matplotlib

问题 I recently reinstalled anaconda to shift the directory over from an admin account to my personal account. Previously, I had no issue with the code below import matplotlib.backends.backend_tkagg as tkagg defaultcursor = tkagg.cursord[1] Now, it gives the following error: AttributeError: module 'matplotlib.backends.backend_tkagg' has no attribute 'cursord' any idea why this is happening? 来源： https://stackoverflow.com/questions/54002098/attributeerror-tkagg-has-no-attribute-cursord

问题 I want to align my y-axis labels like in this example. However, I don't want to use a fixed value like ax4.yaxis.set_label_coords(labelx, 0.5) , but rather something like this: x = np.linspace(-np.pi, np.pi, 100) y1 = np.sin(x)**2 y2 = np.sin(x) fig, (ax1, ax2) = plt.subplots(2, 1, sharex=True) ax1.plot(x, y1) ax2.plot(x, y2) ax1.set_ylabel('y1') ax2.set_ylabel('y2') The position of the lower label is "correct". I want to determine its x-coordinate and apply it to the upper label. How do I do

问题 I want to align my y-axis labels like in this example. However, I don't want to use a fixed value like ax4.yaxis.set_label_coords(labelx, 0.5) , but rather something like this: x = np.linspace(-np.pi, np.pi, 100) y1 = np.sin(x)**2 y2 = np.sin(x) fig, (ax1, ax2) = plt.subplots(2, 1, sharex=True) ax1.plot(x, y1) ax2.plot(x, y2) ax1.set_ylabel('y1') ax2.set_ylabel('y2') The position of the lower label is "correct". I want to determine its x-coordinate and apply it to the upper label. How do I do

问题 I installed Anaconda to simplify the management of many python modules. After that i tried to "import subprocess": >>> import subprocess Traceback (most recent call last): File "<stdin>", line 1, in <module> File "/home/sej/.config/anaconda3/lib/python3.6/subprocess.py", line 155, in <module> _PopenSelector = selectors.SelectSelector AttributeError: module 'selectors' has no attribute 'SelectSelector' How to fix this? I came accross this problem by trying to use matplotlib. When trying to

问题 Below is a working example where I need to draw regression line. I have searched online but I see another function like regplot, implot to draw regression lines but here I am using replot. How I can draw regression line using relplot? from matplotlib import pyplot as plt import pandas as pd import seaborn as sns d = {'x-axis':[100,915,298,299], 'y-axis': [1515,1450,1313,1315], 'text':['point1','point2','point3','point4']} df = pd.DataFrame(d) p1 = sns.relplot(x='x-axis', y='y-axis',data=df )

问题 I've got an interesting application that requires transforming 3D polar data (angle, distance, and value at that point) into images representing the data. It's NOAA NEXRAD radar data that I'm using in a custom application. The data is stored in 3 arrays, range_data (the distance from the radar in meters, 1800 points), azimuth_data (the angle in 0.5 degree steps, 720 points), and radar_data (a 720x1800 array containing a data value for each combination of range and azimuth). This is the format

问题 I've got an interesting application that requires transforming 3D polar data (angle, distance, and value at that point) into images representing the data. It's NOAA NEXRAD radar data that I'm using in a custom application. The data is stored in 3 arrays, range_data (the distance from the radar in meters, 1800 points), azimuth_data (the angle in 0.5 degree steps, 720 points), and radar_data (a 720x1800 array containing a data value for each combination of range and azimuth). This is the format

问题 Problem: I have a tkinter window with a matplotlib graph showing some lines (part of a much larger program). Periodically I add a new line, deleting an oldest one to limit the number of lines shown. Unfortunately the program grows in size continuously. I've seen this on both Windows and Linux. Question: How should I write a long-running graph frame to show the last n lines which doesn't use up all my memory? Preferably by tweaking the code below, but I'm prepared for a complete re-write if

问题 Problem: I have a tkinter window with a matplotlib graph showing some lines (part of a much larger program). Periodically I add a new line, deleting an oldest one to limit the number of lines shown. Unfortunately the program grows in size continuously. I've seen this on both Windows and Linux. Question: How should I write a long-running graph frame to show the last n lines which doesn't use up all my memory? Preferably by tweaking the code below, but I'm prepared for a complete re-write if

问题 I am plotting various correlation matrices with a different number of columns using seaborn. For the sake of eye-candy, I'd like to have all correlation matrices to have the same cell size. Unfortunately, I am not able to parameterize seaborn to do so. Here is a minimal example: from string import ascii_letters import numpy as np import pandas as pd import seaborn as sns import matplotlib.pyplot as plt # Generate two random dataset rs = np.random.RandomState(42) d1 = pd.DataFrame(data=rs