match

递归下降法的语法分析器-3-编译原理

吃可爱长大的小学妹 提交于 2019-12-27 21:18:48
递归下降法的语法分析器 一、实验目的 掌握语法分析器的构造原理,掌握递归下降法的编程方法。 二、实验内容 用 递归下降法 编写一个语法分析程序,使之与词法分析器结合,能够根据语言的上下文无关文法,识别输入的单词序列是否文法的句子。(注意,需要改写文法,消除左递归等) program → block block → { stmts } stmts →  stmt stmts | e stmt → id = expr ; | if ( bool ) stmt | if ( bool ) stmt else stmt | while ( bool ) stmt | do stmt while ( bool ) ; | break ; | block bool → expr < expr | expr <= expr | expr > expr | expr >= expr | expr expr → expr + term | expr - term | term term → term * factor | term / factor | factor factor → ( e xpr ) | id | num   三、实验要求 1.个人完成,提交实验报告。 2.实验报告中给出采用测试源代码片断,及其对应的最左推导过程(形式可以自行考虑)。 程序片断 { i = 2; while (i

52. 正则表达式匹配

别来无恙 提交于 2019-12-27 17:31:05
文章目录 题目描述 1. 递归 代码实现 2. dp自顶向下备忘录 代码实现 复杂度分析 3. dp自底向上 代码实现 复杂度分析 题目描述 1. 递归 代码实现 /** * @Classname Solution * @Description 正则表达式匹配 * @Date 2019/12/24 10:45 * @Author SonnSei */ public class Solution { public static boolean match ( char [ ] str , char [ ] pattern ) { if ( str == null || pattern == null ) return false ; return match ( str , 0 , pattern , 0 ) ; } private static boolean match ( char [ ] str , int sIndex , char [ ] pattern , int pIndex ) { if ( pIndex == pattern . length ) return sIndex == str . length ; boolean firstMatch = sIndex < str . length && ( str [ sIndex ] == pattern [

工程跑不起来 吓懵了

99封情书 提交于 2019-12-27 05:37:13
1. process launch failed: timed out trying to launch app 真机运行的程序已经崩掉了 在运行别的程序就报这个错 有时候工程改为release模式运行时 也会报这个错 打开Xcode的菜单product -> scheme -> edit scheme -> 在左侧选择Run xxx.app栏目,右侧选择Info标签,将Build Configuration的状态改为Debug 2.This application's application-identifier entitlement does not match that of the installed application. These values must match for an upgrade to be allowed. 手机上已经安装了标志符一样的app,删除即可 来源: https://www.cnblogs.com/fengkuangIT/p/5090007.html

2019 SDN上机第6次作业

纵然是瞬间 提交于 2019-12-26 05:36:49
一、使用Python脚本完成拓扑搭建,并连接ryu控制器。 二。使用Ryu的REST API下发流表实现和第2次实验同样的VLAN curl -X POST -d '{ "dpid": 1, "priority":1, "match":{ "in_port":2 }, "actions":[ { "type": "PUSH_VLAN", "ethertype": 33024 }, { "type": "SET_FIELD", "field": "vlan_vid", "value": 4096 }, { "type": "OUTPUT", "port": 1 } ] }' http://127.0.0.1:8080/stats/flowentry/add curl -X POST -d '{ "dpid": 1, "priority":1, "match":{ "in_port":3 }, "actions":[ { "type": "PUSH_VLAN", "ethertype": 33024 }, { "type": "SET_FIELD", "field": "vlan_vid", "value": 4097 }, { "type": "OUTPUT", "port": 1 } ] }' http://127.0.0.1:8080/stats/flowentry/add

What should the javascript match() regex function return? [duplicate]

落爺英雄遲暮 提交于 2019-12-25 18:53:44
问题 This question already has answers here : Match all consecutive numbers of length n [duplicate] (3 answers) Closed 2 years ago . Take this example: "12345".match(/(?=(\d{4}))/g); Pasting that line above into my (Chrome) console is returning ["", ""] for me but I am trying to extract an array of ["1234", "2345"] . This MDN article seems to indicate that I should, indeed, expect an array of matches. The particular regex on this exact string definitely returns those matches as proven in this

excel formula to pull values from another sheet if number in one column is the same

China☆狼群 提交于 2019-12-25 18:50:00
问题 I am trying to automate an invoice and need some help. I have my invoice formatted on one tab, and all orders are entered on a separate tab. The 'Orders' tab has multiple columns -- Invoice ID, Invoice Date, Customer ID, etc. Each product within an order is entered on a new row with the same Invoice ID. I have formulas set up in the cells on my 'Invoice' tab to grab the information from the 'Orders' tab when I simply input the Invoice ID. However, how do I modify the formula to get all the

java regex match for alphanumeric string

蹲街弑〆低调 提交于 2019-12-25 18:34:53
问题 I am trying to check whether a password is alphanumeric or not using regex but I am not getting the result I expect. What is the problem with the below code? boolean passwordOnlyAlphaNumericCheck = false; Pattern patternAlphaNumericCheck = Pattern.compile("^[a-zA-Z0-9]$"); Matcher matcherAlphaNumericCheck = patternAlphaNumericCheck.matcher(login.getPassword()); if(matcherAlphaNumericCheck.find()) passwordOnlyAlphaNumericCheck = true; Thanks for help 回答1: You need to add a quantifier that

SPARQL: Choose one triple from multiple match?

左心房为你撑大大i 提交于 2019-12-25 18:25:28
问题 I have a kind of interesting problem with SPARQL query. I am querying for a triple and I have multiple match - maybe 2. But I need the code to choose only one. It absolutely doesn't matter which one. For example: I am querying for a book for 5-years old and it founds 2 books in the database but I need to have only one saved in variable (doesn't matter which one). Is this even possible in SPARQL? Please let me know if you need any other information. Thank you all in advance for your time! The

FInd nearest value within list condition

守給你的承諾、 提交于 2019-12-25 18:19:12
问题 I want to find nearest value of a cell but don't know how. In my excel sheet cell B1 has a value(LIST NAME) and cell B2 has other value which is to be searched with condition. If cell B1 has value GP_42(list name) then search the value of cell B2 withing list GP_42 (D4:D13) If cell B1 has value GP_42(list name) then se[![enter image description here][2]][2]arch the value of cell B2 withing list GP_42 (E4:E13). If value doesn't match then result should be the nearest matched value. Result

Extract the contents of a string between two string delimiters using match in C#

旧街凉风 提交于 2019-12-25 10:00:39
问题 So, say I'm parsing the following HTML string: <html> <head> RANDOM JAVASCRIPT AND CSS AHHHHHH!!!!!!!! </head> <body> <table class="table"> <tr><a href="/subdir/members/Name">Name</a></tr> <tr><a href="/subdir/members/Name">Name</a></tr> <tr><a href="/subdir/members/Name">Name</a></tr> <tr><a href="/subdir/members/Name">Name</a></tr> <tr><a href="/subdir/members/Name">Name</a></tr> <tr><a href="/subdir/members/Name">Name</a></tr> <tr><a href="/subdir/members/Name">Name</a></tr> <tr><a href="