ls

I'm working on a some build scripts that I'd like to depend on only standardized features. I need to sort some files by version. Say the files are bar-1.{0,2,3} bar-11.{0,2,3}. By default, ls gives me: bar-1_0 bar-11_0 bar-11_2 bar-11_3 bar-1_2 bar-1_3 Getting what I want is easy using 'ls -v': bar-1_0 bar-1_2 bar-1_3 bar-11_0 bar-11_2 bar-11_3 The problem is that 'ls -v' is not standard . Standard sort also seems to lack the option I want, though I could be looking at old versions of the specs. Can anyone suggest a portable way to achieve this effect short of writing my own sort routine?

Need to process files in current directory one at a time. I am looking for a way to take the output of ls or find and store the resulting value as elements of an array. This way I can manipulate the array elements as needed. To answer your exact question, use the following: arr=( $(find /path/to/toplevel/dir -type f) ) Example $ find . -type f ./test1.txt ./test2.txt ./test3.txt $ arr=( $(find . -type f) ) $ echo ${#arr[@]} 3 $ echo ${arr[@]} ./test1.txt ./test2.txt ./test3.txt $ echo ${arr[0]} ./test1.txt However, if you just want to process files one at a time, you can either use find 's

I know that it outputs the "long" version but what do each of the sections mean? On my mac, when I type in ls -l /Users I get total 0 drwxr-xr-x+ 33 MaxHarris staff 1122 Jul 1 14:06 MaxHarris drwxrwxrwt 8 root wheel 272 May 20 13:26 Shared drwxr-xr-x+ 14 admin staff 476 May 17 11:25 admin drwxr-xr-x+ 44 hugger staff 1496 Mar 17 21:13 hugger I know that the first line it the permissions, although I don't know what the order is. It would be great if that could be explained too. Then whats the number after it? Basically, what do each one of these things mean? Why are the usernames written twice

This question already has an answer here: How to pass command output as multiple arguments to another command 4 answers I'm taking a unix/linux class and we have yet to learn variables or functions. We just learned some basic utilities like the flag and pipeline, output and append to file. On the lab assignment he wants us to find the largest files and copy them to a directory. I can get the 5 largest files but I don't know how to pass them into cp in one command ls -SF | grep -v / | head -5 | cp ? Directory It would be: cp `ls -SF | grep -v / | head -5` Directory assuming that the pipeline is

I have to write a script that finds all executable files in a directory. So I tried several ways to implement it and they actually work. But I wonder if there is a nicer way to do so. So this was my first approach: ls -Fla | grep \*$ This works fine, because the -F flag does the work for me and adds to each executable file an asterisk, but let's say I don't like the asterisk sign. So this was the second approach: ls -la | grep -E ^-.{2}x This too works fine, I want a dash as first character, then I'm not interested in the next two characters and the fourth character must be a x. But there's a

This is a question that I self-answered on my tech blog where I keep the tech-tips which I need to give to myself from time to time, so I decided to move it over here instead. The original blog post is here: http://thehacklist.blogspot.com/2009/04/cygwin-ls-command-not-found.html If you are a linux enthusiast and really miss those greps and sed/awks on the windows box, you've probably installed cygwin . You tried running it either by double-clicking the cygwin icon on your desktop or the cygwin.bat file in your C:\cygwin directory and got the bash-3.X$ prompt. However, although the pwd or cd

I'm using ls -a command to get the file names in a directory, but the output is in a single line. Like this: . .. .bash_history .ssh updater_error_log.txt I need a built-in alternative to get filenames, each on a new line, like this: . .. .bash_history .ssh updater_error_log.txt Bert F Use the -1 option (note this is a "one" digit, not a lowercase letter "L"), like this: ls -1a First, though, make sure your ls supports -1 . GNU coreutils (installed on standard Linux systems) and Solaris do; but if in doubt, use man ls or ls --help or check the documentation. E.g.: $ man ls ... -1 list one file