local-variables

Just curious about this. Following are two code snippets for the same function: void MyFunc1() { int i = 10; object obj = null; if(something) return; } And the other one is... void MyFunc1() { if(something) return; int i = 10; object obj = null; } Now does the second one has the benefit of NOT allocating the variables when something is true? OR the local stack variables (in current scope) are always allocated as soon as the function is called and moving the return statement to the top has no effect? A link to dotnetperls.com article says "When you call a method in your C# program, the runtime

I have a method and want to examine variables inside it without debugging - is it possible in Java? I do not want to write tons of code like: System.out.println("a: " + a); I want to something like: System.out.printLocals(); Also it should be great to have something like: System.out.printMembersOf(someObjectInstance); Well, you can write a method with a varargs parameter and just write: dump(variable1, variable2, variable3, variable4, ...); It's not ideal, but it will be enough in some circumstances. There's no way to automatically grab all the local variables from a method and dump them

Following JEP 286: Local-Variable Type Inference description I am wondering, what the reason is for introducing such a restriction, as: Main.java:199: error: cannot infer type for local variable k var k = { 1 , 2 }; ^ (array initializer needs an explicit target-type) So for me logically it should be: var k = {1, 2}; // Infers int[] var l = {1, 2L, 3}; // Infers long[] Because Java compiler can already infer properly the type of an array: void decide() { arr(1, 2, 3); // call void arr(int ...arr) arr(1, 2L, 3); // call void arr(long ...arr) } void arr(int ...arr) { } void arr(long ...arr) { }

How do I default-initialize a local variable of primitive type in C++? For example if a have a typedef: typedef unsigned char boolean;//that's Microsoft RPC runtime typedef I'd like to change the following line: boolean variable = 0; //initialize to some value to ensure reproduceable behavior retrieveValue( &variable ); // do actual job into something that would automagically default-initialize the variable - I don't need to assign a specific value to it, but instead I only need it to be intialized to the same value each time the program runs - the same stuff as with a constructor initializer

Today, I stumbled over something in Perl I was not aware of: it "localizes" the variable that the elements of the list iterated over is assigned to. This, of course, is documented in the Perl documentation - however I failed to remember or read it. The following script demonstrates what I mean: use warnings; use strict; my $g = 99; foreach $g (1..5) { p($g); } sub p { my $l = shift; printf ("%2d %2d\n", $g, $l); } The script prints 99 1 99 2 99 3 99 4 99 5 because $g is "localized" to the foreach loop. As far as I can tell there is no difference if I had added my to $g in the foreach loop: