loops

问题 I have a collection of objects called the response and I am creating another variable called object that's an empty object and creating object.array and set it to the response variable. I would think I am creating a new scope. However, if I set the age inside object.array as null, this sets the age in my response array to null . Why is this happening and how can I create a duplicate variable that doesn't affect the original? I need to keep the above variables as is. So object needs to be an

问题 This question already has answers here : Is there a function to extract a 'column' from an array in PHP? (12 answers) Closed 3 years ago . I have an array: Array ( [0] => Array ( [0] => Pen [1] => Apple ) [1] => Array ( [0] => Oooo [1] => Pineapple pen ) How I can get a first elements of each array? For example: Pen Oooo It's my function $parameters = array('wiki_1', 'wiki_2', 'wiki_3', 'wiki_4','wiki_5' ,'wiki_6', 'wiki_7', 'wiki_8', 'wiki_9', 'wiki_10', 'wiki_11', 'wiki_12'); function wiki

问题 [ ["STRG008c0",2,0,"orange","***STRG008*#*"], ["STRG009c0",3,0,"orange","***STRG009*#*"], ["STRG001c0",2,0,"green","***STRG001*#*"], ["STRG003c0",3,0,"green","***STRG003*#*"], ["STRG002c0",4,0,"green","***STRG002*#*"] ] How do I get the below in a loop in PHP? ***STRG008*#* ***STRG009*#* ***STRG001*#* ***STRG003*#* ***STRG002*#* 回答1: It looks like you want the last column values as a string. Method 1: Collect all last values of each subarray in a new variable, say $result and implode() them

问题 [ ["STRG008c0",2,0,"orange","***STRG008*#*"], ["STRG009c0",3,0,"orange","***STRG009*#*"], ["STRG001c0",2,0,"green","***STRG001*#*"], ["STRG003c0",3,0,"green","***STRG003*#*"], ["STRG002c0",4,0,"green","***STRG002*#*"] ] How do I get the below in a loop in PHP? ***STRG008*#* ***STRG009*#* ***STRG001*#* ***STRG003*#* ***STRG002*#* 回答1: It looks like you want the last column values as a string. Method 1: Collect all last values of each subarray in a new variable, say $result and implode() them

问题 Full Code at https://codepen.io/CodeLegend27/pen/ExPZRxa did read similary articles but didnt managed to solve it so my array looks like this: I have this loop for (let i = 0; i < ultraarr.length; i++) { ultraarr.sort(); $(".row").append(ultraarr[i].display()) } this calls the function display which is a class function and it basically inserts the data into html. What i want it to DO: i want it ordered according to the dates ascending. did research the a-b stuff but cant see the solution for

问题 This is not a case where I can use both without problems, because I'm already convinced that loops are much easier to understand and I try to always use them. But then I stumble upon this (C++ function for binary search tree): Node* Insert(Node* &rootptr,Node* data) { if (rootptr == nullptr) { rootptr = data; } else if (data->number <= rootptr->number) { rootptr->leftptr = Insert(rootptr->leftptr,data); } else { rootptr->rightptr = Insert(rootptr->rightptr,data); } return rootptr; } And my

问题 I am doing web scraping with bash . I have these URLs saved in a file called URL.txt . ?daypartId=1&catId=1 ?daypartId=1&catId=11 ?daypartId=1&catId=2 I want to pass these URL to an array in another file main.sh which would append in the base URL https://www.mcdelivery.com.pk/pk/browse/menu.html**(append here)** . I want to append all the URl in URL.txt file in the end of the base URL one by one. I have come up with the code to extract the URL from the URL.txt but it is unable to append it to

问题 I'm having a problem with loops. How does this loop, loop through different values ​​and display all values ​​on the label, rather than displaying the last value of the array on the label? Image of code for loop. 回答1: This below code is just copied(written) from your screenshot. which has the minor bug. sinhvien sv = new sinhvien(); sv.setdata("CC",12); sv.setdata("CL",14); sv.setdata("CCCL",16); s1.add(sv); As you have only created one instance of sv and setting the value 3 times. Value CCCL

问题 the code below compiles perfectly for 5 integers entered by the user. what i want to do is alter my code so that i can as the user how many numbers the user wants in the list. then the program will ask the user to enter that many integers and then the program will find the largest of those integers. can anyone help me alter the code below to fit these new standards? { int integer1 = Integer.parseInt(JOptionPane.showInputDialog( "Enter an integer:" )); int integer2 = Integer.parseInt

问题 the code below compiles perfectly for 5 integers entered by the user. what i want to do is alter my code so that i can as the user how many numbers the user wants in the list. then the program will ask the user to enter that many integers and then the program will find the largest of those integers. can anyone help me alter the code below to fit these new standards? { int integer1 = Integer.parseInt(JOptionPane.showInputDialog( "Enter an integer:" )); int integer2 = Integer.parseInt