lxml

i got the following code : #!/usr/bin/python2.6 from lxml import etree n = etree.Element('test') n.set('id','1234') print etree.tostring(n) the output generate is <test id="1234"/> but i want <test id='1234'/> can someone help ? I checked the documentation and found no reference for single/double-quote option. I think your only recourse is print etree.tostring(n).replace('"', "'") Update Given: from lxml import etree n = etree.Element('test') n.set('id', "Zach's not-so-good answer") my original answer could output malformed XML because of unbalanced apostrophes: <test id='Zach's not-so-good

I have a document with the following data: <div class="ds-list"> <b>1. </b> A domesticated carnivorous mammal <i>(Canis familiaris)</i> related to the foxes and wolves and raised in a wide variety of breeds. </div> And I want to get everything within the class ds-list (without <b> and <i> tags). Currently my code is doc.cssselect('div.ds-list') , but all this picks up is the newline before the <b> . How can I get this to do what I want it to? Perhaps you are looking for the text_content method?: import lxml.html as lh content='''\ <div class="ds-list"> <b>1. </b> A domesticated carnivorous

I've created a virtualenv for PyPy with: virtualenv test -p `which pypy` source test/bin/activate I installed the following dependencies: sudo apt-get install python-dev libxml2 libxml2-dev libxslt-dev And then I run: pip install --upgrade pypy As a result I get a lot of errors looking like this: src/lxml/lxml.etree.c:234038:22: error: `PyThreadState` {aka struct _ts}` has no member named `use_tracing` How do I properly install lxml for PyPy 2.6.0? I used the following fork of lxml for PyPy instead: https://github.com/aglyzov/lxml/tree/cffi It can be installed with: pip install -e git+git:/

I want to find out all the urls and its name from a html page using lxml. I can parse the url and can find out this thing but is there any easy way from which I can find all the url links using lxml? from lxml.html import parse dom = parse('http://www.google.com/').getroot() links = dom.cssselect('a') from lxml import etree, cssselect, html with open("/you/path/index.html", "r") as f: fileread = f.read() dochtml = html.fromstring(fileread) select = cssselect.CSSSelector("a") links = [ el.get('href') for el in select(dochtml) ] links = iter(links) for n, l in enumerate(links): print n, l 来源：

目录 Beautifulsoup模块 官方中文文档 介绍 基本使用 遍历文档树 搜索文档树 五种过滤器 **find_all( name , attrs , recursive , text , **kwargs )** **find( name , attrs , recursive , text , **kwargs )** 其他方法 CSS选择器 总结 Beautifulsoup模块 官方中文文档 Beautifulsoup官方中文文档 介绍 Beautiful Soup 是一个可以从HTML或XML文件中提取数据的Python库.它能够通过你喜欢的转换器实现惯用的文档导航,查找,修改文档的方式.Beautiful Soup会帮你节省数小时甚至数天的工作时间.你可能在寻找 Beautiful Soup3 的文档,Beautiful Soup 3 目前已经停止开发,官网推荐在现在的项目中使用Beautiful Soup 4, 移植到BS4 #安装 Beautiful Soup pip install beautifulsoup4 #安装解析器 Beautiful Soup支持Python标准库中的HTML解析器,还支持一些第三方的解析器,其中一个是 lxml .根据操作系统不同,可以选择下列方法来安装lxml: $ apt-get install Python-lxml $

I have an xml file <temp> <email id="1" Body="abc"/> <email id="2" Body="fre"/> . . <email id="998349883487454359203" Body="hi"/> </temp> I want to read the xml file for each email tag. That is, at a time I want to read email id=1..extract body from it, the read email id=2...and extract body from it...and so on I tried to do this using DOM model for XML parsing, since my file size is 100 GB..the approach does not work. I then tried using: from xml.etree import ElementTree as ET tree=ET.parse('myfile.xml') root=ET.parse('myfile.xml').getroot() for i in root.findall('email/'): print i.get('Body'