lxml

问题 How can I parse the below XML in order to find for each GUIDE, it's ID and UL, then for each PAGE inside GUIDE, the page ID and any images that appear inside BOXES / BOX / ASSETS / DESCRIPTION? The images are in HTML format so I need to grab the source from each image. <guide> <id></id> <url></url> <group> <id></id> <type></type> <name></name> </group> <pages> <page> <id></id> <name></name> <description></description> <boxes> <box> <id></id> <name></name> <type></type> <map_id></map_id>

问题 I did not find anyone explaining this error... I'm using lxml 3.1.0. When there is an HTML/XML like that: <h1 class="fn"><strong class="brand">Lange</strong> XT 100 LV Ski Boots 2014</h1> the _ElementStringResult of string " XT 100 LV Ski Boots 2014" will be returned when we run: >> elemstr = tree.xpath('//body//h1/text()')[0] However, when we run as follows, we would get... >> parent = elemstr.getparent() >> tree.getpath(parent) /html/body/therestofthepath/h1/strong Did anyone have a problem

问题 I am parsing data from here. On the webpage I can get data for example yesterday by selecting the desired date. How can I parse to get the same data (ie. yesterday)? Like, pass custom dates to get data for that date. 回答1: You can either use Selenium or use the site's ajax api. Here is an example of the latter: def get_by_date(date): url = 'https://markets.ft.com/data/world/ajax/getnextecoevents?startDate=' + date r = requests.get(url) return r.json()['html'] date should be formatted as yyyy

问题 I have some xml files with !ENTITY Definitions and &file_reference; And I can process these successfully. However I would like to preprocess the files and access the !ENTITY Definitions to extract file names and also the &file_references and which section of xml they are in An example XML file looks like <?xml version="1.0" encoding="UTF-8"?> <!DOCTYPE gdml [ <!ENTITY materials SYSTEM "materialsOptical.xml"> <!ENTITY solids_Mainz_v2 SYSTEM "solids_Mainz_v2.xml"> <!ENTITY matrices_Mainz_v2

问题 import lxml.html Gives me error when i want to compile with cx_freeze: Traceback (most recent call last): File "C:\Python27\Scripts\cxfreeze", line 5, in <module> main() File "C:\Python27\lib\site-packages\cx_Freeze\main.py", line 188, in main freezer.Freeze() File "C:\Python27\lib\site-packages\cx_Freeze\freezer.py", line 572, in Freeze self._FreezeExecutable(executable) File "C:\Python27\lib\site-packages\cx_Freeze\freezer.py", line 186, in _FreezeExecutable exe.copyDependentFiles,

问题 For the code below I need to get dates and their times+hrefs+formats+...(not shown) respectively. <div class="showtimes"> <h2>The Little Prince</h2> <div class="poster" data-poster-url="http://www.test.com"> <img src="http://www.test.com"> </div> <div class="showstimes"> <div class="date">9 December, Wednesday</div> <span class="show-time techno-3d"> <a href="http://www.test.com" class="link">12:30</a> <span class="show-format">3D</span> </span> <span class="show-time techno-3d"> <a href=

问题 I have the following xml - <draw:image></draw:image> I want to add multiple xlink attributes to it and make it - <draw:image xlink:href="image" xlink:show="embed"></draw:image> I tried using the following code but got the error "ValueError: Invalid attribute name u'xlink:href'" root.xpath("//draw:image", namespaces= {"draw":"urn:oasis:names:tc:opendocument:xmlns:drawing:1.0"}) [0].attrib['xlink:href'] = 'image' What am I doing wrong? There seems to be something related to namespaces, but I

问题 I try to parse a huge file. The sample is below. I try to take <Name> , but I can't It works only without this string <LevelLayout xmlns="http://schemas.datacontract.org/2004/07/ArcherTech.Common.Domain" xmlns:i="http://www.w3.org/2001/XMLSchema-instance"> xml2 = '''<?xml version="1.0" encoding="UTF-8"?> <PackageLevelLayout> <LevelLayouts> <LevelLayout levelGuid="4a54f032-325e-4988-8621-2cb7b49d8432"> <LevelLayout xmlns="http://schemas.datacontract.org/2004/07/ArcherTech.Common.Domain" xmlns

问题 I have this site http://www.google-proxy.net/ and i need to get first proxy's ip:port. br = webdriver.Firefox() br.get("http://www.google-proxy.net/") ip = br.find_element_by_xpath("//tr[@class='odd']/td[1]").text; time.sleep(random.uniform(1, 1)) port = br.find_element_by_xpath("//tr[@class='odd']/td[2]").text; time.sleep(random.uniform(1, 1)) and it works fine. But now i want to do the same with lxml page = requests.get(proxy_server) root = lxml.html.fromstring(page.text) ip = root.xpath("/

问题 Given following xml: <Ergebnisse> <Spiel> <Datum>2013-10-02</Datum> </Spiel> <Spiel> <Datum>2013-10-03</Datum> </Spiel> <Spiel> <Datum>2013-10-03</Datum> </Spiel> <Spiel> <Datum>2013-10-03</Datum> </Spiel> <Spiel> <Datum>2013-10-06</Datum> </Spiel> <Spiel> <Datum>2013-10-06</Datum> </Spiel> <Spiel> <Datum>2013-10-06</Datum> </Spiel> <Spiel> <Datum>2013-10-06</Datum> </Spiel> <Spiel> <Datum>2014-05-01</Datum> </Spiel> <Spiel> <Datum>2014-05-01</Datum> </Spiel> <Spiel> <Datum>2014-04-27</Datum>