lxml

I know this looks embarrassingly easy, and I guess the problem is that I just don't have a clear understanding of all this bytes-str-unicode (and encoding-decoding , speaking frankly) stuff yet. I've been trying to get my working code to run on Python 3. The part I'm stuck with is when I parse an XML with lxml and decode a base64 string that is in that XML. The code now works in the following manner: I retrieve the binary data with an XPath query '.../binary/text()' . This produces a one-element list containing a lxml.etree._ElementUnicodeResult object. Then, with python 2, I was able to do:

I have an XML document which I'm pretty-printing using lxml.etree.tostring print etree.tostring(doc, pretty_print=True) The default level of indentation is 2 spaces, and I'd like to change this to 4 spaces. There isn't any argument for this in the tostring function; is there a way to do this easily with lxml? As said in this thread , there is no real way to change the indent of the lxml.etree.tostring pretty-print. But, you can: add a XSLT transform to change the indent add whitespace to the tree, with something like in the cElementTree library code: def indent(elem, level=0): i = "\n" + level

I would like to parse a huge xml (>200MB) using lxml.etree in Python. I tried to use etree.parse to load the XML file, but this does not work due to the filesize: etree.parse('file.xml')Traceback (most recent call last): File "<stdin>", line 1, in <module> File "lxml.etree.pyx", line 2706, in lxml.etree.parse (src/lxml/lxml.etree.c:49958) File "parser.pxi", line 1500, in lxml.etree._parseDocument (src/lxml/lxml.etree.c:71797) File "parser.pxi", line 1529, in lxml.etree._parseDocumentFromURL (src/lxml/lxml.etree.c:72080) File "parser.pxi", line 1429, in lxml.etree._parseDocFromFile (src/lxml

Downloading this page and making a minor edit to it, changing the first 65 in this paragraph to 68 : I then parse both sources with BeauifulSoup and diff them with difflib . url = 'https://secure.ssa.gov/apps10/reference.nsf/links/02092016062645AM' response = urllib2.urlopen(url) content = response.read() # get response as list of lines url2 = 'file:///Users/Pyderman/projects/temp/02092016062645AM-modified.html' response2 = urllib2.urlopen(url2) content2 = response2.read() # get response as list of lines import difflib d = difflib.Differ() diffed = d.compare(content, content) soup = bs4

1. 申请公众号。教程有。 2. 开发配置（python） 安装 安装web.py 安装libxml2, libxslt, lxml python 开发自己的本地服务器，然后部署到公网 (可以使用小米球来映射本地服务器） 开发流程图 　　　　 代码片段： 来源： https://www.cnblogs.com/ahMay/p/11677741.html

I'm attempting to write a parser using lxml and the iterparse method to step through a very large xml file containing many items. My file is of the format: <item> <title>Item 1</title> <desc>Description 1</desc> <url> <item>http://www.url1.com</item> </url> </item> <item> <title>Item 2</title> <desc>Description 2</desc> <url> <item>http://www.url2.com</item> </url> </item> and so far my solution is: from lxml import etree context = etree.iterparse( MYFILE, tag='item' ) for event, elem in context : print elem.xpath( 'description/text( )' ) elem.clear( ) while elem.getprevious( ) is not None :