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javafx drawing lines and text

徘徊边缘 提交于 2020-01-14 10:23:18
问题 I've got a problem with drawing lines in JavaFx. We're making an application simulating traffic - there are 16 streets, and every street has a different color dependent on traffic. There is a very simple picture: http://img546.imageshack.us/img546/9949/uliceu.jpg My first idea on how to do this was to draw streets as lines and simply change its colors. But I cant put a text on the line (I want a text with a street name). So I tried to put a line and a text on the StackPane. Then I added that

Moving the mouse along a diagonal line

冷暖自知 提交于 2020-01-14 06:52:27
问题 What kind of math algorithm could I use to calculate the path to move a mouse? I simply want to have this type of function: animateMouseDiag(int X, int Y){ //Move mouse 1 step towards goal, for loop most likely, from the current Mouse.Position Thread.Sleep(1); } For example, if I give it animateMouseDiag(100,300), it would move the mouse 100 to the right and 300 down, but diagonally, not right-then-down in an 'L'. Similarly, if I gave it (-50,-200) it would move it to those relative

「学习笔记——Python」Python输入和输出

孤者浪人 提交于 2020-01-14 05:53:08
7 Python 输入和输出 呈现程序输出结果的方式有很多,可以以可读方式打印出来,也可以写入文件以便将来使用。这一章,将会讲述这些可能的方式。 Table of Contents 1 输入格式 2 读写文件 1 输入格式 很多时候,我们不仅仅想只打印出结果,还对输出格式有所需求。有两种方式可以完成这一点,一是使用字符串的分割,合并,等 功能自己确定输出格式,你可以得到你想要的任何布局。二是使用 str.format() 函数。 这里有一个问题,如何把各种各样的值转化为字符串呢?Python 提供了 repr() 和 str() 来将任何值转化为字符串。 str() 函数会返回人类易读的格式, 而repr()则会返回供解释器读取的格式。但是,如果转化不成人类易读的方式,两个函数 的输出就会一样。 >>> print str('hello\n') hello >>> print repr('hello\n') 'hello\n' 下面是两种打印列表的方式: >>> for i in range(1,11): ... print repr(i).rjust(2), repr(i*i).rjust(3), ... print repr(i*i*i).rjust(4) ... 1 1 1 2 4 8 3 9 27 4 16 64 5 25 125 6 36 216 7 49 343 8

Subset Data for ggplot2 graph

試著忘記壹切 提交于 2020-01-14 02:07:29
问题 I am working with ggplot2 and have a question about how to subset data for plots. I have the following dataset (example) and need to create a line plot comparing Q1 data by year of Company A. x= 2015 Q1, 2016 Q1, 2017 Q1 y= Data for Company A Company Year Quarter Data A 2015 Q1 1 B 2015 Q1 2 C 2015 Q1 3 A 2015 Q2 4 B 2015 Q2 5 C 2015 Q2 6 A 2015 Q3 7 B 2015 Q3 8 C 2015 Q3 9 A 2016 Q1 10 B 2016 Q1 11 C 2016 Q1 12 A 2016 Q2 13 B 2016 Q2 14 C 2016 Q2 15 A 2016 Q3 17 B 2016 Q3 18 C 2016 Q3 19 For

Tensorflow神奇的Bug:ImportError: dlopen: cannot load any more object with static TLS

时光总嘲笑我的痴心妄想 提交于 2020-01-13 23:02:20
(转载请私信或微信联系:moses_1994,请不要原文搬运了连声招呼都不打) 1. 背景 基本环境:anaconda 3.0 + python 3.6 + tensorflow 1.5.0 2. 问题描述 在服务器上安装了tensorflow 1.5.0版本,但是在载入的时候,出现了一个神奇的Bug,详情如下: tensorflow的相关程序在 model.py 这个文件中,如果只在 main.py 中载入这个文件 from model import *,然后训练: python main.py ,那么程序不会报错。 但是如果再载入别的文件,例如 from feature import * ,那么不论这个载入语句在 from model import * 之前还是在其之后,运行 python main.py ,程序都会报错:ImportError: dlopen: cannot load any more object with static TLS 原始错误显示如下: Using TensorFlow backend. Traceback (most recent call last): File "/data00/home/labspeech_intern/anaconda3/envs/yuanbo_tf/lib/python3.6/site-packages

How to pixelate a set of lines into a matrix

此生再无相见时 提交于 2020-01-13 06:15:10
问题 It looks a very simple question. There are many lines available as their two endpoints. The question is how to discretize them into a matrix . Then the matrix can be used for image processing purposes. At the following figure example lines (yellow) and their corresponding pixelated demonstrations are shown. A piece of code in any language would be of great help and strongly recommended and of course is in advance appreciated. Note that performance and accuracy are very important factors. Also

Intersecting Lines POJ - 1269

人走茶凉 提交于 2020-01-13 01:56:38
Intersecting Lines 题目链接: https://vjudge.net/problem/POJ-1269 题目: 题意:判断给出的两条线是否相等平行还是相交,若相交求出交点坐标。。水题坑点就是提交G++WA,而提交C++A了,, 1 // 2 // Created by HJYL on 2020/1/13. 3 // 5 #include<iostream> 6 #include<cstring> 7 #include<cstdio> 8 #include<cmath> 9 #define eps 1e-6 10 using namespace std; 11 struct Point 12 { 13 double x,y; 14 }; 15 struct Line 16 { 17 double a,b,c,angle; 18 Point p1,p2; 19 Line(Point s,Point e) 20 { 21 a=s.y-e.y; 22 b=e.x-s.x; 23 c=s.x*e.y-e.x*s.y; 24 angle=atan2(e.y-s.y,e.x-s.x); 25 p1=s;p2=e; 26 } 27 Line(){} 28 }; 29 Point sub(Point a,Point b) 30 { 31 Point t; 32 t.x=a.x-b

【Bnis】 Linux内核驱动helloworld

雨燕双飞 提交于 2020-01-12 14:48:35
在桌面新建文件夹,并在文件夹里面新建hello.c , 内容如下: #include <linux/init.h> #include <linux/module.h> #include <linux/kernel.h> #include <linux/delay.h> MODULE_LICENSE("GPL"); static int __init hello_init(void) { printk("init: %s,line=%d\n", __func__, __LINE__); msleep(1000); printk("welcome to my linux kernel.\n" ); return 0; } static void __exit hello_exit(void) { printk("exit:%s,%d\n", __func__, __LINE__); } module_init(hello_init); module_exit(hello_exit); 另外再新建MakeFile文件,内容如下: $(warning KERNELRELEASE = $(KERNELRELEASE)) ifeq ($(KERNELRELEASE),) #内核的源码路径, ?= 条件赋值, uname -r 得到内核的版本号 KERNELDIR ?= /lib/modules

How to plot the outline of the outer edges on a Matplotlib line in Python?

三世轮回 提交于 2020-01-12 07:22:46
问题 I am trying to plot an outline ( linestyle=":" ) on the networkx edges. I can't seem to figure out how to do this to the matplotlib patch objects? Does anyone now how to manipulate these patch object to plot outlines to these "edges"? If this is not possible, does anyone know how to get the line data to use ax.plot(x,y,linestyle=":") separately to do this? import networkx as nx import numpy as np from collections import * # Graph data G = {'y1': OrderedDict([('y2', OrderedDict([('weight', 0

In Matlab, how to draw lines from the curve to specific xaxis position?

戏子无情 提交于 2020-01-11 12:03:25
问题 I have a spectral data (1000 variables on xaxis, and peak intensities as y) and a list of peaks of interest at various specific x locations (a matrix called Peak) which I obtained from a function I made. Here, I would like to draw a line from the maximum value of each peaks to the xaxis - or, eventually, place a vertical arrow above each peaks but I read it is quite troublesome, so just a vertical line is welcome. However, using the following code, I get "Error using line Value must be a