matching

here is my code: function check i1=imread('cricketteam.jpg'); [y,x,d]=size(i1); m=imread('musfiq.jpg'); [y1,x1,d]=size(m); x2=1; y2=1; row_match=0; flag_y=0; cx=1; xc=1; xc1=1; counter=0; counter1=0; s_loop=x-x1; k=0; s_loop= s_loop+1; for i=1:y cx=xc; for j=cx:x disp(i) disp(j) counter1=counter1+1; if j==s_loop && row_match==0 break; end f=impixel(m,x2,y2); disp(f) ma=impixel(i1,j,i); disp(ma) d=[155 165 128]; if ma==d k=1; end if isequal(f,ma)==1 disp('Image Matched') if row_match == 0 xc=cx; end row_match=row_match+1; x2=x2+1; else flag_y=0; row_match=0; y2=1; x2=1; end if row_match==x1

I have the following set data in Sheet1 and start from row 4 column A where the header in row 3: No Date Code Name Remarks D e b i t Cr e d i t 1 4/30/2015 004/AB/01/04/15 Anna YES 40239.66 0.00 2 2/16/2015 028/AA/01/02/15 Andy NO 0.00 2205.49 3 1/31/2015 021/DR/04/01/15 Jim YES 167.60 0.00 4 7/14/2015 083/RF/01/07/15 Anna YES 3822.60 0.00 5 8/6/2015 030/AB/01/08/15 Anna NO 0.00 11267.96 6 1/15/2015 020/TY/01/01/15 Barry 0.00 5237.84 7 7/14/2015 024/HU/01/07/15 Anna NO 0.00 3822.60 8 1/31/2015 039/JK/01/01/15 YES 0.00 1780.84 9 1/27/2015 007/ER/01/01/15 Jim NO 5237.84 0.00 10 4/29/2015 077/FX

I have a larger data frame (~50K rows and 50 to 75 columns) that has a small number of row that are duplicated in, say, 7 of the 75 columns. Although it's simple enough to locate rows that duplicate rows above using duplicated(...) , I want to be able to pull out the duplicated rows and the row that is duplicated, or if (stolen from an earlier post) a <- c(rep("A", 3), rep("B", 3), rep("C",2)) b <- c(1,1,2,4,1,1,2,2) d <- c('x','y','x','z','y','y','z','x') df <- data.frame(a,b,d) df a b d 1 A 1 x 2 A 1 y 3 A 2 x 4 B 4 z 5 B 1 y 6 B 1 y 7 C 2 z 8 C 2 x duplicated(df[,c(1,2)]) gives me rows 2, 6

I'm stuck in the middle of my project. I have a list of lists like: '((a for apple) (b is book) (c in cat) (ronn live in NY)) Now I want to make a query in the form of a list and have it display the correct entry in my list of lists. For example, if I input '(a for what) or '(what in cat) it will display (a for apple) or (c in cat) . If I input '(ronn live in where) it will show (ronn live in NY) . Can anyone help me solve this problem? How about running a filter routine across the list, and using a lambda object initialized with your query information that will then be applied to the list

https://blog.csdn.net/c1z2w3456789/article/details/81082374 来源： https://www.cnblogs.com/diyunpeng/p/11734030.html

I have a dataframe called imp2 (with about 6,000 rows) for which there are 9 columns labeled 'savres1'...'savres9' . Values in each of these columns are either 1 or 0. For each row, the value of only 1 of these columns is 1 (rest are 0). I'd like to create a new column called 'savres' into which I would put a value between 1 and 9 that matches the index of the column (within this set of 9 columns) which holds the 1 value. E.g. if 'savres7' is 1 and the rest of these columns are 0, then savres should equal 7. I've used several variations of which , match and %in% to find the value, but I'm not