levenshtein-distance

问题 I am trying to implement in Eclipse Java Levenshtein distance on the following two strings: I took the idea from Wikipedia, but I don't know why my output is wrong, I need help to find my mistake/s. "kruskal" "causal" package il.ac.oranim.alg2016; public class OPT { public static void main(String[] args) { char[] t={'k','r','u','s','k','a','l'}; char[] s={'c','a','u','s','a','l'}; for (int i=0;i<=s.length;i++) { for (int j=0;j<=t.length;j++) System.out.print(LevenshteinDistance(s,t)[i][j]+" "

问题 I need to calculate orthographic similarity (edit/Levenshtein distance) among words in a given corpus. As Kirill suggested below, I tried to do the following: import csv, itertools, Levenshtein import numpy as np # import the list of words from csv file path = '/Users/my path' file = path + 'file.csv' with open(file, 'rb') as f: reader = csv.reader(f) wordlist = list(reader) wordlist = np.array(wordlist) #make it a np array wordlist2 = wordlist[:,0] #subset the first column of the imported

问题 I'm using a tutorial from Rosetta Code to calculate Levenshtein distance. It seems their code is in Swift2 so I get this error Binary operator '+' cannot be applied to operands of type '[Int]' and 'Repeated<String.CharacterView>' when doing this: var cur = [i + 2] + empty where let empty = repeatElement(s, count: 0) . How can I go about this? 回答1: There were a couple of changes to make. The construction of the Array empty. enumerate() is now enumerated() successor() doesn't exist anymore so I

问题 I'm using a tutorial from Rosetta Code to calculate Levenshtein distance. It seems their code is in Swift2 so I get this error Binary operator '+' cannot be applied to operands of type '[Int]' and 'Repeated<String.CharacterView>' when doing this: var cur = [i + 2] + empty where let empty = repeatElement(s, count: 0) . How can I go about this? 回答1: There were a couple of changes to make. The construction of the Array empty. enumerate() is now enumerated() successor() doesn't exist anymore so I

问题 So I am trying to devise a spin off of the Levenshtein algorithm, where I keep track of what transformations I did in the string(inserted a, or substitute a for b). Example: Basically, say I am computing the edit distance of "bbd" and "bcd" The edit distance will be 1 and the transformation will be "substitude b for c" Question: How would I approach this problem since the implementations i've seen do not concern themselves with knowing what kind of operation it was but only the total cost?

问题 I have a cell array dictionary which contains a lot of words (ca. 15000). I want to compute the function strdist (to calculate the Levenshtein distance) for all the couples of words. I tried in two ways, but they are both really slow. What can be a more efficient solution? Here is my code (dict_keys is my cell array of length m): 1) matrix = sparse(m,m); for i = 1:m-1; matrix(i,:) = cellfun( @(u) strdist(dict_keys{i},u), dict_keys ); end 2) matrix = sparse(m,m); for i = 1:m-1; for j = i+1:m

问题 Let's assume we have a database like: Actions_tbl: -------------------------------------------------------- id | Action_name | user_id| -------------------------------------------------------- 1 | John reads one book | 1 2 | reading the book by john | 1 3 | Joe is jumping over fire | 2 4 | reading another book | 2 5 | John reads the book in library | 1 6 | Joe read a book | 2 7 | read a book | 3 8 | jumping with no reason is Ronald's habit| 3 Users_tbl: ----------------------- user_id | user

问题 I was informed Levenshtein distance is symmetric. When I used google's diffMatchPatch tool which computes Levenshtein distance among other things, the results don't imply Levenshtein distance is symmetric. i.e Levenshtein(x1,x2) is not equal to Levenshtein(x2,x1). Is Levenshtein not symmetric or is there a problem with that particular implementation? Thanks. 回答1: Just looking at the basic algorithm it definitely is symmetric given the same cost for the operations - the number of additions,

问题 I am trying to find the Levenshtien distance between the columns of two different tables TableA and TableB. Basically I need to match ColumnA of TableA with all the elements of ColumnB in TableB and find the Levenshtien Distance I have created a Levenshtien Function as follows CREATE FUNCTION [Levenshtein] (@value1 [NVARCHAR](MAX), @value2 [NVARCHAR](MAX)) RETURNS [INT] AS EXTERNAL NAME [FastenshteinAssembly].[Fastenshtein.Levenshtein].[Distance] GO This is basically calling a Levenshtien dll

问题 Introduction - This question has been updated the 27th May 2018: I have 1 PHP multidimensional-array, containing 6 sub-arrays, each containing 20 sub-sub-arrays, which in turn, each contain 2 sub-sub-arrays, one being a string (header), the other being an unspecified number of keywords (keywords). I am looking to compare each of the 120 sub-sub-arrays to the 100 other sub-sub-arrays contained in the remainint 5 sub-arrays. So that sub-sub-array 1 in sub-array 1 is compared to sub-array 1 to