matrix-multiplication

matrix multiplication using Mpi_Scatter and Mpi_Gather

巧了我就是萌 提交于 2019-12-01 11:04:19
I newbie to mpi programming. I was trying to write matrix multiplication. Went through the post MPI Matrix Multiplication with scatter gather about matrix multiplication using scatter and gather routine. I tried modifying the code available on above post as below... #define N 4 #include <stdio.h> #include <math.h> #include <sys/time.h> #include <stdlib.h> #include <stddef.h> #include "mpi.h" void print_results(char *prompt, int a[N][N]); int main(int argc, char *argv[]) { int i, j, k, rank, size, tag = 99, blksz, sum = 0; int a[N][N]={{1,2,3,4},{5,6,7,8},{9,1,2,3},{4,5,6,7,}}; int b[N][N]={{1

Numpy tensor: Tensordot over frontal slices of tensor

守給你的承諾、 提交于 2019-12-01 10:15:56
问题 I'm trying to perform a matrix multiplication with frontal slices of a 3D tensor, shown below. If X.shape == (N, N) , and Y.shape == (N, N, Y) , the resulting tensor should be of shape (N, N, Y) . What's the proper np.tensordot syntax to achieve this? I'm trying to limit myself to np.tensordot , and not np.einsum , because I want to later translate this solution to Theano. Unfortunately, Theano does not have np.einsum implemented yet. Graphics adapted from this paper about tensor

Matrix Multiplication CUDA

痴心易碎 提交于 2019-12-01 05:34:38
问题 I have been reading through several websites and even used NVIDA's code as a guide but I am still getting the wrong answer. The main will ask the user for size, and will display A and B then display the resulting matrix C. However say I run a 2x2 matrix for both A and B this is my sample output: Matrix A 0.000000 8.000000 2.000000 2.000000 Matrix B 3.000000 1.000000 5.000000 7.000000 Matrix C (Results) 0.000000 9.000000 7.000000 4.000000 But that's incorrect. It should be: 40.000 56.000 16

Multiplying values from two different dictionaries together in Python

我的未来我决定 提交于 2019-12-01 05:24:16
I have two separate dictionaries with keys and values that I would like to multiply together. The values should be multiplied just by the keys that they have. i.e. dict1 = {'a': 1, 'b': 2, 'c': 3} dict2 = {'a': 15, 'b': 10, 'd': 17} dict3 = dict.items() * dict.items() print dict3 #### #dict3 should equal {'a': 15, 'b': 20} If anyone could help, that would be great. Thanks! You can use a dict comprehension : >>> {k : v * dict2[k] for k, v in dict1.items() if k in dict2} {'a': 15, 'b': 20} Or, in pre-2.7 Python, the dict constructor in combination with a generator expression : >>> dict((k, v *

Matrix multiplication time complexity in MATLAB

人走茶凉 提交于 2019-12-01 05:20:35
Does anyone know which algorithm MATLAB uses for matrix multiplication and what is its time complexity? For completeness -- as mentioned in this thread , Matlab uses the DGEMM (Double GEneral Matrix Multiplication) routine from BLAS (Basic Linear Algebra Subprograms). Note that there is not one single implementation of BLAS - it is tuned for particular processor architectures. Therefore you cannot be absolutely certain which algorithm is being used on your machine without finding out which version of BLAS is in use. The specification for BLAS specifies the inputs and output of each subroutine,

How to just calculate the diagonal of a matrix product in R

生来就可爱ヽ(ⅴ<●) 提交于 2019-12-01 05:13:11
I have two matrix A and B , so what's the fastest way to just calculate diag(A%*%B) , i.e., the inner-product of the ith row of A and ith column of B , and the inner-product of other terms are not concerned . supplement: A and B have large row and column numbers respectively. This can be done without full matrix multiplication, using just multiplication of matrix elements. We need to multiply rows of A by the matching columns of B and sum the elements. Rows of A are columns of t(A) , which we multiply element-wise by B and sum the columns. In other words: colSums(t(A) * B) Testing the code we

Large matrix multiplication on gpu

孤街浪徒 提交于 2019-12-01 04:02:34
I need to implement a matrix multiplication on GPU with CUDA for large matrices. Size of each matrix alone is bigger than the GPU memory. So I think I need an algorithm to do that efficiently. I went around the internet but couldn't find any. Can anyone give me the name or link of such algorithms. Thank you talonmies There isn't really a formal algorithm for this; in general, these sorts of linear algebra operations where the whole problem isn't stored in memory simultaneously are referred to as "out of core" operations. To solve it, you don't need a particularly elaborate algorithm, just the

How to just calculate the diagonal of a matrix product in R

别等时光非礼了梦想. 提交于 2019-12-01 01:32:51
问题 I have two matrix A and B , so what's the fastest way to just calculate diag(A%*%B) , i.e., the inner-product of the ith row of A and ith column of B , and the inner-product of other terms are not concerned . supplement: A and B have large row and column numbers respectively. 回答1: This can be done without full matrix multiplication, using just multiplication of matrix elements. We need to multiply rows of A by the matching columns of B and sum the elements. Rows of A are columns of t(A) ,

Google Cloud: matrix multiplication with Bigquery or some other service?

烈酒焚心 提交于 2019-12-01 01:23:20
I am using Google Analytics and processing the data with Bigquery, I need to do a matrix multiplication . What is the most feasible way of implementing matrix multiplication in Google Cloud? Can it be done directly in Bigquery? Assuming MatrixA is a table with below columns: i, k, value and MatrixB - has schema as k, j, value and also assuming that range of k-values is the same in both tables: This would mimic below matrices : Matrix A 2 -3 4 -1 0 2 Matrix B -1 2 3 0 1 7 1 1 -2 Below code for multiplication is for BigQuery Standard SQL #standardSQL WITH MatrixA AS ( SELECT 1 AS i, 1 AS k, 2 AS

Large matrix multiplication on gpu

混江龙づ霸主 提交于 2019-12-01 01:12:45
问题 I need to implement a matrix multiplication on GPU with CUDA for large matrices. Size of each matrix alone is bigger than the GPU memory. So I think I need an algorithm to do that efficiently. I went around the internet but couldn't find any. Can anyone give me the name or link of such algorithms. Thank you 回答1: There isn't really a formal algorithm for this; in general, these sorts of linear algebra operations where the whole problem isn't stored in memory simultaneously are referred to as