MASM

Hey so I am getting this error when I run this code: 1>------ Build started: Project: Project, Configuration: Debug Win32 ------ 1> Assembling [Inputs]... 1>assign2.asm(32): error A2022: instruction operands must be the same size 1>assign2.asm(33): error A2022: instruction operands must be the same size 1>C:\Program Files (x86)\MSBuild\Microsoft.Cpp\v4.0\BuildCustomizations\masm.targets(49,5): error MSB3721: The command "ml.exe /c /nologo /Zi /Fo"Debug\assign2.obj" /Fl"Project.lst" /I "c:\Irvine" /W3 /errorReport:prompt /Taassign2.asm" exited with code 1. ========== Build: 0 succeeded, 1

How can I convert a number contained in a string from any base to any other base? Bases can be anything i.e.: 2, 16, 10, 4, 8, 9. I'm expecting the user to enter the base number. The user will enter the output base (the base to be converted to). The user will enter the number he wants to convert. Pre thoughts: I will save the input base and the output base in variables. Then I'll save the number he enters in a string (because he could enter any kind of number (hex, binary, base-5..). I'm just trying to figure out how to convert that string to a number so i can convert it to the output base.

There is an example code in this introduction , like below: ; Sample x64 Assembly Program ; Chris Lomont 2009 www.lomont.org extrn ExitProcess: PROC ; external functions in system libraries extrn MessageBoxA: PROC .data caption db '64-bit hello!', 0 message db 'Hello World!', 0 .code Start PROC sub rsp,28h ; shadow space, aligns stack mov rcx, 0 ; hWnd = HWND_DESKTOP lea rdx, message ; LPCSTR lpText lea r8, caption ; LPCSTR lpCaption mov r9d, 0 ; uType = MB_OK call MessageBoxA ; call MessageBox API function mov ecx, eax ; uExitCode = MessageBox(...) call ExitProcess Start ENDP End The above

I wanted to add the following numbers: 40, 90, 50 and 155 and I get a total of 355. I wanted to experiment and test out whether the register AL will have a bit limit of (2^8) - 1, and when I compiled the code and execute the code, I get decimal of 1376331855. How did that happen? Also, I thought 355 is greater than 255, and as a result should display an overflow exception. I understand if I use MOVZX I will be able to carry the calculation into the higher register of AX. Also, I am very confused with the difference between AL and AH. Is there a different in memory allocation for AL and AH?

I'm working with masm and I've encountered a scenario I do not readily understand how to solve, for example: X = (A)/(C*D) If I multiple C*D first, my value is DX:AX and to my knowledge, I cannot use that as a divisor. If I do division separately as A/C and A/D, I run the risk of losing precision (from the reminders, etc.). What's the best way to implement this? As you correctly note, you can't use a 32-bit number as the divisor in a 16-bit division, but since we're only interested in doing integer division that's not a problem. There are two cases to consider (for unsigned division): DX == 0

1、建立一个文件夹xxx将masm中的lnk.exe,masm.exe,ml.exe和debug.exe放到文件夹中，并mount C X:\xxx C: 单步运行程序 debug xxx.exe debug将程序加载入内存，设置CS:IP指向程序的入口，但debug并不放弃对CPU的控制，所以可以使用相关命令单步执行程序。 来源： https://www.cnblogs.com/aeron99/p/11731431.html