mapping

问题 I want to use Spring-Tiles intergration. Here you can see how my app looks like. So my question is: why Spring-MVC dispatcher Servlet can not resolve my Target page ??? 回答1: The problem is that you use <url-pattern>/*</url-pattern> in servlet mapping, so all requests are processed by DispatcherServlet , including request to *.jsp tiles. The most versatile way to solve it (but to keep restful urls without prefixes) is to use a UrlRewriteFilter. 回答2: I think you're missing a critical

问题 How can I map a Map in JPA without using Hibernate's classes? 回答1: Does not the following work for you? @ManyToMany(cascade = CascadeType.ALL) Map<String,EntityType> entitytMap = new HashMap<String, EntityType>(); EntityType could be any entity type, including a String . 回答2: Although answer given by Subhendu Mahanta is correct. But @CollectionOfElements is deprecated. You can use @ElementCollection instead: @ElementCollection @JoinTable(name="ATTRIBUTE_VALUE_RANGE", joinColumns=@JoinColumn

问题 All my models contain at least two associations. When modeling this in ef4 I've only been able to do this without a second Foreign Key property through the use of the fluent interface. ForeignKey seems like the right attribute to use, except for the fact that it requires a string parameter. So my question is, can you have a navigational property and declare it as such using an attribute? public class User : IAuditable { // other code public virtual User Creator { get; set; } public virtual

问题 I've been trying to use AutoMapper to save some time going from my DTOs to my domain objects, but I'm having trouble configuring the map so that it works, and I'm beginning to wonder if AutoMapper might be the wrong tool for the job. Consider this example of domain objects (one entity and one value): public class Person { public string Name { get; set; } public StreetAddress Address { get; set; } } public class StreetAddress { public string Address { get; set; } public string City { get; set;

问题 I have a User < Country model. A user belongs to a country, but may not belong to any (null foreign key). How do I set this up? When I try to insert a user with a null country, it tells me that it cannot be null. The model is as follows: public class User{ public int CountryId { get; set; } public Country Country { get; set; } } public class Country{ public List<User> Users {get; set;} public int CountryId {get; set;} } Error: A foreign key value cannot be inserted because a corresponding

问题 I've coded a function that aims to map into an arbitrary tree of nested proper lists, somewhat analogous to the common lisp function map-into : (defun map-into-tree (fn tree) "Destructive mapping into a proper tree." (cond ((null tree) nil) ((atom (car tree)) (setf (car tree) (funcall fn (car tree))) (map-into-tree fn (cdr tree))) (t (map-into-tree fn (car tree)) (map-into-tree fn (cdr tree))))) (defparameter *tree* '(1 (2) ((3)) (4 5) (6 ((7))))) *TREE* (map-into-tree #'1+ *tree*) NIL *tree*

问题 Lets say i have a list and i want to add some values into it using a mapping function: const arr = [1, 2, 3, 4, 5]; const anotherArr = []; I do this using a functional approach: arr.map((item) => anotherArr.push(item); Is this an antipattern / bad logic - that is, not using the mapping operation return value for anything? Are there any good resources on this? (i know this logic is silly and i can just copy the list - that is not the point of my question) 回答1: Yes, this is an anti-pattern. The

问题 I use elasticsearch ngram "analysis": { "filter": { "desc_ngram": { "type": "ngram", "min_gram": 3, "max_gram": 8 } }, "analyzer": { "index_ngram": { "type": "custom", "tokenizer": "keyword", "filter": [ "desc_ngram", "lowercase" ] }, "search_ngram": { "type": "custom", "tokenizer": "keyword", "filter": "lowercase" } } } And I have 2 objects here { "name": "Shana Calandra", "username": "shacalandra", }, { "name": "Shana Launer", "username": "shalauner", }, And using this query { query: {

问题 The original question stems from this question: Why is this JPA 2.0 mapping giving me an error in Eclipse/JBoss Tools? As you can see this constellation also freaks out the Eclipse Dali JPA validator. The JPA spec seems to allow this as seen here (somewhat reliable): Does the JPA specification allow references to non-primary key columns? The exact code posted in the first question also raises a Hibernate MappingException: Exception in thread "main" javax.persistence.PersistenceException:

问题 I have a table with five columns. The two columns, together, make up the primary key of my table. I'm trying to instantiate an Entity class that corresponds to that table using hibernate. The problem is how do I tell hiberante that the primary key is not just a single field of the class but two. I don't want hiberante to create the database schema for me as I have already crated it with all the necessary primary key settings. I have read about the composite-key but it think that is not