logic

问题 To clarify I only wanted one or two for loops to help me on my way, preferably in the same style as I had used in the vertical :) I'm making a game using a 2D array, and I need a check that tests if at the current position (indicated by a green square) the character there is part of a diagonal sequence of "l" more of the character. 回答1: public static boolean diagonals(char[][] b, int row, int col, int l) { int counter = 1; // because we start from the current position char charAtPosition = b

问题 I have a ANTLR expression parser which can evaluate expressions of the form ( A & ( B | C ) ) using the generated visitor. A , B and C can take any of the 2 values true or false . However I am faced with a challenge of finding all combinations of A,B and C for which the expression is true. I tried to solve this by the following method. Evaluate the expression for the 3 variables taking true and false each This comes to 8 combinations since 2 ^ 3 is 8 I evaluate giving values like 000, 001,

问题 I am writing a code in order to calculating the value of Pi, and sometimes could take a long time to calculate. I added a progress bar to show progress, but the code does exactly what I told it to, it opens the progress bar after the calculations and then immediately closes it (It closes when the value reaches 100.) I have attempted to stick the code for the progress bar into the loop, but soon I realized that solves the solution, but creates multiply progress bar windows. If placed before

问题 I have this hypothetical program to check if a path exists from point A to B. /*city rules*/ edge(phx, tuc). edge(tuc, ccg). edge(ccg, sf). connected(C1, C2) :- edge(C1, C2). connected(C1, C2) :- edge(C1, X), connected(X, C2). the problem is it returns true, then false. Where is the false coming from? 回答1: Let's look at the exact reply you got from Prolog! First you got a single true and on pressing SPACE or ; you eventually got: ?- connected(phx,sf). true ; false. So you got true ; false. as

问题 The standard proof of of the impossibility of solving the halting problem is usually something like this //does_halt() takes a function as input and returns true if it will ever finish computing function paradox() {if does_halt(paradox()) { while(true){} } } This proof requires that you call the halting function recursively, but is it possible to make a halting function that always computes the correct result as long as it isn't called on itself? 回答1: That proof does not require recursion.

问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed last year . I've been trying to design support for recurring events (like you would see in Outlook, or a task manager, etc). I've been doing a lot of digging on Google and StackOverflow, but not much luck. Wondering if anyone has any pointers or resources. 'Requirements' Support for daily events (occurring Mon, Tues, Thurs at

问题 I'm trying to create a INSERT statement for every row in a PHPExcel object. As I've struggled to iterate across the column (ie. go B1 C1 D1, get the values, and put them into an array), I've opted to get all the values for each column and put them into a multi-dimensional array that looks like this: Array ( [foo] => Array ( [0] => 250 [1] => 247 [2] => 279 [3] => 249 ) [bar] => Array ( [0] => AM PROV [1] => AM PROV [2] => AM PENS [3] => AM PROV ) [schoo] => Array ( [0] => xxxx [1] => yyy [2]

问题 A program that prints its input one word per line. int main() { int c; while ((c=getchar()) != EOF) { if (c== ' ' || c== '\n' ||c == '\t') putchar('\n'); else { putchar(c); } } return 0; } The above program prints the result correctly, one word per line. After changing the condition accordingly, I was expecting the program below to also print one word per line. However I am not getting the correct result. Am I making some silly mistake or is something wrong? int main() { int c; while ((c

问题 how can we get the number of sundays from an given month ? in average they are 4 but can we get the exact number of sundays in a specify month , i don't know where to start for this so any hint about the logic behind counting the sundays or any thing related to this will be much appreciated and helpful for me , am trying to get the total number of days in a given month and somewhat am able to do that with this code : func getNumberOfDaysInMonth (month : Int , Year : Int) -> Int{ let

问题 Let's say I have 100 different conditions in a IF-ELSE statement. if((boolean = methodA)){ ... } else((boolean = methodZ)){ ... } Logically, I think the least possible condition should go to the last condition(the one with methodZ) and the most frequent condition should go to ths first condition(methodA). Then I thought "what if methodA takes a lot of time compute?". methodZ would take more time than to reach even if its least frequent. Should I order the conditions by its compute time? Or