of the maze.** Add the

//finder.h #ifndef FINDER_H #define FINDER_H #include <QStack> struct Position { int x ; int y ; Position ( int x = 0 , int y = 0 ) { this -> x = x ; this -> y = y ; } } ; struct StackElem { Position pos ; int direction ; } ; class Finder { public : Finder (); bool findPath ( int maze [][ 10 ], Position startpoint , Position endpoint ); void nextPos ( Position * p_pos , StackElem pm ); bool pass ( int maze [][ 10 ] , Position curpos ); void footPrint ( int maze [][ 10 ] , Position curpos ); void setElem ( Position pos , int direction , StackElem * p_e ); void markprint ( int maze [][ 10 ] ,