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问题 One parent launch two process A, B with python multiprocessing that should run in parallel. Share two lists with Multiprocessing.Manager list_1 list_2 A write to list_1 that is passed as parameter to A, inside A list_1 became list_W. A read from a list_2 that is passed as parameter to A, inside A list_2 became list_R B write to list_2 that is passed as parameter to B, inside B list_2 became list_W. B read from a list_1 that is passed as parameter to B, inside B list_1 became list_R if I call

问题 One parent launch two process A, B with python multiprocessing that should run in parallel. Share two lists with Multiprocessing.Manager list_1 list_2 A write to list_1 that is passed as parameter to A, inside A list_1 became list_W. A read from a list_2 that is passed as parameter to A, inside A list_2 became list_R B write to list_2 that is passed as parameter to B, inside B list_2 became list_W. B read from a list_1 that is passed as parameter to B, inside B list_1 became list_R if I call

问题 This question already has answers here : How do you split a list into evenly sized chunks? (63 answers) Closed 6 years ago . Is there an easy way to convert a 1D list into a 2D list with a given row length? Suppose I have a list like this: myList = [1, 2, 3, 4, 5, 6, 7, 8, 9] I want to convert the above list into a 3 x 3 table like below: myList = [[1,2,3],[4,5,6],[7,8,9]] I know I can accomplish this by creating a new 2D list called myList2 and inserting the element into MyList2 using 2

问题 I would like to subtract two consecutive element in a list with numbers in Scala. For example : I have this list : val sortedList = List(4,5,6) I would like to have an output list like diffList =(1, 1) where 5-4 = 1 and 6-5 = 1 . I tried the following code: var sortedList = List[Int]() var diffList = List[Int]() for (i <- 0 to (sortedList.length - 1) ;j <- i + 1 to sortedList.length - 1) { val diff = (sortedList(j) - sortedList(i)) diffList = diffList :+ diff } I have the following result for

问题 I would like to subtract two consecutive element in a list with numbers in Scala. For example : I have this list : val sortedList = List(4,5,6) I would like to have an output list like diffList =(1, 1) where 5-4 = 1 and 6-5 = 1 . I tried the following code: var sortedList = List[Int]() var diffList = List[Int]() for (i <- 0 to (sortedList.length - 1) ;j <- i + 1 to sortedList.length - 1) { val diff = (sortedList(j) - sortedList(i)) diffList = diffList :+ diff } I have the following result for

问题 I would like to subtract two consecutive element in a list with numbers in Scala. For example : I have this list : val sortedList = List(4,5,6) I would like to have an output list like diffList =(1, 1) where 5-4 = 1 and 6-5 = 1 . I tried the following code: var sortedList = List[Int]() var diffList = List[Int]() for (i <- 0 to (sortedList.length - 1) ;j <- i + 1 to sortedList.length - 1) { val diff = (sortedList(j) - sortedList(i)) diffList = diffList :+ diff } I have the following result for

问题 I have the following list of tuples: [('a', 1), ('a', 1), ('b', 1), ('c',1), ('a', 1), ('c', 1)] I would like to know if I can utilize python's reduce function to aggregate them and produce the following output : [('a', 3), ('b', 1), ('c', 2)] Or if there are other ways, I would like to know as well (loop is fine) 回答1: It seems difficult to achieve using reduce , because if both tuples that you "reduce" don't bear the same letter, you cannot compute the result. How to reduce ('a',1) and ('b'

问题 I have the following list of tuples: [('a', 1), ('a', 1), ('b', 1), ('c',1), ('a', 1), ('c', 1)] I would like to know if I can utilize python's reduce function to aggregate them and produce the following output : [('a', 3), ('b', 1), ('c', 2)] Or if there are other ways, I would like to know as well (loop is fine) 回答1: It seems difficult to achieve using reduce , because if both tuples that you "reduce" don't bear the same letter, you cannot compute the result. How to reduce ('a',1) and ('b'

问题 I have the following list of tuples: [('a', 1), ('a', 1), ('b', 1), ('c',1), ('a', 1), ('c', 1)] I would like to know if I can utilize python's reduce function to aggregate them and produce the following output : [('a', 3), ('b', 1), ('c', 2)] Or if there are other ways, I would like to know as well (loop is fine) 回答1: It seems difficult to achieve using reduce , because if both tuples that you "reduce" don't bear the same letter, you cannot compute the result. How to reduce ('a',1) and ('b'

问题 I have the following list of tuples: [('a', 1), ('a', 1), ('b', 1), ('c',1), ('a', 1), ('c', 1)] I would like to know if I can utilize python's reduce function to aggregate them and produce the following output : [('a', 3), ('b', 1), ('c', 2)] Or if there are other ways, I would like to know as well (loop is fine) 回答1: It seems difficult to achieve using reduce , because if both tuples that you "reduce" don't bear the same letter, you cannot compute the result. How to reduce ('a',1) and ('b'