logic

问题 I have five 2-D Arrays, (You can assume it like five spreadsheets), I want to take the intersection of the five (I want the common rows of all five in a new spreadsheet) but now I find out that one of the array is a NULL Array, (I find that instead of a spreadsheet, it's just a blank piece of paper), so now I want to ignore it and Intersect the rest of the Arrays... Please suggest a method of doing that... P.S. - I know it is against the property of intersection because we all know that

问题 I want to toggle the visibility of classes of list items and also toggle the visibility of all the list items. With help of another stack overflow post, I am able to toggle specific classes of list items. Here's the Javascript I have that toggles specific classes of list items: var switcher = [false, false, false]; var classes = ['easy', 'fun', 'silly']; $('.toggler').click(function () { var x = $(this).hasClass('checked'); switcher[$(this).data('switch')] = !x; $(this).toggleClass("checked",

问题 Suppose I have a Sphinx index with the following boolean attributes: narrow tall I want to filter all the documents that are NOT (narrow AND tall) . Can this be done with Sphinx? If it makes any difference I'm using the Python sphinxapi.py . 回答1: Ok, with attributes, you can create a 'virtual' attribute and then filter on that. .setSelect("*, (tall=1)+(narrow=1) as tallnarrow") .setFilter("tallnarrow", [2], true) 来源： https://stackoverflow.com/questions/29018778/can-sphinx-search-engine-do-a

问题 I'm supposed to write a program that asks for the number of rows the user wants. For example is the user entered 5 it will display all numbers from 25 to 1 arranged in 5 columns and 5 rows. Something like this should be the output if 5 is entered: 25 24 23 22 21 16 17 18 19 20 15 14 13 12 11 6 7 8 9 10 5 4 3 2 1 As you can see there is a pattern. the first number to appear is the square of the number. then the next number is number squared minus 1. Until it reached 21, 5 will be subtracted

问题 /* * isLessOrEqual - if x <= y then return 1, else return 0 * Example: isLessOrEqual(4,5) = 1. * Legal ops: ! ~ & ^ | + << >> * Max ops: 24 * Rating: 3 */ int isLessOrEqual(int x, int y) { int msbX = x>>31; int msbY = y>>31; int sum_xy = (y+(~x+1)); int twoPosAndNegative = (!msbX & !msbY) & sum_xy; //isLessOrEqual is FALSE. // if = true, twoPosAndNegative = 1; Overflow true // twoPos = Negative means y < x which means that this int twoNegAndPositive = (msbX & msbY) & !sum_xy;//isLessOrEqual

问题 I want to write a SQL query where if the datetime is not been assigned I want to replace a string which can select all date and time. How Actually it works: SELECT * FROM `entry` WHERE `user` like 'TOM' or `user` like 'PHP' and `entry_datetime` between '2013-03-13 22:20:18' and '2013-03-13 22:20:26' My Doubt: If the php do not get the value of the date from and to but I don't want to change the query by deleting the AND condition but I want to replace some thing in between date and time and

问题 I am working on a project where I am reading memory locations and need to output their hex value in ASCII. The language gives me a 16 bit word length, so I have a need to divide to grab a nibble at a time to convert to hex. Unfortunately, the language only offers and, or, not, and add for mathematical/logical functions. I've figured I can create the desired effect by left shifting and testing for a negative flag to add a 1 to the end after shifting, but I'm figuring there has to be a better

问题 I have two way of doing handling hashed IDs but need your opinions on which one would better over another and why? I'm only interested in the logic rather than what technology I used for hashing or table data type etc! I'm going to generate an URL to handle deleting a product and the URL will be like this (last segment is hashed (SHA1) product.id): ...../delete/product/123c45c789ds654dedkjfghr87frd SCENARIO 1: Store hashed ID in table and use it like this: > Query: DELETE ...... WHERE hash_id

问题 Found this little oddity while playing around. >>> 'Hello' == ('Hello' or 'World') True >>> 'Hello' == ('World' or 'Hello') False >>> 'Hello' == ('Hello' and 'World') False >>> 'Hello' == ('World' and 'Hello') True Is there some trick to this logic that I'm not getting? Why is the order of the strings the determining factor of these queries? Should I not be using parentheses at all? Why does changing to "and" flip the outputs? Thanks a buncharooni. 回答1: In Python, all objects may be

问题 Its well known in theoretical computer science that the "Hello world tester" program is an undecidable problem.(Here is a link what i mean by hello world tester My question is since given a program as input we can't say what the program will do,can we solve the reverse problem: Given set of input and output,is there an algorithm for writing a program that writes a program to achieve a one to one mapping between the given input and output. I know about metaprogramming but my question is more