local-variables

In IL, you can define local variables using the .locals directive. Where are these variables stored, stack or heap? It is very much an implementation detail of the JIT compiler. It will try very hard to store local variables in a CPU register, very efficient. The stack is the usual backing store, in case there aren't enough registers available to store all the local variables. Big difference between the x86 and x64 jitters for example. x64 has a lot more registers available. This also applies to the arguments passed to a method. x86 allows 2 passed in a CPU register, x64 allows 4. Plus

This question already has an answer here: How to dynamically create a local variable? 4 answers I'm interested in dynamically setting local variables in Ruby. Not creating methods, constants, or instance variables. So something like: args[:a] = 1 args.each_pair do |k,v| Object.make_instance_var k,v end puts a > 1 I want locally variables specifically because the method in question lives in a model and I dont want to pollute the global or object space. Dorkus Prime The problem here is that the block inside each_pair has a different scope. Any local variables assigned therein will only be

Let's say I'm using irb , and type a = 5 . How do I remove the definition of a so that typing a returns a NameError ? Some context: later I want to do this: context = Proc.new{}.binding context.eval 'a = 5' context.eval 'undef a' # though this doesn't work. mikej There are remove_class_variable , remove_instance_variable and remove_const methods but there is currently no equivalent for local variables. You can avoid un-declaring the variable by reducing the scope in which the variable exists: def scope yield end scope do b = 1234 end b # undefined local variable or method `b' for main:Object

Is there a defined order in which local variables are deallocated in C++ (11) ? To be more concise: In which order will side effects of the destructors of two local variables in the same scope become visible? e.g.: struct X{ ~X(){/*do something*/} } int main(){ X x1; X x2; return 0; } Is x1 or x2 destroyed first when main returns or is the order undefined in C++11? James Kanze Within each category of storage classes (except dynamically allocated objects), objects are destructed in the reverse order of construction. I. About local variables Local variables are allocated on the Stack . The Stack